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| Section | Objectives |
|---|---|
| Topic 1: Enterprise Firewall | - Security Fabric integration - High availability - Routing and advanced networking - Centralized management and analytics - Troubleshooting - VPN technologies - Authentication and identity - Advanced firewall deployment |
| Topic 2: SD-WAN | - Performance SLA - SD-WAN architecture - Overlay VPN - Deployment and troubleshooting - Application steering - SD-WAN routing |
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NEW QUESTION # 53
Refer to the exhibit, which shows a partial output of the real-time LDAP debug.
What two actions can the administrator take to resolve this issue? (Choose two.)
Answer: C,D
NEW QUESTION # 54
Refer to the exhibit.
Partial output of the get vpn ipsec tunnel details command is shown. Based on the output, which two statements are correct? (Choose two.)
Answer: C,D
Explanation:
The correct answers are C and D .
The study guide's get vpn ipsec tunnel details example shows:
* replay: enabled
* inbound and outbound sections with separate SPIs
* NPU acceleration: encryption(outbound) decryption(inbound) and it labels these as "Phase 2 SAs for each direction" and "Hardware acceleration" This directly proves D. Anti-replay is enabled , because the output explicitly says replay: enabled For the NPU status, the study guide explains the exact npu_flag meanings:
* npu_flag=00 = both IPsec SAs loaded to the kernel
* npu_flag=01 = outbound IPsec SA copied to NPU
* npu_flag=02 = inbound IPsec SA copied to NPU
* npu_flag=03 = both outbound and inbound IPsec SAs copied to NPU
Because the exhibit shows hardware acceleration in both directions - encryption(outbound) and decryption(inbound) - the matching npu_flag is 03 , not 02. That makes C correct and A incorrect.
Why B is wrong:
The same study guide output labels the tunnel as having Phase 2 SAs for each direction , so different inbound and outbound SPIs are normal for the two SAs. Also, the FortiOS administration guide explains that auto-negotiate controls whether phase 2 SA negotiation is initiated automatically, not whether inbound and outbound SPIs are different: "By default the phase 2 security association (SA) is not negotiated until a peer attempts to send data... Auto-negotiate initiates the phase 2 SA negotiation automatically..." So the verified answers are: C, D .
NEW QUESTION # 55
Refer to the exhibit, which shows the output of diagnose sys session list.
If the HA ID for the primary device is 0, what happens if the primary fails and the secondary becomes the primary?
Answer: C
Explanation:
The decisive session-state flag is synced. Fortinet defines this flag as indicating that the session has been synchronized to the other HA members. The session was created on HA member 0, and a synchronized copy is available to the secondary device.
The FortiOS 7.6 Administrator Study Guide states: "When you enable session synchronization, the new primary can resume communication for sessions after a failover event." It further explains that session pickup allows existing sessions to continue through the newly elected primary with minimal or no interruption.
Therefore, the established TCP session remains usable, and the client does not need to establish a new connection.
The may_dirty flag does not mean that the session is currently dirty. It identifies an allowed session that can be marked dirty later if a firewall-policy, routing, or related configuration change requires re-evaluation. The output does not contain the separate dirty flag. Additionally, app_ntf represents block-notification handling; it does not prove that application control is inspecting the session. The fields app_list=0 and app=0 reinforce this.
The allow_err values are session statistics and do not cause session deletion. Although act=snat and act=dnat confirm NAT, the translation tuples are part of the synchronized session state and do not independently require re-evaluation after FGCP failover.
References: High Availability - Cluster Synchronization and HA Failover, pages 456 and 463; Fortinet: HA session failover; Fortinet: Session-table information.
NEW QUESTION # 56
Refer to the exhibit.
The output from a collector agent log is shown. The collector agent is showing the status of a workstation as Not Verified. What are two common causes for this message? (Choose two.)
Answer: C,D
Explanation:
The correct answers are B and C.
The study guide has a section titled "Not Verified Status on the Collector Agent" and states:
"The collector agent cannot verify if the user is still logged in" and lists these common causes:
"A firewall is blocking traffic to port 139 and 445"
"The workstation remote registry service is not running"
The guide also explains the verification method:
"For WMI polling mode, the collector agent checks the WMI service. For all the other modes, the collector agent checks the HKEY_USERS hive through remote registry services." If the workstation does not respond to these checks, the status can become not verified An additional requirements slide in the same study guide confirms:
"TCP ports 139 and 445 must be open between the collector agent and all workstations"
"Remote registry service must be up and running on each workstation"
Why the other options are wrong:
A is wrong because the study guide mentions a workstation coming out of hibernate mode under a different problem: "No Internet After IP Address Change", not as a common cause of Not Verified status D is wrong because DNS resolution issues are also discussed under the IP address change scenario, where the collector agent uses DNS to resolve the workstation name after an IP change. That is separate from the Not Verified causes listed for this log message So the verified answers are: B, C.
NEW QUESTION # 57
Refer to the exhibit, which shows the partial output of FortiOS kernel slabs.
Which statement is true?
Answer: C
Explanation:
The study guide states:
"The kernel memory slabs are collections of objects with a common purpose. The kernel uses them to store information in memory." It also gives the exact calculation rule:
"Total slab size = available objects x object size"
From the exhibit:
tcp_session 3 5 1500 ...
So:
available objects = 5
object size = 1500
Therefore:
Total slab size = 5 ร 1500 = 7500 kB
That makes D correct, and it is associated with the kernel, not user space.
Why the other options are wrong:
A is wrong because sctp_session 0 0 1600 ... gives 0 ร 1600 = 0, but slabs are associated with the kernel, not user space.
B is wrong because ip_session 1 3 1200 ... gives 3 ร 1200 = 3600, but again slabs are kernel memory, not user space.
C is wrong because ip6_session 0 0 1300 ... gives 0 ร 1300 = 0, not 1300.
NEW QUESTION # 58
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