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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Aggregating Data Using Group Functions | 10% | - GROUP BY and HAVING clauses - Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions |
| Topic 2: Using SET Operators | - Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators | |
| Topic 3: Manipulating Data and Managing Transactions | - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - Multi-table inserts - INSERT, UPDATE, DELETE, MERGE statements | |
| Topic 4: Managing Indexes, Synonyms and Sequences | - Create and use sequences - Create and maintain indexes - Create and use synonyms | |
| Topic 5: Using Subqueries to Solve Queries | - Single-row and multi-row subqueries - Correlated subqueries for update/delete | |
| Topic 6: Controlling User Access | - Roles, granting and revoking privileges - System and object privileges | |
| Topic 7: Restricting and Sorting Data | 15% | - WHERE clause and filtering conditions - ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands - Operator precedence |
| Topic 8: Conversion Functions and Conditional Expressions | 10% | - TO_CHAR, TO_NUMBER, TO_DATE functions - Implicit and explicit data type conversion - NVL, NULLIF, COALESCE and CASE expressions |
| Topic 9: Retrieving Data Using SQL SELECT Statement | 20% | - SELECT statement syntax and usage - Arithmetic operations and NULL handling - Column aliases, concatenation, literals and DISTINCT |
| Topic 10: Managing Views | - Updatable and read-only views - Create, modify and drop views | |
| Topic 11: Managing Tables and Constraints | - Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables - Temporary and external tables | |
| Topic 12: Working with Time Zones and Date/Time Data | - TIMESTAMP, INTERVAL data types - Time zone conversion functions | |
| Topic 13: Displaying Data from Multiple Tables | 15% | - Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins |
| Topic 14: Using Data Dictionary Views | - Retrieve metadata and object information | |
| Topic 15: Relational Database Concepts | 10% | - ERD and SQL statement mapping - Theoretical and physical aspects of relational databases - Relationship between database and SQL |
| Topic 16: Using Single-Row Functions to Customize Output | 20% | - Character, number, and date functions - Nested functions usage |
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NEW QUESTION # 420
Which three statements are true about Oracle synonyms?
Answer: B,D,E
Explanation:
B . True. In Oracle, synonyms can be created for sequences, allowing them to be referenced with an alternative name. This can be particularly useful when sequences are accessed across different schemas.
C . True. Oracle provides the ability to create public synonyms which are available to all users in the database. A public synonym is accessible to any user that has the necessary privileges on the underlying object.
D . True. A synonym can be created by a user to refer to an object owned by another user, assuming that the creator of the synonym has the necessary privileges to access the object owned by the other user.
NEW QUESTION # 421
Examine the description of the PRODUCTS table:
Which two statements execute without errors?
Answer: B,D
NEW QUESTION # 422
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)
In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table.
You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:
SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p ______________ sales s
ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?
Answer: B,D
NEW QUESTION # 423
Examine these two queries and their output:
SELECT deptno, dname FROM dept;
SELECT ename, job, deptno FROM emp ORDER BY deptno;
Now examine this query:
SELECT ename, dname
FROM emp CROSS JOIN dept WHERE job = 'MANAGER'
AND dept.deptno IN (10, 20) ;
Answer: B
Explanation:
In a CROSS JOIN (also known as a Cartesian join), each row from the first table (emp) is joined to every row of the second table (dept). When we apply the filter for job = 'MANAGER' and dept.deptno IN (10, 20), we are restricting the results to managers in departments 10 and 20.
From the given data:
There are 2 managers in department 10 (CLARK and KING).
There is 1 manager in department 20 (JONES).
With a cross join, each of these emp records will join with each dept record where deptno is 10 or 20. Since there are two departments (10 and 20) in the dept table, each employee will match with two departments.
Therefore, the result set will be:
CLARK with accounting (dept 10) and research (dept 20)
KING with accounting (dept 10) and research (dept 20)
JONES with accounting (dept 10) and research (dept 20)
That gives us a total of 6 rows, which means the correct answer is B: 6.
NEW QUESTION # 424
View the Exhibit and examine the description of the EMPLOYEES table.
Evaluate the following SQL statement:
SELECT first_name, employee_id, NEXT_DAY(ADD_MONTHS(hire_date, 6), 1) "Review" FROM employees;
The query was written to retrieve the FIRST_NAME, EMPLOYEE_ID, and review date for employees. The review date is the firsts Monday after the completion of six months of the hiring. The NLS_TERRITORY parameter is set to AMERICA in the session.
Which statement is true regarding this query?
Answer: A
NEW QUESTION # 425
......
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