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Snowflake SPS-C01 Exam Syllabus Topics:
| Section | Objectives |
|---|
| Topic 1: Data Engineering with Snowpark | - Pipeline development
- 1. Integration with Snowflake data pipelines
- 2. Batch processing workflows
|
| Topic 2: Testing, Debugging, and Deployment | - Production readiness
- 1. Deployment strategies
- 2. Debugging Snowpark applications
|
| Topic 3: User Defined Functions and Stored Procedures | - Extending Snowpark with custom logic
- 1. Python UDFs
- 2. Stored procedures in Snowpark
|
| Topic 4: Snowpark Fundamentals | - Snowpark architecture and concepts
- 1. Snowflake execution model overview
- 2. Snowpark APIs and supported languages
|
| Topic 5: Performance Optimization and Best Practices | - Efficient Snowpark execution
- 1. Pushdown optimization concepts
- 2. Resource utilization tuning
|
| Topic 6: DataFrame Operations and Data Processing | - Data transformation workflows
- 1. Joins and window functions
- 2. Filtering, selecting, and aggregations
|
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最新的 Snowflake Certification SPS-C01 免費考試真題 (Q149-Q154):
問題 #149
You are tasked with setting up secure authentication for your Snowpark application. You want to use key pair authentication for a service user. Which of the following steps are necessary and in the correct order?
- A. 1. Generate an RSA key pair (private and public key). 2. Store the public key securely on the client machine. 3. Provide the path to the public key file in the Snowpark session configuration. 4. Associate the private key with the Snowflake user using the SALTER USER command.
- B. 1. Generate an RSA key pair (private and public key). 2. Store the private key securely on the client machine. 3. Provide the path to the private key file in the
- C. 1. Generate an RSA key pair (private and public key). 2. Store the private key securely on the client machine. 3. Associate the private key with the Snowflake user using the SALTER USER command. 4. Provide the public key in the Snowpark session configuration.
- D. 1. Generate an RSA key pair (private and public key). 2. Store the private key in a database table. 3. Use database credentials in the Snowpark session configuration. 4. Associate the public key with the Snowflake user using the 'ALTER USER command.
- E. 1. Generate an RSA key pair (private and public key). 2. Store the private key securely on the client machine. 3. Provide the path to the private key file and passphrase (if any) in the Snowpark session configuration. 4. Associate the public key with the Snowflake user using the 'ALTER USER command.
答案:E
解題說明:
The correct steps for key pair authentication involve generating an RSA key pair, securely storing the private key on the client, providing the path to the private key (and passphrase, if used) in the Snowpark session configuration, and associating the public key with the Snowflake user using the 'ALTER USER command. Storing the private key in the database (option E) is a security risk. Options B and C have incorrect key associations.
問題 #150
Consider a DataFrame 'products df loaded from a SnoMlake table. It contains a 'features' column of type VARIANT, where each row contains a JSON object representing product features. Your task is to create a new DataFrame where each feature becomes a separate column. You need to dynamically extract these features without knowing the specific feature names in advance. Which of the following approaches could achieve this using Snowpark, and what considerations are important? Choose all that apply:
- A. Use a User-Defined Function (UDF) to parse the JSON and return a dictionary. Then, use a loop to iterate over the keys in the dictionary and create new columns based on these keys.
- B. It's not possible to dynamically extract feature names and create columns in Snowpark without knowing the schema in advance.
- C. Use the 'FLATTEN' function within a Snowpark DataFrame transformation. This allows you to transform the key-value pairs within the VARIANT column into separate rows, which can then be pivoted to create new columns.
- D. The function can be used in conjunction with a Snowpark SQL query to dynamically extract the json into separate columns.
- E. Use the function on the VARIANT column to get an array of feature names. Then, use a loop to iterate over this array and dynamically create new columns using bracket notation (e.g.,
答案:C,E
解題說明:
Options B and C are viable approaches. Option B: You can use the native function on the VARIANT column to extract the keys, then iterate over the returned array to dynamically create new columns. This relies on knowing the structure of the data at runtime, but doesn't require a UDE Option C: FLATTEN' offers a SQL-centric way to achieve this, which might be preferable for performance and maintainability. After flattening, you would typically pivot the data. Option A is possible with IJDFs, but might be less performant than using native functions or FLATTEN. Option D is incorrect; dynamic column creation is possible. While OBJECT_CONSTRUCT() can construct JSON objects, it's not directly helpful for dynamically extracting JSON properties into separate columns in this scenario (Option E).
問題 #151
A Snowpark application frequently experiences performance degradation during peak hours. You suspect that resource contention on the virtual warehouse is the primary cause. Which of the following actions, when implemented together, would BEST address this issue and ensure consistent performance?
- A. Implement workload management rules to prioritize Snowpark workloads during peak hours.
- B. Convert all Snowpark DataFrames to views to reduce computational overhead.
- C. Enable query acceleration for all Snowpark queries.
- D. Increase the AUTO_SUSPEND parameter of the virtual warehouse to a shorter duration to release resources more quickly.
- E. Create separate virtual warehouses for different Snowpark workloads and apply resource monitors to limit credit consumption.
答案:A,E
解題說明:
Workload management rules (A) allow you to prioritize Snowpark workloads, ensuring they receive preferential access to resources during peak hours. Creating separate virtual warehouses (C) isolates different workloads, preventing resource contention and allowing you to apply resource monitors for cost control. Shortening AUTO SUSPEND (B) may lead to frequent warehouse starts, increasing costs. Query acceleration (D) can help, but it might not be the most cost-effective solution for all queries. Converting DataFrames to views (E) doesn't directly address resource contention.
問題 #152
You are developing a secure UDF in Snowpark Python that needs to access sensitive data stored in an internal stage. The UDF should be accessible to users without granting them direct access to the stage. Which of the following security measures and code snippets are required to achieve this, assuming the stage is already created?
- A. Create a secure UDF using the ' VOLATILE keyword, allowing it to access secured data with current user's permissions.
- B. Create an external function and grant access to the API integration that provides the security context.
- C. Create a UDF and grant USAGE on the stage to the role that owns the UDF.
- D. Create a secure UDF and use a stored procedure owned by a role with access to the internal stage to retrieve data, passing the data to the UDF as an argument.
- E. Create a secure UDF and use the function to access stage credentials within the UDF's handler function.
答案:E
解題說明:
Secure UDFs are designed to execute with the privileges of the UDF owner, not the caller. allows secure access to stage credentials. Option B is incorrect because granting USAGE on the stage directly grants access to the data in the stage. Option C is a valid approach but unnecessary complex. Option D concerns external functions, not secure UDFs within Snowflake. Option E is incorrect because 'VOLATILE doesn't affect privilege handling.
問題 #153
You have a complex data pipeline implemented using Snowpark Tasks in a Directed Acyclic Graph (DAG). One of the tasks, , depends on the successful completion of two parent tasks, and 'task B'. You need to implement error handling such that if 'task_R fails, 'task_C' should not be executed, but should still complete its execution regardless of status. If 'task B' fails, 'task_C' should not be executed. How do you configure the task dependencies and error handling in Snowflake to achieve this behavior?
答案:A
解題說明:
Setting to execute 'AFTER task_A, task_B' establishes the dependency. Configuring on both 'task_R and 'task_B' ensures that if either task fails, it will suspend itself and prevent 'task_C' from running. This achieves the required behavior. Option A is incorrect because setting the parameter on 'task_C' will not prevent the execution of 'task_C' if either 'task_R or failed, but only suspend it after it tries to execute and fails. Option B is not correct because Snowflake's default behavior does not inherently skip 'task_C' unless specifically configured through dependencies. Option C is overly complex and doesn't accurately reflect intended behaviour.Option E is overly complex and doesn't accurately reflect intended behaviour. Option D will ensure only if both 'task_A' and runs successfully then runs else it will suspend the further execution.
問題 #154
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