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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Relational Database Concepts	10%	- ERD and SQL statement mapping - Relationship between database and SQL - Theoretical and physical aspects of relational databases
Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Aggregating Data Using Group Functions	10%	- Handling NULLs in group functions - GROUP BY and HAVING clauses - SUM, AVG, COUNT, MAX, MIN functions
Managing Views		- Create, modify and drop views - Updatable and read-only views
Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins
Managing Tables and Constraints		- Data types, creating/altering/dropping tables - Constraints: primary key, foreign key, unique, check, not null - Temporary and external tables
Restricting and Sorting Data	15%	- ORDER BY clause and sorting rules - WHERE clause and filtering conditions - Operator precedence - Substitution variables, DEFINE and VERIFY commands
Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Retrieving Data Using SQL SELECT Statement	20%	- Column aliases, concatenation, literals and DISTINCT - SELECT statement syntax and usage - Arithmetic operations and NULL handling
Conversion Functions and Conditional Expressions	10%	- TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions - Implicit and explicit data type conversion
Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and use sequences - Create and maintain indexes
Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Manipulating Data and Managing Transactions		- Multi-table inserts - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements
Using Data Dictionary Views		- Retrieve metadata and object information
Controlling User Access		- Roles, granting and revoking privileges - System and object privileges

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Oracle Database SQL Sample Questions (Q341-Q346):

NEW QUESTION # 341
Examine the commands used to create DEPARTMENT_DETAILS and COURSE_DETAILS tables:

You want to generate a list of all department IDs along with any course IDs that may have been assigned to them.
Which SQL statement must you use?

A. SELECT d.department_id, c.course_id FROM department_details d RIGHT OUTER JOIN course_details c ON (d.department_id=c.department_id);
B. SELECT d.department_id, c.course_id FROM course_details c LEFT OUTER JOIN department_details d ON (c.department_id=d.department_id);
C. SELECT d.department_id, c.course_id FROM department_details d RIGHT OUTER JOIN course_details c ON (c.department_id=d.department_id);
D. SELECT d.department_id, c.course_id FROM department_details d LEFT OUTER JOIN course_details c ON (d.department_id=c.department_id);

Answer: D

NEW QUESTION # 342
Which two are true about queries using set operators (UNION, UNION ALL, INTERSECT and MINUS)?

A. The name of each column in the first SELECT list must match the name of the corresponding column in each subsequent SELECT list.
B. The FOR UPDATE clause cannot be specified.
C. There must be an equal number of columns in each SELECT list.
D. None of the set operators can be used when selecting CLOB columns.
E. Each SELECT statement in the query can have an ORDER BY clause.

Answer: B,C

NEW QUESTION # 343
Examine the data in the ENPLOYEES table:

Which statement will compute the total annual compensation tor each employee

A. SELCECT last_namo, (monthly_salary * 12) + (menthy_salary * 12 * NVL (monthly_commission_pct, 0)) AS annual_comp FROM employees
B. SELCECT last_namo, (monthly_salary * 12) + (menthy_salary * 12 * monthly_commission_pct) AS annual_comp FROM employees
C. SELCECT last_namo, (monthly_salary * 12) + (monthly_commission_pct * 12) AS annual_comp FROM employees
D. SECECT last_namo, (menthy_salary + monthly_commission_pct) * 12 AS annual_comp FROM employees;

Answer: A

NEW QUESTION # 344
Which two statements are true regarding constraints? (Choose two.)

A. A column with a FOREIGN KEYconstraint can never contain a NULL value.
B. Constraints are enforced only during INSERToperations.
C. A column with a UNIQUEconstraint can contain a NULL value.
D. All constraints can be defined at the table or column level.
E. A constraint can be disabled even if the constrained column contains data.

Answer: C,E

NEW QUESTION # 345
Examine these statements:
CREATE TABLE dept (
deptno NUMBER PRIMARY KEY,
diname VARCHAR2(10) ,
mgr NUMBER ,
CONSTRAINT dept_fkey FOREIGN KEY(mgr) REFERENCES emp (empno));
CREATE TABLE emp (
Empno NUMBER PRIMARY KEY,
Ename VARCHAR2 (10) ,
deptno NUMBER,
CONSTRAINT emp_fkey FOREIGN KEY (deptno) REFERENCES dept (deptno) DISABLE); ALTER TABLE emp MODIFY CONSTRAINT emp_fkey ENABLE; Which two are true?

A. The DEFT FKEY constraint definition must be removed from the CREATE TABLE DEF statement.and be added with an AITER TABLE statement once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.
B. The MGR column in the DEPT table will not be able to contain NULL values.
C. Both foreign key constraint definitions must be removed from the CREATE TABLE statements, andbe added with ALTER TABLE statements once both tables are created, for the two CREATE TABLEstatements to execute successfully in the order shown.
D. The Deptno column in the emp table will be able to contain nulls values.
E. All three statements execute successfully in the order shown
F. The CREATE TABLE EMP statement must precede the CREATE TABLE DEPT statement for all threestatements to execute successfully.

Answer: D,E

Explanation:
E). True. The deptno column in the emp table can contain null values unless explicitly constrained not to, which is not the case here.
F). True. The three statements can execute successfully in the order shown. The foreign key constraint in the dept table is referring to the emp table which does not yet exist, but this is not a problem because it is not immediately enabled. The emp table is created next with a disabled foreign key constraint referencing the already created dept table. Finally, the foreign key constraint on emp is enabled after both tables are in place.
A is incorrect because the MGR column can contain NULL values as there is no NOT NULL constraint applied to it. B is incorrect because the CREATE TABLE EMP statement contains a disabled foreign key, so it can be created before CREATE TABLE DEPT. C and D are incorrect because foreign key constraints do not need to be removed and added later for the tables to be created successfully; they can be managed as shown in the provided statements.

NEW QUESTION # 346
......

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