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The WGU Applied-Algebra exam questions pdf is properly formatted to give candidates the asthenic and unformatted information they need to succeed in the Applied-Algebra exam. In addition to the comprehensive material, a few basic and important questions are highlighted and discussed in the Applied-Algebra Exam Material file. These questions are repeatedly seen in past WGU Applied Algebra FXO2 PFXP C957 exam papers. The WGU Applied Algebra FXO2 PFXP C957 practice questions are easy to access and can be downloaded anytime on your mobile, laptop, or MacBook.
| Section | Objectives |
|---|---|
| Linear Functions and Systems | - Systems of Equations
|
| Polynomial and Rational Expressions | - Polynomials
|
| Exponential and Logarithmic Concepts | - Exponential Functions
|
| Foundations of Algebra | - Equations and Inequalities
|
| Functions and Graphs | - Graphing Functions
|
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NEW QUESTION # 102
The graphed function n(t)represents the number of animals, n, at a feeding station thours after 5:00 a.m. The plotted points Aand Bhave coordinates (1#10.6)and (8#6.59).
Which statement gives the correct interpretation of the average rate of change of the number of animals over the interval from point Ato point B?
Answer: B
Explanation:
The average rate of change tells how much the output changes per one unit of input.
Here:
t= " hours after 5:00 a.m. "
and
n(t)= " number of animals "
The two given points are:
A=(1,10.6)
and
B=(8,6.59)
Use the average rate of change formula:
(y_2-y_1)/(x_2-x_1 )
Substitute the coordinates:
(6.59-10.6)/(8-1)
=(-4.01)/7
#-0.573
The negative sign means the number of animals is decreasing.
So the correct interpretation is:
" The number of animals at the station decreases at an average rate of " 0.573 " animals per hour. " Therefore, the correct answer is:
# ( " B " )
NEW QUESTION # 103
The graph shows the daily practice duration for a musician, where the number of days since the beginning of the month is along the horizontal axis and the number of minutes practiced per day is along the vertical axis.
Based on the graph, what was the practice duration for day 8?
Answer: D
Explanation:
This question asks us to interpret a value from a graph.
The horizontal axis represents:
Days
The vertical axis represents:
Practice duration in minutes
We need to find the practice duration on day 8.
To do this:
Locate 8 on the horizontal axis.
Move vertically until you reach the blue graph.
Read the corresponding value on the vertical axis.
From the graph, when:
x=8
the blue graph is at:
y=115
So the musician practiced for:
115 minutes
NEW QUESTION # 104
A team was assembled at a manufacturing plant in order to boost productivity. The team was tasked with producing as many widgets each day as possible. The results are shown in the graph.
What is the correct interpretation of the average rate of change from day 6 to day 14?
Answer: B
Explanation:
The graph models the number of widgets the team can produce each day.
The horizontal axis represents:
" days "
The vertical axis represents:
" widgets "
The graph gives two labeled points:
(6#3.4)
and
(14#23)
The average rate of change is:
" change in widgets " / " change in days "
Substitute the values:
(23-3.4)/(14-6)
=19.6/8
=2.45
Rounded to the nearest tenth:
2.5
This means the team increased production by an average of approximately:
2.5 " widgets each day "
Therefore, the correct answer is:
# ( " B " )
NEW QUESTION # 105
A new company just launched and is using the function M(t)to predict its market share after tyears. The graph of M(t)is shown.
When should the company expect to have a market share of 60%?
Answer: C
Explanation:
The function M(t)represents the company's predicted market share after tyears.
The horizontal axis represents:
t= " time in years "
The vertical axis represents:
M(t)= " market share percentage "
We need to find when the company's market share reaches:
60%
To answer this from the graph:
Locate 60on the vertical axis.
Move horizontally until reaching the blue curve.
Move downward to the horizontal axis to read the corresponding time.
From the graph, the blue curve reaches 60%a little after 6years, approximately at:
t=6.6
So the company should expect to have a market share of 60%after about:
6.6 " years "
NEW QUESTION # 106
The function P(t) represents the yearly profit, in thousands of dollars, for a virtual store since opening. The graph of P(t) is shown.
What is the time at which the store reached the maximum yearly profit?
Answer: D
Explanation:
The maximum value of a graph is the highest output value the function reaches. Since P(t) represents yearly profit, the maximum value occurs where the store earns its greatest yearly profit. The graph is a downward- opening curve, so its highest point is the vertex. To answer the question, we need the t-value of the vertex, not the profit amount. From the graph, the highest point occurs between 4 and 5 years after opening, closest to 4.5 years. This means the virtual store reached its maximum yearly profit approximately 4.5 years after it opened.
The later values decrease after the vertex, so options involving 7.5 or 14 years are not correct. Therefore, the correct answer is B.
NEW QUESTION # 107
......
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