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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Plan and Manage Supply | 16% | - Supply planning and execution
|
| Topic 2: Conduct Sales and Operations Planning (S&OP) to Support Strategy | 9% | - S&OP process and purpose
|
| Topic 3: Plan and Manage Inventory | 19% | - Inventory principles and control
|
| Topic 4: Plan and Manage Demand | 9% | - Demand forecasting and planning
|
| Topic 5: Plan and Manage Distribution | 5% | - Distribution network and logistics
|
| Topic 6: Align the Supply Chain to Support the Business Strategy | 15% | - Supply chain environment and strategy alignment
|
| Topic 7: Manage Quality, Continuous Improvement, and Technology | 11% | - Quality management and improvement
|
| Topic 8: Plan, Manage, and Execute Detailed Schedules | 16% | - Scheduling techniques and execution
|
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NEW QUESTION # 432
Which of the following is the MOST effective practice for tracking organizational assets when removed from the premises?
Answer: B
NEW QUESTION # 433
Given the bill of material (BOM) information below and independent requirements of 10 pieces (pcs) per week of Component A and 20 pieces (pcs) per week of Component B, what is the weekly gross requirement of component F?
Answer: B
Explanation:
Given the bill of material (BOM) information, we can calculate the weekly gross requirement of component F by considering the independent requirements of Component A and B. For Component A, there is no direct requirement for Component F. For Component B, which has an independent requirement of 20 pcs per week, each requires 4 pcs of Component F according to its BOM. So, the total weekly gross requirement for Component F due to Component B is 204 = 80 pcs. Additionally, each piece of Component A requires 2 pieces of Component C according to its BOM and has an independent requirement of 10 pcs per week; hence requiring a total of 20 pieces of component C per week. Each piece of component C in turn requires 4 pieces of component F according to its BOM; hence requiring a total weekly gross requirement for component F due to component A is: 204 =80 pcs. Adding both gives us a total weekly gross requirement for component F as:
80+80=160pcs. References:
*CPIM Part 1 Learning System, Module 4: Inventory Management, Section 4.2: Inventory Management Policies and Objectives
*CPIM Part 2 Learning System, Module 1: Supply Chain Strategy, Section 1.3: Capacity Management
NEW QUESTION # 434
An example of an assignable cause of variation in process performance is:
Answer: A
Explanation:
An assignable cause of variation is a source of variation that is intermittent, not predictable, and identifiable. It is also called a special cause of variation. An assignable cause of variation affects the process performance in an unexpected and non-random way, and it can be eliminated or controlled by finding and correcting the specific cause1. An example of an assignable cause of variation in process performance is incorrect setup of a machine by the operator. This means that the operator did not follow the standard procedure or specification for setting up the machine, which may result in defective or nonconforming products or materials. This cause of variation can be identified and corrected by checking the setup instructions, training the operator, or implementing a setup verification system23. Reference: 1 Assignable Cause - isixsigma.com 4 2 Process Capability Analysis - an overview | ScienceDirect Topics 5 3 CPIM Exam Reference - Association for Supply Chain Management 1
NEW QUESTION # 435
A manufacturer has a forecasted annual demand of 1,000,000 units for a new product. They have to choose 1 of 4 new pieces of equipment to produce this product. Assume that revenue will be $10 per unit for all 4 options.
Which machine will maximize their profit if the manufacturer anticipates market demand will be steady for 3 years and there is no residual value for any of the equipment choices?
MachineFixed CostVariable Cost per UnitAnnual Capacity
AS100.000$6 00800,000 units
B$200,000$5 501.000,000 units
C$250,000$5 001,200,000 units
D$1 000.000$4 501 400.000 units
Answer: A
Explanation:
To maximize profit, the manufacturer should choose the machine that has the lowest total cost per unit of demand. The total cost per unit of demand is calculated by adding the fixed cost per unit of demand and the variable cost per unit. The fixed cost per unit of demand is obtained by dividing the fixed cost by the annual demand. The variable cost per unit is given in the table. The total cost per unit of demand for each machine is:
Machine A: 1,000,000100,000+6.00=6.10
Machine B: 1,000,000200,000+5.50=5.70
Machine C: 1,000,000250,000+5.00=5.25
Machine D: 1,000,0001,000,000+4.50=5.50
The lowest total cost per unit of demand is for Machine C, which is $5.25. Therefore, Machine C will maximize the profit for the manufacturer.
Reference:
Some possible references for this question are:
CPIM Part 1 Exam Content Manual, Version 8.0, Domain 3: Plan and Manage Supply, Section A: Plan and Manage Supply Chain Capacity, Topic 2: Capacity Planning Concepts, Subtopic b: Capacity planning methods, Page 30 CPIM Part 1 Learning System, Version 8.0, Module 3: Plan and Manage Supply, Section 3.2: Capacity Planning Concepts, Topic 3.2.2: Capacity Planning Methods, Subtopic 3.2.2.2: Cost-Volume Analysis, Pages 3-24 to 3-26 CPIM Part 1 Study Guide, Version 8.0, Module 3: Plan and Manage Supply, Section 3.2: Capacity Planning Concepts, Topic 3.2.2: Capacity Planning Methods, Subtopic 3.2.2.2: Cost-Volume Analysis, Pages 3-24 to 3-26
NEW QUESTION # 436
Which of the following provides for continuous improvement of the change control process?
Answer: B
NEW QUESTION # 437
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