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Candidates who pass the Oracle 1z0-071 Exam will earn the Oracle Database SQL Certified Associate certification. Oracle Database SQL certification is recognized by employers worldwide and can help individuals stand out in the job market. Additionally, the certification can serve as a stepping stone to more advanced certifications in Oracle database administration and development.

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Oracle 1z0-071 exam, also known as the Oracle Database SQL exam, is designed to test the knowledge and skills of individuals in the area of SQL for Oracle databases. 1z0-071 Exam is ideal for individuals who are looking to validate their understanding of SQL and wish to obtain a certification in this area.

Oracle Database SQL Sample Questions (Q384-Q389):

NEW QUESTION # 384
In which three situations does a new transaction always start? (Choose three.)

A. when issuing a SELECT FOR UPDATEstatement after a CREATE TABLE AS SELECTstatement was issued in the same session
B. when issuing the first Data Manipulation Language (DML) statement after a COMMIT or ROLLBACK statement was issued in the same session
C. when issuing a DML statement after a DML statement failed in the same session
D. when issuing a TRUNCATEstatement after a SELECT statement was issued in the same session
E. when issuing a CREATE TABLEstatement after a SELECTstatement was issued in the same session
F. when issuing a CREATE INDEXstatement after a CREATE TABLEstatement completed successfully in the same session

Answer: A,B,F

NEW QUESTION # 385
Which statement will execute successfully?

A. SELECT 1, 2 FROM DUAL
UNION
SELECT 3, 4 FROM DUAL
ORDER BY 3, 4;
B. SELECT 1 FROM DUAL
UNION
SELECT 2 FROM DUAL
ORDER BY 1, 2;
C. SELECT 1, 2 FROM DUAL
UNION
SELECT 3, 4 FROM DUAL
ORDER BY 1, 2;
D. SELECT 3 FROM DUAL
UNION
SELECT 4 FROM DUAL
ORDER BY 3 ;

Answer: D

Explanation:
B). True. This statement will execute successfully because it has a single column in the SELECT statements combined with UNION, and the ORDER BY clause is referencing a valid column in the result set.
A is incorrect because it uses an ORDER BY clause with two columns, which is not allowed when the SELECT statements have only one column each. C is incorrect for the same reason as A; it references columns that do not exist in the result set. D is incorrect because it attempts to ORDER BY a second column, which does not exist in the result of the union.

NEW QUESTION # 386
View the exhibit and examine the structure of the STOREStable.

You want to display the NAME of the store along with the ADDRESS, START_DATE, PROPERTY_PRICE, and the projected property price, which is 115% of property price.
The stores displayed must have START_DATEin the range of 36 months starting from 01-Jan-2000 and above.
Which SQL statement would get the desired output?

A. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address, start_date, property_price, property_price*115/100
FROM stores
WHERE TO_NUMBER(start_date-TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
B. SELECT name, concat (address||','| |city| |', ', country) AS full_address, start_date, property_price, property_price*115/100
FROM stores
WHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR'))
<=36;
C. SELECT name, address||','||city||','||country AS full_address,
start_date,
property_price, property_price*115/100
FROM stores
WHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR'))
<=36;
D. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address, start_date, property_price, property_price*115/100
FROM stores
WHERE MONTHS_BETWEEN (start_date, '01-JAN-2000') <=36;

Answer: B

NEW QUESTION # 387
Which two statements are true regarding multiple-row subqueries? (Choose two.)

A. They should not be used with the NOT IN operator in the main query if NULL is likely to be a part of the result of the subquery.
B. They can be used to retrieve multiple rows from a single table only.
C. They use the < ALL operator to imply less than the maximum.
D. They can contain group functions.
E. They always contain a subquery within a subquery.

Answer: A,D

NEW QUESTION # 388
Examine the description of the PRODUCT_INFORMATION table:

A. SELECT (COUNT(list_price) FROM Product_intormation WHERE list_price=NULL;
B. BELECT COUNT(list_price) FROM product_information where list_price is NULL;
C. SELECT count(nvl( list_price,0)) FROM product_information WHERE list_price is null;
D. SELECT COUNT(DISTINCT list_price) FROM product_information WHERE list_price is null.

Answer: C

NEW QUESTION # 389
......

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