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| Section | Objectives |
|---|---|
| Topic 1: Statistical Inference | - Hypothesis Testing (Introductory Level)
|
| Topic 2: Probability Theory | - Fundamental Probability Concepts
|
| Topic 3: Regression and Modeling | - Linear Relationships
|
| Topic 4: Descriptive Statistics | - Single Variable Data Analysis
|
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NEW QUESTION # 33
Determine z in the equation:
1/(6z) = 2/9
Answer: D
Explanation:
The equation 1/(6z) = 2/9 is a proportion because it sets two fractions equal to each other. To solve it, use cross multiplication. Multiply the numerator of the first fraction by the denominator of the second fraction, and multiply the denominator of the first fraction by the numerator of the second fraction: 1 × 9 = 2 × 6z. This gives 9 = 12z. To isolate z, divide both sides by 12: z = 9/12. This fraction can also be simplified to 3/4, but the answer choices list the unsimplified equivalent form 9/12. The other options do not satisfy the original equation. For example, if z = 2/54, then 6z is very small and the left side becomes much larger than 2/9. If z =
12/9 or 18/2, the denominator becomes too large, making the left side too small. References/topics from the Study Guide: proportions, solving equations, cross multiplication, equivalent fractions.
NEW QUESTION # 34
Z-score = ?
Answer: C
Explanation:
A z-score standardizes a raw value by expressing its distance from the mean in standard deviation units. The formula is z = (x # #)/#, where x is the observed value, # is the mean, and # is the standard deviation. The numerator x # # measures how far the value is from the mean. Dividing by # converts that distance into standard deviation units. A positive z-score means the value is above the mean, a negative z-score means the value is below the mean, and z = 0 means the value equals the mean. Option B divides the raw value by the mean and does not measure standardized distance. Option C reverses the ratio incorrectly. Option D gives only the raw deviation and fails to standardize by the standard deviation. Z-scores are central in normal distribution calculations and comparisons across different scales. Study Guide references/topics: z-score, standardization, mean, standard deviation.
NEW QUESTION # 35
A school surveyed student participation in extracurricular activities. The survey found:
* The drama club had 50% of students participate.
* The science club had 30% of students participate.
* Both clubs had 15% of students participate.
What is the probability that a student participated in the drama club, given that they attended the science club?
Answer: B
Explanation:
This question asks for a conditional probability. The phrase "given that they attended the science club" means the science club group becomes the restricted reference group. The required probability is P(drama club | science club), which is calculated as P(drama and science) divided by P(science). The problem states that 15% of students participated in both clubs, so P(drama and science) = 0.15. It also states that 30% participated in the science club, so P(science) = 0.30. Therefore, P(drama | science) = 0.15 ÷ 0.30 = 0.50. This means that among students who attended the science club, half also participated in drama club. Option A gives the joint probability, not the conditional probability. Option B gives only the science club participation rate. Option C does not match the conditional probability calculation. References/topics from the Study Guide: conditional probability, joint probability, probability ratios, two-event probability.
NEW QUESTION # 36
The table shows the results of a survey of favorite movie genres.
What is the probability of selecting an action and then a comedy respondent if the selection is replaced?
Answer: A
Explanation:
Because the first selection is replaced, the two selections are independent. Replacement means the probability structure returns to its original state after the first respondent is selected. The probability of selecting an action respondent is 30%, or 0.30. The probability of selecting a comedy respondent is 35%, or 0.35. For independent sequential events, multiply the probabilities: 0.30 × 0.35 = 0.105. Converting 0.105 to a percentage gives 10.5%. Therefore, the probability of first selecting an action respondent and then selecting a comedy respondent is 10.5%. Option B does not result from multiplying the two relevant genre percentages.
Options C and D are far too large because they resemble combined or unrelated percentages rather than the probability of a two-step ordered selection. The word "and" signals multiplication, while "replacement" confirms independence between draws. References/topics from the Study Guide: independent events, replacement, multiplication rule, probability with percentages.
NEW QUESTION # 37
95% CI = 50 ± 2. SE = ?
Answer: C
Explanation:
A confidence interval has the structure estimate ± margin of error. The margin of error is calculated as critical value × standard error. For a 95% confidence interval using the normal approximation, the critical value is approximately 1.96, often rounded to 2 in introductory settings. The interval is given as 50 ± 2, so the margin of error is 2. Using the approximate 95% critical value of 2, we solve 2 = 2 × SE, giving SE = 1. More exactly, using 1.96 gives SE = 2/1.96 # 1.02, which rounds to 1. Option B confuses the margin of error with the standard error. Option C is too large, and option D would produce a margin of error near 1 under a 95% critical value. The correct standard error is approximately 1. Study Guide references/topics: confidence intervals, standard error, critical value, margin of error.
NEW QUESTION # 38
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