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Oracle 1z1-071 Exam Syllabus Topics:

Section	Objectives
Topic 1: Subqueries and Advanced SQL	- Correlated subqueries and nested queries - Single-row and multi-row subqueries
Topic 2: SQL Functions	- Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions - Single-row functions 1. Character, numeric, date functions
Topic 3: SQL Retrieval	- SELECT statements and filtering data 1. ORDER BY and row limiting 2. WHERE clause and conditions - Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS
Topic 4: Relational Database Concepts	- Data types and database objects overview - Tables, rows, columns, and relational model basics
Topic 5: Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints

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Oracle Database SQL Sample Questions (Q228-Q233):

NEW QUESTION # 228
In your session, the NLS._DAE_FORMAT is DD- MM- YYYY.There are 86400 seconds in a day.Examine this result:
DATE
02-JAN-2020
Which statement returns this?

A. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '4' DAYINTERVAL
'120' SECOND, 'DD-MON-YY') AS "daTe"
FROM DUAL;
B. SELECT TO_ CHAR(TO_ DATE('29-10-2019') + INTERVAL '3' MONTH + INTERVAL '7' DAY - INTERVAL '360' SECOND, ' DD-MON-YYYY') AS "date" FROM DUAL;
C. SELECT TO_ CHAR(TO_ DATE('29-10-2019') +INTERVAL '2'; MONTH + INTERVAL '5'; DAY
-
INTERVAL '86410' SECOND, ' DD-MON-YYYY') AS "date"
FROM DUAL;
D. SELECT To CHAR(TO _DATE('29-10-2019') + INTERVAL '2' NONTH + INTERVAL '5' DAY INEERVAL '120' SECOND, ' DD-MON-YYY) AS "date" FROM DUAL;
E. SELECT-TO_CHAR(TO _DATE('29-10-2019'+ INTERVAL '2' MONTH+INTERVAL '6' DAYINTERVAL
'120' SECOND, 'DD-MON-YY') AS "daTe"
FROM DUAL;

Answer: B

Explanation:
To calculate the date from a given base date with intervals, Oracle allows you to add or subtract intervals from dates. Since the NLS_DATE_FORMAT is set to DD-MM-YYYY, the output is expected to be in that format.
Option B seems to calculate a date that is 3 months and 7 days ahead of October 29, 2019, and then subtracts
360 seconds (which is 6 minutes), resulting in a time that is still within the same day.
Here's how the calculation in option B would work out:
* Start date: 29-10-2019
* Add 3 months: 29-01-2020
* Add 7 days: 05-02-2020
* Subtract 360 seconds: Since it's only a few minutes, the date remains 05-02-2020.
However, this does not match the provided result of 02-JAN-2020. We would need to consider the exact amount of time being subtracted or added to find the correct answer.
But upon reviewing the options, they all have various syntax errors such as a missing TO_CHAR function, incorrect quotes, and date formats not matching the session's NLS_DATE_FORMAT. Therefore, we would need to correct these issues to find the right answer.

NEW QUESTION # 229
Examine the commands used to create DEPARTMENT_DETAILS and COURSE_DETAILS tables:

You want to generate a list of all department IDs along with any course IDs that may have been assigned to them.
Which SQL statement must you use?

A. SELECT d.department_id, c.course_id FROM course_details c LEFT OUTER JOIN department_details d ON (c.department_id=d.department_id);
B. SELECT d.department_id, c.course_id FROM department_details d RIGHT OUTER JOIN course_details c ON (c.department_id=d.department_id);
C. SELECT d.department_id, c.course_id FROM department_details d LEFT OUTER JOIN course_details c ON (d.department_id=c.department_id);
D. SELECT d.department_id, c.course_id FROM department_details d RIGHT OUTER JOIN course_details c ON (d.department_id=c.department_id);

Answer: C

NEW QUESTION # 230
Evaluate the following query

What is the correct output of the above query?

A. +25-00, +54-02, +00 11:12:10.123457
B. +25-00, +00-650, +00 11:12:10.123457
C. +00-300, +00-650, +00 11:12:10.123457
D. +00-300, +54-02, +00 11:12:10.123457

Answer: A

NEW QUESTION # 231
Which two are true about queries using set operators (UNION, UNION ALL, INTERSECT and MINUS)?

A. Each SELECT statement in the query can have an ORDER BY clause.
B. The FOR UPDATE clause cannot be specified.
C. None of the set operators can be used when selecting CLOB columns.
D. There must be an equal number of columns in each SELECT list.
E. The name of each column in the first SELECT list must match the name of the corresponding column in each subsequent SELECT list.

Answer: B,D

Explanation:
A). True. When using set operators, the number and order of columns must be the same in all SELECT statements involved in the query. The data types of those columns must also be compatible.
E). True. The FOR UPDATE clause cannot be specified in a subquery or a SELECT statement that is combined with another SELECT statement by using a set operator.
B is incorrect because the column names do not need to match; only the number and data types of the columns must be compatible. C is incorrect because only the final SELECT statement in the sequence of UNION/INTERSECT/MINUS operations can have an ORDER BY clause. D is incorrect because, as of Oracle 12c, UNION ALL can be used with CLOB columns, but UNION, INTERSECT, and MINUS cannot.

NEW QUESTION # 232
View the Exhibits and examine the structure of the COSTS and PROMOTIONS tables.
You want to display PROD IDS whose promotion cost is less than the highest cost PROD ID in a pro motion time interval.
Examine this SQL statement:
SELECT prod id
FROM costs
WHERE promo id IN
(SELECT promo id
FROM promotions
WHERE promo_cost < ALL
(SELECT MAX (promo cost)
FROM promotions
GROUP BY (promo_end date-promo_begin_date)) );
What will be the result?

A. It executes successfully and gives the required result.
B. It gives an error because the ALL keyword is not valid.
C. It gives an error because the GROUP BY clause is not valid
D. It executes successfully but does not give the required result.

Answer: D

NEW QUESTION # 233
......

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