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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Topic 1: Managing Views		- Updatable and read-only views - Create, modify and drop views
Topic 2: Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Topic 3: Displaying Data from Multiple Tables	15%	- Equijoins and non-equijoins - Cartesian products - Self-joins and outer joins
Topic 4: Managing Tables and Constraints		- Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables - Temporary and external tables
Topic 5: Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Topic 6: Manipulating Data and Managing Transactions		- Transaction control: COMMIT, ROLLBACK, SAVEPOINT - INSERT, UPDATE, DELETE, MERGE statements - Multi-table inserts
Topic 7: Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Topic 8: Restricting and Sorting Data	15%	- WHERE clause and filtering conditions - Operator precedence - ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands
Topic 9: Controlling User Access		- Roles, granting and revoking privileges - System and object privileges
Topic 10: Managing Indexes, Synonyms and Sequences		- Create and use sequences - Create and maintain indexes - Create and use synonyms
Topic 11: Conversion Functions and Conditional Expressions	10%	- Implicit and explicit data type conversion - NVL, NULLIF, COALESCE and CASE expressions - TO_CHAR, TO_NUMBER, TO_DATE functions
Topic 12: Retrieving Data Using SQL SELECT Statement	20%	- Arithmetic operations and NULL handling - SELECT statement syntax and usage - Column aliases, concatenation, literals and DISTINCT
Topic 13: Using Data Dictionary Views		- Retrieve metadata and object information
Topic 14: Relational Database Concepts	10%	- ERD and SQL statement mapping - Relationship between database and SQL - Theoretical and physical aspects of relational databases
Topic 15: Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Topic 16: Aggregating Data Using Group Functions	10%	- SUM, AVG, COUNT, MAX, MIN functions - Handling NULLs in group functions - GROUP BY and HAVING clauses

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Oracle Database SQL Sample Questions (Q372-Q377):

NEW QUESTION # 372
Examine the description products table:

Examine the description of the new_projects table;

Which two queries execute successfully?

Answer: A,C

Explanation:
To determine which queries will execute successfully, we need to consider the compatibility of the column definitions and the structure of the SELECT statements:
Option A uses the MINUS set operator, which subtracts rows returned by the second SELECT statement from the rows returned by the first. For MINUS to work, the number and the order of columns and their data types must be the same in both queries. This query will not execute successfully because the second SELECT statement does not include all columns from the first SELECT statement, and the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
Option B uses the UNION ALL set operator, which appends the results of the second SELECT statement to the results of the first. Unlike UNION, UNION ALL does not eliminate duplicate rows. This query will execute successfully because UNION ALL does not require the same data types or sizes, and the result will contain all columns from the first SELECT statement filled with NULL for non-matching columns from the second SELECT statement.
Option C uses the UNION set operator, which requires the same number of columns and compatible data types. This query will not execute successfully because PROD_NAME has different data types (CHAR(4) vs VARCHAR2(10)), and the result of a UNION must have the same number of columns with compatible data types in the two SELECT statements.
Option D uses the UNION set operator as well, but unlike Option C, it does not require a specific data type match because both SELECT statements include all columns and UNION is used (which will automatically handle type conversion where necessary). This query will execute successfully.
Option E uses the INTERSECT set operator, which requires the same number and order of columns and their data types to be identical or compatible. This query will not execute successfully because the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
Reference:
Oracle Documentation on Set Operators: SQL Language Reference - Set Operators Oracle Documentation on Data Type Precedence: SQL Language Reference - Data Type Precedence In conclusion, only Option B and Option D will execute successfully because they adhere to the rules of the UNION ALL and UNION operators respectively, regarding column count and data type compatibility.

NEW QUESTION # 373
Which two tasks can be performed by using Oracle SQL statements? (Choose two.)

A. starting up a database instance
B. querying data from tables in different databases
C. connecting to a database instance
D. executing operating system (OS) commands in a session
E. changing the password for an existing database user

Answer: B,E

Explanation:
Explanation
http://www.techonthenet.com/oracle/password.php
https://docs.oracle.com/cd/B28359_01/server.111/b28324/tdpii_distdbs.htm

NEW QUESTION # 374
Examine the structure of the ORDERStable:

You want to find the total value of all the orders for each year and issue this command:
SQL> SELECT TO_CHAR(order_date,'rr'), SUM(order_total) FROM orders
GROUP BY TO_CHAR(order_date, 'yyyy');
Which statement is true regarding the result? (Choose the best answer.)

A. It return an error because the datatype conversion in the SELECTlist does not match the data type conversion in the GROUP BYclause.
B. It executes successfully and gives the correct output.
C. It executes successfully but does not give the correct output.
D. It returns an error because the TO_CHARfunction is not valid.

Answer: A

NEW QUESTION # 375
Examine the description of the EMPLOYEES table:

Which query requires explicit data type conversion?

A. SELECT join_date + `20' FROM employees;
B. SELECT salary + `120.50' FROM employees;
C. SELECT join_date || ` ` || salary FROM employees;
D. SELECT SUBSTR(join_date, 1, 2) ?10 FROM employees;
E. SELECT join_date FROM employees WHERE join_date > '10-02-2018';

Answer: E

NEW QUESTION # 376
Examine the description of the PRODUCTS table:

Which two statements execute without errors?

A. MERGE INTO new_prices n
USING products p
ON (p.prod_id =n.prod_id)
WHEN NOT MATCHED THEN
INSERT (n.prod _id, n.price) VALUES (p.prod_id, cost*.01)
WHERE (p.cost<200);
B. MERGE INTO new_prices n
USING (SELECT * FROM products WHERE cost>150) p
ON (n.prod_id= p.prod_id)
WHEN MATCHED THEN
DELETE WHERE (p.cost<200)
C. MERGE INTO new_prices n
USING (SELECT * FROM products WHERE cost>150) p
ON (n.prod_id= p.prod_id)
WHEN MATCHED THEN
UPDATE SET n.price= p.cost*.01
DELETE WHERE (p.cost<200);
D. MERGE INTO new_prices n
USING (SELECT * FROM products) p
WHEN MATCHED THEN
UPDATE SET n.price= p.cost* 01
WHEN NOT MATCHED THEN
INSERT(n.prod_id, n.price) VALUES(p.prod_id, cost*.01)
WHERE(p.cost<200);

Answer: A,C

NEW QUESTION # 377
......

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