可靠的Applied-Algebra權威認證和資格考試中的領先提供者和快速下載Applied-Algebra:WGU Applied Algebra FXO2 PFXP C957

在這個競爭激烈的IT行業中,擁有一些認證證書是可以幫助你步步高升的。很多公司升職加薪的依據就是你擁有的認證證書的含金量。WGU Applied-Algebra認證考試就是個含金量很高的考試。WGU Applied-Algebra 認證證書能滿足很多正在IT行業拼搏的人的需求。Fast2test可以為你提供WGU Applied-Algebra認證考試的針對性訓練。你可以先在網上免費下載Fast2test為你提供的關於WGU Applied-Algebra 認證考試的培訓工具的試用版和部分練習題及答案作為嘗試。

WGU Applied-Algebra Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Exponents, Radicals, and Quadratic Relationships15%- Properties of exponents
- Basic quadratic graphs
- Solving quadratic equations
- Simplifying radical expressions
Topic 2: Systems of Equations and Inequalities15%- Solving by substitution and elimination
- Graphical solutions
- Applications of systems
Topic 3: Graphing and Functions25%- Coordinate plane and plotting points
- Slope and equations of lines
- Function notation and evaluation
- Linear functions and their graphs
Topic 4: Linear Equations and Inequalities25%- Solving single-variable equations
- Real-world applications
- Solving and graphing inequalities
Topic 5: Algebraic Expressions and Operations20%- Simplifying and evaluating expressions
- Order of operations
- Operations with polynomials
- Variables, constants, and coefficients

>> Applied-Algebra權威認證 <<

Applied-Algebra認證考試資料庫

獲得Applied-Algebra認證是IT職業發展有利保证,而Fast2test公司提供最新最準確的Applied-Algebra題庫資料,幾乎包含真實考試的所有知識點,借助我們的學習資料,您不必浪費時間去閱讀過多的參考書籍,只需要花費一定的時間去學習我們的WGU Applied-Algebra題庫資料。本站提供PDF版本和軟件本版的Applied-Algebra題庫,PDF版本的方便打印,而對于軟件版本的WGU Applied-Algebra題庫可以模擬真實的考試環境,方便考生選擇。

最新的 Courses and Certificates Applied-Algebra 免費考試真題 (Q42-Q47):

問題 #42
As sacks are unloaded off a wagon, the total weight of the wagon and sacks changes. Each sack has the same weight. After 5 sacks are removed, the total weight of the wagon and remaining sacks is 135 pounds. After 9 sacks are removed, the total weight is 87 pounds. What is the weight of each sack?

答案:C

解題說明:
This situation has a constant rate of change because each sack weighs the same amount. After 5 sacks are removed, the total weight is 135 pounds. After 9 sacks are removed, the total weight is 87 pounds. From 5 to
9 sacks removed is 4 more sacks. Over the same interval, the total weight decreases by 135#87=48 pounds.
Since 4 sacks account for a 48-pound decrease, each sack must weigh 48÷4=12 pounds. This uses the linear idea that equal changes in the input produce equal changes in the output. Therefore, the weight of each sack is
12 pounds, which is answer A.


問題 #43
The function V(t)represents the number of travelers, V, in a travel depot thours after 7:00 a.m. The graph of V (t)is shown.

What does V(2)represent?

答案:D

解題說明:
The function V(t)represents the number of travelers in the travel depot.
The input trepresents:
" hours after 7:00 a.m. "
The output V(t)represents:
" number of travelers "
So V(2)means the number of travelers in the depot:
2 " hours after 7:00 a.m. "
From the graph, when:
t=2
the value of V(t)is approximately:
79.2
Since V(t)measures travelers, not hours, V(2)represents:
79.2 " travelers "
Therefore, the correct answer is:
# ( " D " )


問題 #44
The graph shows the estimated wait time, in minutes, based on the number of hours after 7:00 a.m.
What is the average rate of change of the wait time from point Ato point B?

答案:A

解題說明:
The average rate of change tells us how much the output changes, on average, for each 1-unit increase in the input.
Here:
x= " hours after 7:00 a.m. "
and
y= " estimated wait time in minutes "
From the graph, point Ais approximately:
A=(5,88.3)
and point Bis approximately:
B=(9,65)
Now use the average rate of change formula:
" Average rate of change " =(y_2-y_1)/(x_2-x_1 )
Substitute the values:
(65-88.3)/(9-5)
=(-23.3)/4
=-5.825
Rounded to two decimal places:
-5.83
The negative sign means the estimated wait time is decreasing from point Ato point B.
So the average rate of change is approximately:
-5.83 " minutes per hour "


問題 #45
The function P(t) represents the yearly profit, in thousands of dollars, for a virtual store since opening. The graph of P(t) is shown.

What is the time at which the store reached the maximum yearly profit?

答案:D

解題說明:
The maximum value of a graph is the highest output value the function reaches. Since P(t) represents yearly profit, the maximum value occurs where the store earns its greatest yearly profit. The graph is a downward- opening curve, so its highest point is the vertex. To answer the question, we need the t-value of the vertex, not the profit amount. From the graph, the highest point occurs between 4 and 5 years after opening, closest to 4.5 years. This means the virtual store reached its maximum yearly profit approximately 4.5 years after it opened.
The later values decrease after the vertex, so options involving 7.5 or 14 years are not correct. Therefore, the correct answer is B.


問題 #46
The populations, in thousands, of two towns are shown in the graph, where the horizontal axis measures the time in years.

Which town's population is growing at a faster rate?

答案:C

解題說明:
This question asks which town's population is growing at a faster rate.
Since both population graphs are straight lines, we compare their slopes.
The slope of a line represents the rate of change:
" slope " = " change in population " / " change in time "
From the graph:
Town A starts at about 8.0thousand people and increases at a rate of about 1.0thousand people per year.
Town B starts at about 5.5thousand people and increases at a rate of about 1.3thousand people per year.
Even though Town A starts with a larger population, the question asks about the growth rate, not the starting population.
Compare the rates:
1.3 > 1.0
So Town B is growing faster than Town A.


問題 #47
......

我們Fast2test確保你第一次嘗試通過考試,取得該認證專家的認證。因為我們Fast2test提供給你配置最優質的類比WGU的Applied-Algebra的考試考古題,將你一步一步帶入考試準備之中,我們Fast2test提供我們的保證,我們Fast2test WGU的Applied-Algebra的考試試題及答案保證你成功。

Applied-Algebra認證指南: https://tw.fast2test.com/Applied-Algebra-premium-file.html