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| Section | Weight | Objectives |
|---|---|---|
| Variables, Types, and Collections | 23% | - String manipulation and Date objects - Variable declaration (var, let, const, scoping, hoisting) - Type coercion and type conversion - Array manipulation (map, filter, reduce, forEach, find) - JSON parsing and stringification |
| Asynchronous Programming | 13% | - Callback patterns - Event loop and asynchronous code execution - Promises and async/await |
| Debugging and Error Handling | 7% | - try-catch blocks - Logging strategies and debugging techniques |
| Browser and Events | 17% | - Event handling, propagation, bubbling, and capturing - Browser Developer Tools - DOM manipulation |
| Server Side JavaScript | 8% | - Node.js applications - Salesforce API integration - Modules and file operations |
| Objects, Functions, and Classes | 25% | - ES6 Classes, constructors, methods, and inheritance - Higher-order functions and closures - JavaScript modules (export, import) - Function declarations, expressions, and arrow functions - Object creation, properties, and prototypal inheritance |
| Testing | 7% | - Test-driven development principles - Unit testing with Jest - Automated testing strategies |
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NEW QUESTION # 95
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?
Answer: B,D
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
________________________________________
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.
NEW QUESTION # 96
A developer creates a class that represents a news story based on the requirements that a Story should have a body, author, and view count. The code is shown below:
01 class Story {
02 // Insert code here
03 this.body = body;
04 this.author = author;
05 this.viewCount = viewCount;
06 }
07 }
Which statement should be inserted in the placeholder on line 02 to allow for a variable to be set to a new instance of a Story with the three attributes correctly populated?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
In ES6 class syntax, the special method used to initialize a new instance is called constructor.
A class definition syntax:
class ClassName {
constructor(param1, param2) {
this.prop1 = param1;
this.prop2 = param2;
}
}
The constructor method:
Is called automatically when you create a new instance with new ClassName(...).
Receives the arguments passed in the new expression.
Assigns values to this to set instance properties.
Applying this to Story
We want to be able to write:
const article = new Story('Some body', 'Author Name', 100);
and have:
article.body === 'Some body'
article.author === 'Author Name'
article.viewCount === 100
To achieve this, the class must have:
class Story {
constructor(body, author, viewCount) {
this.body = body;
this.author = author;
this.viewCount = viewCount;
}
}
So the correct line 02 is:
constructor(body, author, viewCount) {
Why the other options are incorrect
A . constructor() {
This defines a constructor with no parameters.
The lines inside the constructor use body, author, and viewCount, which would be undefined unless they exist in an outer scope (they normally do not).
This would lead to the instance properties being set to undefined in normal usage.
B . super(body, author, viewCount) {
super(...) is used inside a constructor of a subclass to call the parent class constructor.
You cannot use super(...) { as a method definition; this is invalid syntax in a class body.
Additionally, Story as given is not shown extending any class, so super is inappropriate here.
C . function Story(body, author, viewCount) {
Inside a class definition, you do not use the function keyword to define methods.
function Story(...) here would be invalid syntax in a class body.
Even if it were allowed, the special constructor method for a class is named constructor, not the class name.
Therefore, only:
constructor(body, author, viewCount) {
correctly declares the constructor for the Story class and ensures instances created with new Story(body, author, viewCount) have all three properties populated.
Reference / Study Guide concepts (no links):
ES6 class syntax
constructor method in classes
this and instance properties in classes
Difference between class constructors and regular functions
Invalid use of super and function inside class bodies
________________________________________
NEW QUESTION # 97
Corrected code:
let a = "*";
let b = "**";
// x = 3;
console.log(a);
What is displayed when the code executes?
Answer: B
Explanation:
The correct answer is B because variable a is declared and initialized before it is printed.
let a = "*";
This creates a block-scoped variable named a and assigns it the string value:
"*"
The line:
// x = 3;
is a comment. JavaScript ignores comments during execution, so this line has no effect.
Then this line runs:
console.log(a);
Since a already exists and contains "*", the console displays:
* Option A is incorrect because a is defined.
Option C is incorrect because a has an assigned value, so it is not undefined.
Option D is incorrect because a was never assigned null.
Therefore, the verified answer is B.
NEW QUESTION # 98
Given the code below:
const delay = async delay =>{
return new Promise((resolve,reject)=>{
console.log(1);
setTimeout(resolve,deleay);
});
};
const callDelay =async ()=>{
console.log(2);
const yup = await delay(1000);
console.log(3);
}
console.log(4);
callDelay();
console.log(5);
What is logged to the console?
Answer:
Explanation:
4 2 1 5 3
NEW QUESTION # 99
Refer to the following code block:
What is the console output?
Answer: D
NEW QUESTION # 100
......
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