1z1-071全真問題集 & 1z1-071日本語版参考書

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Oracle Database SQL 認定 1z1-071 試験問題 (Q331-Q336):

質問 # 331
Which two are true about external tables that use the ORACLE _DATAPUMP access driver?

A. Creating an external table creates a directory object.
B. Creating an external table creates a dump file that can be used by an external table in the same or a different database.
C. Creating an external table creates a dump file that can be used only by an external table in the same database.
D. When creating an external table, data can be selected only from a table whose rows are stored in database blocks.
E. When creating an external table, data can be selected from another external table or from a table whose rows are stored in database blocks.

正解：E

解説：
External tables using the ORACLE_DATAPUMP access driver have specific characteristics:
C). Creating an external table using the ORACLE_DATAPUMP access driver allows you to select data from other tables, including another external table or a regular table whose rows are stored in database blocks.
A, B, D, and E are incorrect. Specifically:
* A is incorrect because creating an external table does not automatically create a directory object; the
* directory object must exist prior to or be created separately.
* B is incorrect as it limits the creation to tables stored in database blocks, which is not a restriction.
* D is incorrect because creating an external table does not create a dump file; it reads from an existing dump file created by Data Pump.
* E is also incorrect because the dump file is not created as part of the external table creation process.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "CREATE TABLE" for External Tables

質問 # 332
Examine the structure of the BOOKS_TRANSACTIONStable.

You want to update this table such that BOOK_IDis set to 'INVALID'for all rows where no MEMBER_ID has been entered.
Examine this partial SQL statement:

Which condition must be used in the WHEREclause to perform the required update?

A. MEMBER_ID IS NULL;
B. MEMBER_ID = '';
C. MEMBER_ID = "";
D. MEMBER_ID = NULL;

正解：A

質問 # 333
Which two statements are true regarding the COUNTfunction? (Choose two.)

A. COUNT(DISTINCT inv_amt)returns the number of rows excluding rows containing duplicates and NULLsin the INV_AMTcolumn.
B. COUNT(*)returns the number of rows including duplicate rows and rows containing NULLvalue in any column.
C. It can only be used for NUMBERdata types.
D. COUNT(inv_amt)returns the number of rows in a table including rows with NULLin the INV_AMTcolumn.
E. A SELECTstatement using the COUNTfunction with a DISTINCTkeyword cannot have a WHEREclause.

正解：A、B

解説：
Explanation/Reference:

質問 # 334
Examine the description of the MEMBERStable:

Examine the partial query:
SELECT city, last_name LNAME FROM members ...;
You want to display all cities that contain the string AN. The cities must be returned in ascending order, with the last names further sorted in descending order.
Which two clauses must you add to the query? (Choose two.)

A. ORDER BY last_name DESC, city ASC
B. WHERE city = `%AN%'
C. WHERE city LIKE `%AN%'
D. ORDER BY 1, LNAME DESC
E. ORDER BY 1, 2
F. WHERE city IN (`%AN%')

正解：C、D

質問 # 335
Examine the data in the COLORS table:

Examine the data in the BRICKS table:

Which two queries return all the rows from COLORS?

正解：B、C

解説：
In SQL, to return all rows from one table in a join regardless of whether they match rows in the other table, a LEFT JOIN is used when we want all rows from the left table, or a RIGHT JOIN when we want all rows from the right table. Here's an explanation for each query provided in the context of the COLORS and BRICKS tables:
A). This query uses a LEFT JOIN and will return all the rows from the COLORS table (c) because it is on the left side of the join. Additionally, it joins the BRICKS table (b) on the condition that the color_rgb_hex_value matches. The condition in the WHERE clause (b.brick_id > 0) will not exclude any COLORS rows because it only filters the rows from the right table (BRICKS) after the join.
B). This query uses a RIGHT JOIN, and while it does return all rows from the COLORS table, it doesn't place it on the left side of the join, which is not what is typically expected from a RIGHT JOIN to return all rows from the right side table.
C). This query is a plain JOIN (also known as an inner join), which only returns rows that have matching values in both tables, so it will not return all the rows from the COLORS table if there is no match in the BRICKS table.
D). This query uses a FULL JOIN, which returns all rows when there is a match in one of the tables. Hence, it will return all the rows from both the COLORS and BRICKS tables. While this does return all rows from the COLORS table, it also includes all rows from the BRICKS table, which may not be desired if the requirement was only to return all rows from COLORS.
E). This query is similar to option A and uses the USING clause to specify the join condition. The USING clause is used when both tables have a column with the same name and is meant to simplify the syntax.
However, in this case, the columns do not have the same name in both tables (RGB_HEX_VALUE in COLORS and COLOR_RGB_HEX_VALUE in BRICKS), so this query will not execute successfully.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Joins"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "LEFT OUTER JOIN"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "RIGHT OUTER JOIN"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "FULL OUTER JOIN"
Based on the explanations above, the correct answers that return all rows from the COLORS table are A and D: However, D includes all rows from BRICKS as well, which may not be the intended requirement if the question specifies only rows from COLORS should be returned. Thus, A is the most accurate answer to the question as it adheres to the standard expectation of a LEFT JOIN.

質問 # 336
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