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WGU Introduction-to-Cryptography Exam Syllabus Topics:

SectionObjectives
Topic 1: Hash Functions and Message Authentication- MAC and HMAC mechanisms
- Cryptographic hash functions (e.g., SHA family concepts)
Topic 2: Cryptographic Protocols and Applications- TLS/SSL conceptual overview
- Secure communication design principles
Topic 3: Key Management and PKI- Key exchange and lifecycle management
- Certificates, certificate authorities, and PKI structure
Topic 4: Foundations of Cryptography- Core concepts of confidentiality, integrity, authentication, non-repudiation
- Historical and modern cryptography principles
Topic 5: Symmetric Encryption- Block and stream ciphers
- AES and legacy algorithms (e.g., DES conceptually)
Topic 6: Asymmetric Encryption- Public key cryptography principles
- RSA and ECC fundamentals

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WGU Introduction to Cryptography HNO1 Sample Questions (Q51-Q56):

NEW QUESTION # 51
(A Linux user password is identified as follows:
$2a$08$AbCh0RCM8p8FGaYvRLI0H.Kng54gcnWCOQYIhas708UEZRQQjGBh4
Which hash algorithm should be used to salt this password?)

Answer: D

Explanation:
The string format $2a$08$... is a well-known identifier for the bcrypt password hashing scheme. In common password-hash notation, the prefix indicates the algorithm and parameters: "$2a$" denotes bcrypt (version 2a), and "08" indicates the cost factor (work factor) controlling how computationally expensive hashing is. bcrypt is designed specifically for password storage: it includes a built-in salt and is intentionally slow and adaptive, making brute-force and GPU attacks far more expensive than fast general-purpose hashes like MD5 or SHA-512. NTLM and MD5 are obsolete for secure password storage due to speed and known weaknesses. SHA-512, while cryptographically strong as a hash, is still too fast for password hashing unless used in a dedicated password-hashing construction (e.g., PBKDF2, scrypt, Argon2) with appropriate parameters and salts. Since the given hash clearly matches bcrypt's encoding, the correct algorithm is bcrypt, which incorporates salting and cost-based key stretching as part of its design.


NEW QUESTION # 52
(What is the RC4 encryption key size when utilizing WPA with Temporal Key Integrity Protocol (TKIP)?)

Answer: B

Explanation:
WPA with TKIP was designed as an interim improvement over WEP while still using the RC4 stream cipher for compatibility with legacy hardware. TKIP addresses WEP's major weaknesses by introducing per-packet key mixing, a message integrity mechanism ("Michael"), and replay protection. In TKIP, the encryption key used with RC4 is 128 bits. Practically, TKIP derives a per-packet RC4 key from a 128-bit temporal key (TK), the transmitter's MAC address, and a sequence counter (TKIP Sequence Counter, TSC) to avoid the simple IV reuse patterns that made WEP easy to break. Even with these improvements, TKIP has known weaknesses and is deprecated in favor of WPA2/WPA3 using AES-based CCMP/GCMP. But strictly for the question asked, TKIP's RC4 keying material is based on a 128-bit key size, not 40/56-bit legacy sizes and not 256-bit.


NEW QUESTION # 53
(How does Electronic Codebook (ECB) mode encryption function?)

Answer: B

Explanation:
ECB is the simplest block cipher mode: each plaintext block is encrypted independently using the same key and the block cipher primitive. There is no IV and no chaining, so identical plaintext blocks produce identical ciphertext blocks. This property leaks patterns and structure in the plaintext, which is why ECB is generally considered insecure for most real-world data beyond tiny, random-looking inputs. For example, images encrypted with ECB often reveal outlines because repeated pixel blocks map to repeated ciphertext blocks. Option A describes CTR mode, option C describes CBC mode, and option B resembles feedback-based modes. ECB's independence also means it can be parallelized, but the pattern leakage is a severe weakness. Modern practice prefers authenticated encryption modes (like GCM) or, at minimum, modes with IVs and chaining (like CBC with proper padding and MAC).
Therefore, the correct statement is that ECB encrypts each block with the same key and each block is independent of the others.


NEW QUESTION # 54
(How does a cryptographic policy contribute to incident response?)

Answer: D

Explanation:
A cryptographic policy defines how encryption, keys, certificates, and integrity mechanisms are used and managed across an organization. During incident response, that policy becomes a playbook for making safe, consistent decisions under pressure. It can specify how to rotate or revoke compromised keys, how to validate and reissue certificates, how to preserve evidence integrity with hashing, and how to securely communicate sensitive incident details (e.g., using approved encrypted channels). It can also define backup encryption requirements and key escrow or recovery procedures, enabling secure data recovery without exposing protected data. Policies typically outline roles and responsibilities (who can access keys, who can approve rekeying), logging requirements, and escalation steps-reducing confusion and preventing ad hoc crypto changes that might worsen exposure. The goal is not to limit encryption; it is to ensure cryptography is used correctly to contain and remediate incidents. Therefore, providing guidelines for secure recovery and communication is the correct contribution of cryptographic policy to incident response.


NEW QUESTION # 55
(Which symmetric encryption technique uses a 112-bit key size and a 64-bit block size?)

Answer: C

Explanation:
3DES (Triple DES) is a symmetric block cipher that retains DES's 64-bit block size while increasing effective security by applying DES multiple times. The common "two-key 3DES" variant uses two independent 56-bit DES keys (K1 and K2) in an Encrypt-Decrypt-Encrypt (EDE) sequence: Encrypt with K1, Decrypt with K2, then Encrypt again with K1. Because each DES key is 56 bits (ignoring parity bits), the total keying material is 112 bits. This matches the question's "112-bit key size and 64-bit block size." Plain DES uses only a 56-bit effective key and a 64-bit block size, so it does not match the 112-bit key size. AES has a 128-bit block size and key sizes of 128/192/256. IDEA uses a 64-bit block size but has a 128-bit key.
Therefore, the correct algorithm is 3DES. Although 3DES improved on DES, it is now considered legacy due to its small 64-bit block size (birthday-bound issues for large data volumes) and performance overhead compared to AES.


NEW QUESTION # 56
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