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| Section | Objectives |
|---|---|
| JavaScript Fundamentals | - Control Flow and Error Handling - Variables, Data Types, and Operators - Functions and Scope |
| Object-Oriented JavaScript | - Objects and Prototypes - Classes and Inheritance |
| Salesforce Platform Integration | - Lightning Web Components (LWC) Basics - Working with Salesforce Data Models |
| Asynchronous Programming | - Callbacks, Promises, and Async/Await - API Calls and Data Fetching |
| Browser and DOM Interaction | - DOM Manipulation - Events and Event Handling |
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NEW QUESTION # 93
Given:
const str = 'Salesforce';
Which two statements result in 'Sales'?
Answer: C,D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
str = 'Salesforce'
Index positions:
S(0) a(1) l(2) e(3) s(4) f(5) o(6) r(7) c(8) e(9)
substring(start, end)
Start index inclusive, end index exclusive.
str.substring(0, 5) → characters at indices 0-4 → "Sales"
str.substring(1, 5) → indices 1-4 → "ales"
substr(start, length)
Start index, then number of characters.
str.substr(0, 5) → 5 characters starting at index 0 → "Sales"
str.substr(1, 5) → 5 characters from index 1 → "alesf"
So the expressions that return "Sales" are A and C.
________________________________________
NEW QUESTION # 94
Given the code below:
01 const delay = async delay => {
02 return new Promise((resolve, reject) => {
03 console.log(1);
04 setTimeout(resolve, delay);
05 });
06 };
07
08 const callDelay = async () => {
09 console.log(2);
10 const yup = await delay(1000);
11 console.log(3);
12 };
13
14 console.log(4);
15 callDelay();
16 console.log(5);
What is logged to the console?
Answer: A
Explanation:
Execution order:
Top-level code runs synchronously:
Line 14: console.log(4); → logs 4.
Line 15: callDelay(); is called.
Inside callDelay:
Line 9: console.log(2); → logs 2.
Line 10: await delay(1000);:
Calls delay(1000).
Inside delay(1000):
Line 3: console.log(1); → logs 1.
Line 4: setTimeout(resolve, delay); schedules resolve in 1000 ms.
delay returns a pending Promise. await pauses callDelay here and returns control to the event loop.
Back to top-level:
Line 16: console.log(5); → logs 5.
So synchronous log sequence is: 4, 2, 1, 5.
After ~1000 ms:
The setTimeout in delay resolves the Promise.
The await in callDelay resumes.
Line 11: console.log(3); → logs 3.
Final log order: 4 2 1 5 3.
Both A and B show the same sequence; one must be chosen, so A is correct.
Concepts: async/await flow, Promise resolution timing, event loop, and ordering of synchronous vs timer callbacks.
NEW QUESTION # 95
Refer to the code below:
Line 05 causes an error. What are the values of greeting and salutation once code completes?
Answer: C
NEW QUESTION # 96
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?
Answer: A,C
Explanation:
Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.
NEW QUESTION # 97
const str = 'Salesforce';
Which two statements result in the word "Sales"?
Answer: B,D
Explanation:
Comprehensive and Detailed
"Salesforce" indices: S(0) a(1) l(2) e(3) s(4) f(5) ...
A / C (substring(0, 5)):
substring(start, end) returns characters from start up to but not including end.
str.substring(0, 5) → characters at indices 0,1,2,3,4 → "Sales".
D (substr(0, 5)):
substr(start, length) returns length characters starting at start.
str.substr(0, 5) → 5 chars from index 0 → "Sales".
B is invalid because s is not defined; it should be 0. So the two correct statements are A and D.
NEW QUESTION # 98
......
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