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Oracle 1z1-071 (Oracle Database SQL) Exam is a certification exam offered by Oracle Corporation for individuals looking to demonstrate their proficiency in SQL and Oracle Database. 1z0-071 Exam is designed to test the candidate's knowledge and skills in SQL language, data modeling, database concepts, and the use of Oracle Database software. Passing 1z0-071 exam validates the candidate's ability to work with Oracle Database and SQL, making them a valuable asset to any organization that uses these technologies.

Oracle Database SQL Sample Questions (Q50-Q55):

NEW QUESTION # 50
Which three statements are correct regarding indexes? (Choose three.)

A. When a table is dropped, corresponding indexes are automatically dropped.
B. A non-deferrable PRIMARY KEY or UNIQUE KEY constraint in a table automatically attempts to create a unique index.
C. Indexes should be created on columns that are frequently referenced as part of any expression.
D. For each DML operation performed on a table, the corresponding indexes are automatically updated if required.

Answer: A,B,D

Explanation:
References:
http://viralpatel.net/blogs/understanding-primary-keypk-constraint-in-oracle/

NEW QUESTION # 51
Which task can be performed by using a single Data Manipulation Language (DML) statement?

A. Removing all data only from a single column on which a primary key constraint is defined.
B. Removing all data from a single column on which a unique constraint is defined.
C. Adding a column with a default value while inserting a row into a table.
D. Adding a column constraint while inserting a row into a table.

Answer: A

NEW QUESTION # 52
View the exhibit and examine the structure of the STOREStable.
STORES table
Name Null? Type
----------------- ----- -------------
STORE_ID NUMBER
NAME VARCHAR2(100)
ADDRESS VARCHAR2(200)
CITY VARCHAR2(100)
COUNTRY VARCHAR2(100)
START_DATE DATE
END_DATE DATE
PROPERTY_PRICE NUMBER
You want to display the NAME of the store along with the ADDRESS, START_DATE, PROPERTY_PRICE, and the projected property price, which is 115% of property price.
The stores displayed must have START_DATEin the range of 36 months starting from 01-Jan-2000 and above.
Which SQL statement would get the desired output?

A. SELECT name, address||','||city||','||country AS full_address,
start_date,
property_price, property_price*115/100
FROM stores
WHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR'))
<=36;
B. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address, start_date,
property_price, property_price*115/100
FROM stores
WHERE MONTHS_BETWEEN (start_date, '01-JAN-2000') <=36;
C. SELECT name, concat (address||','| |city| |', ', country) AS full_address, start_date,
property_price, property_price*115/100
FROM stores
WHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR'))
<=36;
D. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address, start_date,
property_price, property_price*115/100
FROM stores
WHERE TO_NUMBER(start_date-TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;

Answer: C

NEW QUESTION # 53
View the Exhibit and examine the structure of CUSTOMERS table.
Using the CUSTOMERS table, you need to generate a report that shows an increase in the credit limit by 15% for all customers. Customers whose credit limit has not been entered should have the message "Not Available" displayed.
Which SQL statement would produce the required result?

A. SELECT NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
B. SELECT TO_CHAR (NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
C. SELECT NVL(cust_credit_limit), 'Not Available') "NEW CREDIT"FROM customers;
D. SELECT NVL (TO CHAR(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;

Answer: D

NEW QUESTION # 54
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.

The PROD_ID column is the foreign key in the SALES table referencing the PRODUCTS table.
The CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the CUSTOMERS and TIMES tables, respectively.
Examine this command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true?

A. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
C. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
D. The NEW_SALES table would get created and all the NOT NULL constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.

Answer: D

NEW QUESTION # 55
......

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