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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Data Handling and Logic | 15% | - Basic data processing
|
| Topic 2: App Design and Best Practices | 15% | - Code organization
|
| Topic 3: Development Environment | 15% | - Debugging techniques
|
| Topic 4: Swift Programming Fundamentals | 30% | - Structures and classes
|
| Topic 5: SwiftUI Basics | 25% | - Views and controls
|
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NEW QUESTION # 35
Review the code.
You need to add the word " Great! " to the Capsule shape.
Complete the code by typing in the boxes.
Answer:
Explanation:
overlay, Text
Explanation:
This question belongs to View Building with SwiftUI , particularly the domain involving positioning and/or laying out a single SwiftUI view with standard views and modifiers . To place text on top of a shape such as a Capsule, SwiftUI uses the overlay modifier. Apple documents overlay as a view modifier that layers one view in front of another, which is exactly what is needed here: the text should appear on top of the blue capsule rather than beside or below it. The second blank must therefore be Text , because SwiftUI uses a Text view to display string content like " Great! " .
The completed code is:
struct ContentView: View {
var body: some View {
Capsule()
.fill(.blue)
.frame(width: 200.0, height: 100.0)
.overlay(
Text( " Great! " )
.font(.largeTitle)
)
}
}
This works because Capsule() creates the shape, .fill(.blue) gives it the blue color, .frame(width:height:) sets its size, and .overlay(...) places the Text( " Great! " ) directly above that shape. This is a standard SwiftUI composition pattern: build a base view, then apply modifiers to style it and layer additional content. In App Development with Swift objectives, this aligns with understanding standard views, modifiers, and layout techniques in SwiftUI.
NEW QUESTION # 36
Review the code snippet.
What will print after the final line of code is executed?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objective on variable scope and shadowing .
The code first declares:
let even = 2
This creates a constant named even in the outer scope with the value 2.
Inside the for loop, the code declares another constant with the same name:
let even = num * 2
This inner even exists only inside the loop body. It shadows the outer even, which means that within the loop, the name even refers to the loop's local constant, not the original one. However, that inner constant goes out of scope at the end of each loop iteration.
After the loop finishes, the inner even no longer exists. So when the final line runs:
print(even)
Swift uses the original outer constant, which is still 2.
So the output is:
2
This question tests two important Swift concepts:
* Scope : where a variable or constant can be accessed
* Shadowing : when a local declaration temporarily hides another declaration with the same name Therefore, the correct answer is 2 .
NEW QUESTION # 37
When you press ' Show Button ' on your app. a modal View appears.
Complete the code by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
Answer:
Explanation:
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .
To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:
sheet(isPresented: $showInfo) {
// modal content
}
So the first blank must be .sheet , and the second blank must be (isPresented: .
The logic works like this:
* @State stores the local Boolean that controls presentation.
* Pressing the button calls showInfo.toggle(), changing the value from false to true.
* When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.
* When the modal is dismissed, SwiftUI updates the Boolean back as needed.
There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:
@State var showInfo = false
Therefore, the correct dropdown selections are:
sheet
(isPresented:
NEW QUESTION # 38
Review the code.
var capitalCities = [ " USA " : " Washington D.C. " , " Spain " : " Madrid " , " Peru " : " Lima " ] Which two statements add the capital city of " Italy " to the dictionary? (Choose 2.)
Answer: D,E
Explanation:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question falls under Swift Programming Language , specifically the domain for managing data using collection types , with emphasis on dictionaries . In Swift, a dictionary stores data as key-value pairs , so in this example the country name is the key and the capital city is the value. To add a new entry, Swift supports two standard approaches. The first is subscript assignment , which is shown in option C : capitalCities[ " Italy " ] = " Rome " . Apple's documentation explains that you can add a key-value pair to a dictionary by assigning a value for a new key through the dictionary subscript.
The second correct approach is option E : capitalCities.updateValue( " Rome " , forKey: " Italy " ). Apple documents that updateValue(_:forKey:) updates the value for an existing key, or adds a new key-value pair if the key does not already exist . That makes it equally valid for inserting " Italy " : " Rome " into the dictionary.
The incorrect options fail for different reasons. A reverses the key and value, making " Rome " the key and " Italy " the value. B is wrong because append is used with arrays, not dictionaries. D is not the standard valid insertion syntax for Swift dictionaries in this context; Swift's documented mutation approaches here are subscript assignment and updateValue. Therefore, the two correct answers are C and E .
NEW QUESTION # 39
Drag the views on the left to the correct locations m the code on the fight to match the shown canvas.
You may use each View once, more than once, or not at all.
Answer:
Explanation:
Explanation:
* RedCircleView()
* GreenTriangleView()
* BlueSquareView()
* BlueSquareView()
* GreenTriangleView()
This question belongs to View Building with SwiftUI , specifically arranging views with HStack , VStack , and ZStack . In SwiftUI, an HStack lays views out horizontally, a VStack lays them out vertically, and a ZStack overlays views front-to-back. Apple's stack layout guidance describes these three containers exactly this way.
To match the canvas, the main HStack must show three items from left to right: a red circle , a green triangle
, and then a right-side vertical group. That means the first two blanks inside HStack are RedCircleView() and GreenTriangleView(). On the right side, the VStack shows a blue square on top, so the next blank is BlueSquareView(). Under that, the lower-right shape is made by layering a green triangle on top of a blue square , which means the ZStack must contain BlueSquareView() first as the background and GreenTriangleView() second as the foreground. SwiftUI's documentation notes that ZStack aligns and overlays its children in depth order, which is why the square goes before the triangle.
So the correct placement order is:
HStack {
RedCircleView()
GreenTriangleView()
VStack {
BlueSquareView()
ZStack {
BlueSquareView()
GreenTriangleView()
}
}
}
That arrangement reproduces the exact layout shown in the canvas.
NEW QUESTION # 40
......
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