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WGU Applied-Probability-and-Statistics Exam Syllabus Topics:

SectionObjectives
Topic 1: Regression and Modeling- Linear Relationships
  • 1. Slope and intercept interpretation
    • 2. Simple linear regression
      Topic 2: Statistical Inference- Estimation and Confidence Intervals
      • 1. Confidence interval interpretation
        • 2. Point estimates
          - Hypothesis Testing (Introductory Level)
          • 1. Null vs alternative hypothesis
            • 2. p-values interpretation
              Topic 3: Descriptive Statistics- Single Variable Data Analysis
              • 1. Measures of dispersion (variance, standard deviation, range)
                • 2. Data visualization (histograms, box plots)
                  • 3. Measures of central tendency (mean, median, mode)
                    - Two Variable Data Analysis
                    • 1. Outliers and relationships
                      • 2. Scatter plots interpretation
                        • 3. Correlation
                          Topic 4: Probability Theory- Fundamental Probability Concepts
                          • 1. Conditional probability
                            • 2. Basic probability rules
                              • 3. Independent vs dependent events
                                - Probability Distributions
                                • 1. Binomial distribution basics
                                  • 2. Normal distribution

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                                    WGU Applied Probability and Statistics (FZO1 C955) Sample Questions (Q155-Q160):

                                    NEW QUESTION # 155
                                    A hospital analyzes the recovery rates of patients undergoing two different treatments for a specific condition.
                                    Treatment X has an overall recovery rate of 80%, while Treatment Y has a recovery rate of 90%. However, when the data is divided by age groups, Treatment X has a higher recovery rate in each age group compared to Treatment Y.
                                    Is Simpson's paradox present in this study?

                                    Answer: C

                                    Explanation:
                                    Simpson's paradox occurs when an association observed in aggregated data reverses or conflicts with the association observed within relevant subgroups. In this case, the overall recovery rate appears better for Treatment Y, since Y has a 90% overall recovery rate compared with 80% for Treatment X. However, after the data are divided by age group, Treatment X has a higher recovery rate in every age group. That reversal between the overall comparison and the subgroup comparisons is precisely the defining structure of Simpson' s paradox. Age group functions as the lurking or confounding variable because different age distributions across treatment groups can distort the overall recovery rates. Option B states a true overall fact, but it ignores the contradiction created by the age-specific rates. Option C is too general; simple differences between treatments do not necessarily create Simpson's paradox. The key issue is inconsistency between aggregate and stratified results. References/topics from the Study Guide: two-variable data, confounding variables, conditional comparisons, Simpson's paradox.


                                    NEW QUESTION # 156
                                    A cafe recorded the total ice cream sales and the average maximum temperature of the day. The scatterplot shows the recorded data. The regression equation y = 13x # 598 estimates the total ice cream sales, y, of a day and the average maximum temperature, x, on that day.

                                    What does the slope represent in this context?

                                    Answer: A

                                    Explanation:
                                    In a linear regression equation of the form y = mx + b, the slope m gives the predicted change in the response variable y for a one-unit increase in the explanatory variable x. Here, y represents total ice cream sales and x represents average maximum temperature. The equation y = 13x # 598 has slope 13, so the model predicts that ice cream sales increase by about $13 for every 1°F increase in temperature. This is not the sales value at
                                    0°F; that would be the intercept, #598, which is generally not meaningful in this practical context. It is also not the predicted sales at 100°F, because that would require substituting x = 100 into the regression equation.
                                    The positive slope matches the upward trend in the scatterplot: higher temperatures are associated with higher ice cream sales. References/topics from the Study Guide: correlation and regression, slope interpretation, explanatory and response variables.


                                    NEW QUESTION # 157
                                    If y = #4, evaluate the following expression:
                                    (20 # y)/(5 + y)

                                    Answer: A

                                    Explanation:
                                    To evaluate the expression, substitute y = #4 everywhere y appears. The numerator is 20 # y, so replacing y with #4 gives 20 # (#4). Subtracting a negative is equivalent to addition, so the numerator becomes 24. The denominator is 5 + y, so substituting #4 gives 5 + (#4) = 1. The expression therefore becomes 24/1, which equals 24. The correct answer is D. The most common error in this problem is mishandling the negative sign in the numerator. If a student incorrectly computes 20 # (#4) as 16, the resulting value would not match the correct algebraic structure. Another important check is that the denominator is not zero; here it equals 1, so the expression is defined. References/topics from the Study Guide: substitution, evaluating algebraic expressions, integers, order of operations.


                                    NEW QUESTION # 158
                                    Ten teachers each had a jar of jelly beans. The jars had this number of jelly beans in each respective jar: 50,
                                    60, 80, 80, 100, 100, 100, 120, 120, and 140.
                                    What is the mean of these data?

                                    Answer: B

                                    Explanation:
                                    The mean is the arithmetic average of a quantitative data set. To calculate it, add all observed values and divide by the number of observations. The jelly bean counts are 50, 60, 80, 80, 100, 100, 100, 120, 120, and
                                    140. Their sum is 950. There are 10 jars, so the mean is 950 ÷ 10 = 95. This means the average number of jelly beans per jar is 95. Option A, 100, may seem plausible because 100 appears frequently and is near the center of the data, but frequency alone determines the mode, not the mean. Option C, 80, is one of the repeated values but not the average. Option B, 120, is too high because several observations fall well below
                                    120. The mean uses every value in the data set, including the low values 50 and 60 and the high value 140.
                                    References/topics from the Study Guide: mean, measures of center, quantitative data, arithmetic average.


                                    NEW QUESTION # 159
                                    Two dice rolled. Probability sum = 7?

                                    Answer: D

                                    Explanation:
                                    When two standard six-sided dice are rolled, there are 6 × 6 = 36 equally likely ordered outcomes. To find the probability that the sum is 7, count all ordered pairs that produce 7. These are (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1). There are 6 favorable outcomes. Therefore, the probability is 6/36, which simplifies to 1/6. Since the answer choices include both 6/36 and 1/6, the listed answer from the PDF uses the unsimplified equivalent form, 6/36. Option C, 5/36, omits one valid ordered pair. Option D, 1/12, is too small because it would represent only 3 favorable outcomes out of 36. This problem reinforces that dice outcomes are ordered when two dice are rolled, so (1,6) and (6,1) are counted separately. Study Guide references/topics: sample spaces, dice probability, favorable outcomes, theoretical probability.


                                    NEW QUESTION # 160
                                    ......

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