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Oracle Database SQL Sample Questions (Q309-Q314):
NEW QUESTION # 309
Which two are true about external tables that use the ORACLE_DATAPUMP access driver?
(Choose two.)
- A. Creating an external table creates a dump file that can be used only by an external table in the same database.
- B. Creating an external table creates a dump file that can be used by an external table in the same or a different database.
- C. Creating an external table creates a directory object.
- D. When creating an external table, data can be selected from another external table or from a table whose rows are stored in database blocks.
- E. When creating an external table, data can be selected only from a table whose rows are stored in database blocks.
Answer: B,D
NEW QUESTION # 310
Examine the description of the EMPLOYEES table:

Which statement will fail?
- A. SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90 GROUP BY department_id
HAVING COUNT(*) >= 3; - B. SELECT department_id, COUNT (*)
FROM employees
HAVING department_ id <> 90 AND COUNT(*) >= 3
GROUP BY department_id; - C. SELECT department_id, COUNT (*)
FROM employees
WHERE department_ id <> 90 AND COUNT(*) >= 3
GROUP BY department_id; - D. SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90 HAVING COUNT(*) >= 3
GROUP BY department_id;
Answer: C
NEW QUESTION # 311
Examine the description of the CUSTOMERS table:

You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?
- A. SELECT * FROM customers WHERE city ='%D_';
- B. SELECT * FROM customers WHERE city LIKE'D %';
- C. SELECT * FROM customers WHERE city LIKE'D_';
- D. SELECT * FROM customers WHERE city ='D_%';
Answer: D
Explanation:
The LIKE operator is used in SQL to search for a specified pattern in a column. To find all customers residing in cities starting with 'D' followed by at least two characters, you need to use the LIKE operator with the appropriate wildcard pattern:
* A. SELECT * FROM customers WHERE city LIKE 'D_%'; The underscore () wildcard character in SQL represents a single character. The percent (%) wildcard character represents zero or more characters. So 'D%' will match any city starting with 'D' followed by at least one character (as there is one underscore).
References:
* Oracle Database SQL Language Reference 12c, specifically the section on pattern matching with the
* LIKE condition.
NEW QUESTION # 312
Which two statements are true about the COUNT function?
- A. It can only be used for NUMBER data types.
- B. A SELECT statement using the COUNT function with a DISTINCT keyword cannot have a WHERE clause.
- C. COUNT(inv_amt) returns the number of rows in a table including rows with NULL in the INV_AMT column.
- D. COUNT (DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULLs in the INV_AMT column
- E. COUNT(*) returns the number of rows in a table including duplicate rows and rows containing NULLs in any column.
Answer: D,E
NEW QUESTION # 313
Examine the data in the PRODUCTS table:

Examine these queries:
1. SELECT prod name, prod list
FROM products
WHERE prod 1ist NOT IN(10,20) AND category _id=1;
2. SELECT prod name, | prod _ list
FROM products
WHERE prod list < > ANY (10,20) AND category _id= 1;
SELECT prod name, prod _ list
FROM products
WHERE prod_ list <> ALL (10, 20) AND category _ id= 1;
Which queries generate the same output?
- A. 1 and 3
- B. 1 and 2
- C. 2 and 3
- D. 1, 2 and 3
Answer: A
Explanation:
Based on the given PRODUCTS table and the SQL queries provided:
Query 1: Excludes rows where prod_list is 10 or 20 and category_id is 1.
Query 2: Includes rows where prod_list is neither 10 nor 20 and category_id is 1.
Query 3: Excludes rows where prod_list is both 10 and 20 (which is not possible for a single value) and category_id is 1.
The correct answer is A, queries 1 and 3 will produce the same result. Both queries exclude rows where prod_list is 10 or 20 and include only rows from category_id 1. The NOT IN operator excludes the values within the list, and <> ALL operator ensures that prod_list is not equal to any of the values in the list, which effectively excludes the same set of rows.
Query 2, using the <> ANY operator, is incorrect because this operator will return true if prod_list is different from any of the values in the list, which is not the logic represented by the other two queries.
NEW QUESTION # 314
......
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