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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Data Structures | 20% | - Arrays, linked lists, stacks, queues - Data storage and retrieval principles - Trees, graphs, hash tables - Primitive and composite data types |
| Topic 2: Algorithms & Complexity | 25% | - Algorithm design and analysis - Sorting and searching algorithms - Recursion and iterative structures - Big O notation, time and space complexity |
| Topic 3: Computer Architecture & Organization | 15% | - Memory hierarchy and performance - CPU, memory, I/O systems - Instruction sets and execution cycles - Von Neumann architecture |
| Topic 4: Software Engineering & Programming Basics | 15% | - Programming paradigms - Testing and debugging fundamentals - Basic syntax and control structures - Software development lifecycle |
| Topic 5: Discrete Mathematics & Logic | 25% | - Propositional and predicate logic - Proof techniques and mathematical induction - Set theory, relations, functions - Boolean algebra and digital logic |
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NEW QUESTION # 60
Given the following code, what is the expected output?
Answer: B
Explanation:
In NumPy, a 2D array can be visualized as a table of rows and columns. When you write np_2d[0], you are usingzero-based indexingto select thefirst rowof that 2D array. This is a standard convention in Python and many other programming languages: index 0 refers to the first element, index 1 to the second, and so on.
Therefore, np_2d[0] returns all the elements in row 0.
With a typical construction such as np_2d = np.array([[1, 2, 3, 4], [10, 20, 30, 40]]), the first row is [1, 2, 3,
4], so printing np_2d[0] displays that row. NumPy returns the row as a 1D NumPy array, and when printed it often appears in bracket form like [1 2 3 4] (spaces rather than commas are common in NumPy's display).
Conceptually, however, the contents are exactly the first row values, matching option C.
Option A and D show the second row (index 1), not the first. Option B incorrectly suggests a column extraction rather than a row selection.
NEW QUESTION # 61
Which protocol provides encryption while email messages are in transit?
Answer: D
Explanation:
"Encryption in transit" means protecting data while it moves across a network so that eavesdroppers cannot read or modify it. For email systems, this protection is most commonly provided byTLS (Transport Layer Security). TLS is a cryptographic protocol that can wrap application protocols (including mail protocols) to provide confidentiality, integrity, and server (and sometimes client) authentication. In practice, TLS is used to secure connections such as SMTP submission (often with STARTTLS or implicit TLS), IMAP over TLS, and POP3 over TLS. Textbooks present TLS as the standard successor to SSL and the foundation of secure communication on the modern Internet.
The other options are not correct in this context. FTP is a file transfer protocol and is traditionally unencrypted unless paired with additional security mechanisms (e.g., FTPS, which uses TLS, or SFTP, which uses SSH). HTTP is a web protocol; it becomes encrypted only when used as HTTPS, which again relies on TLS underneath. IMAP is an email retrieval protocol, butIMAP itself is not the encryption protocol- IMAP can be run over TLS (IMAPS) to become secure.
Therefore, the protocol that provides encryption while email messages (or email protocol traffic) are in transit is TLS.
NEW QUESTION # 62
Which method converts the default smallest-to-largest index order of a list to instead be the opposite?
Answer: D
Explanation:
Python lists maintain an order, and sometimes you need to reverse that order so the last element becomes first and the first becomes last. The standard list method for reversing the elementsin placeis reverse(). For example, if nums = [1, 2, 3, 4], then nums.reverse() mutates the list so it becomes [4, 3, 2, 1]. This is a built-in operation taught in introductory programming texts because it is efficient and conceptually simple: it does not create a new list unless you explicitly copy the data.
It is important to distinguish reversing from sorting. Reversing changes the sequence order as-is, while sorting rearranges elements according to comparisons. The question refers to converting the index order to the opposite, which is reversing. If you wanted descendingsortedorder, you would typically use sort (reverse=True) or sorted(nums, reverse=True). But the direct method that reverses the list's order is reverse().
The other options are not standard Python list methods. sortDescending(), flip(), and invert() are not part of Python's built-in list API. Textbooks emphasize learning the correct method names because Python's standard library provides a consistent, widely used interface across programs. Thus, reverse() is the correct answer for reversing the index order of a list.
NEW QUESTION # 63
How is a NumPy array named data with 6 elements reshaped into a 2x3 array?
Answer: A
Explanation:
Reshaping is the operation of changing the "view" of an array so that the same elements are arranged with new dimensions. In NumPy, reshaping is possible when the total number of elements stays the same. A 2x3 array contains 6 elements, so a 1D array data of length 6 can be reshaped into shape (2, 3) without adding or removing values. Textbooks stress this invariant: the product of the dimensions must equal the original size.
NumPy provides two standard reshaping interfaces: the function np.reshape(data, (2, 3)) and the method data.
reshape(2, 3) (or data.reshape((2, 3))). Option A is correct because it uses the official NumPy function with the proper arguments: the original array and the target shape. The shape is passed as a tuple describing rows and columns.
Option B is incorrect because np_reshape is not the correct NumPy function name, and it references an unrelated identifier list. Option C is incorrect because NumPy arrays do not provide a set_shape method like that. Option D is not valid NumPy syntax for reshaping.
Reshaping is fundamental in data analysis and machine learning: it converts flat vectors into matrices, prepares batches of samples, and aligns dimensions for matrix multiplication and broadcasting.
NEW QUESTION # 64
Which type of data structure is the only focus of a binary search?
Answer: D
Explanation:
Binary search is designed for searching in asorted (ordered) sequence. Its efficiency comes from repeatedly comparing the target to the middle element and discarding half of the remaining search space. This halving logic only works when the data is ordered, because the algorithm relies on the guarantee that all elements on one side of the midpoint are smaller (or larger) than the midpoint. In textbooks, this requirement is stated explicitly: binary search assumes the collection is sorted according to the same ordering used for comparisons.
An "ordered list" is therefore the correct focus among the options. Binary search can be implemented on arrays or other random-access structures where you can quickly access the middle element by index. While you can conceptually perform binary search on a linked list, it becomes inefficient because finding the middle requires linear traversal, losing the O(log n) advantage. Stacks and queues are not appropriate because they restrict access to ends only (LIFO for stacks, FIFO for queues), preventing direct access to the midpoint and making the binary search strategy infeasible.
Thus, the central requirement for binary search is a sorted/ordered sequence, typically supporting efficient indexing, which is why the correct choice is an ordered list.
NEW QUESTION # 65
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