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| Section | Objectives |
|---|---|
| SD-WAN | - SD-WAN routing - Deployment and troubleshooting - Performance SLA - Overlay VPN - SD-WAN architecture - Application steering |
| Enterprise Firewall | - Advanced firewall deployment - Troubleshooting - Routing and advanced networking - Security Fabric integration - Authentication and identity - Centralized management and analytics - VPN technologies - High availability |
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NEW QUESTION # 146
Exhibit.
Refer to the exhibit, which shows a partial output of diagnose hardware aysinfo memory.
Which two statements about the output are true? (Choose two.)
Answer: A,D
Explanation:
The partial output from diagnose hardware sysinfo memory provides details on system RAM allocation.
According to Fortinet ' s technical documentation for memory troubleshooting and Linux memory management (which FortiOS is based on):
MemFree is the portion of physical memory not currently allocated to any running process or kernel function.
Thus, 708880 kB is available and can be immediately used by user-space programs or system operations.
Inactive refers to pages in the memory cache that were previously in use for I/O or file system buffering but are now not actively referenced. These pages are retained in memory for quick access if needed again, but can be reclaimed for other memory operations if demand increases. The value 98908 kB here represents currently unused cache pages (inactive pages), ready for repurposing or deletion if the system requires more RAM.
Cached represents the total amount of system memory allocated to cache, which includes both active and inactive cache pages. It does not, by itself, represent I/O cache exclusively, nor does " inactive " mean memory "will never be used" as the kernel can re-purpose inactive pages on demand.
References:
Fortinet Technical Tip: Explaining the ' diagnose hard sysinfo memory ' command FortiOS System Administration Guide: Linux Memory Reporting, Cached and Inactive Statistics
NEW QUESTION # 147
Refer to the exhibit, which shows the partial output of a real-time OSPF debug.
Why are the two FortiGate devices unable to form an adjacency?
Answer: C
NEW QUESTION # 148
Which statement about IKEv2 is true?
Answer: B
Explanation:
The correct answer is B .
The study guide explicitly states: "IKE version 2 does not interoperate with IKE version 1, but they share enough of the header format that both versions can unambiguously operate over the same UDP port." That directly proves B .
Why the other options are wrong:
* A is wrong because the study guide shows authentication methods as Asymmetric for IKEv2 and Symmetric for IKEv1
* C is wrong because the study guide does not say they use the same TCP port; instead, it specifically says they can operate over the same UDP port
* D is wrong because the study guide states: "IKEv2 does not use the concept of phase 1 or phase 2" , even though FortiOS CLI/GUI still uses those terms for configuration purposes
NEW QUESTION # 149
Refer to the exhibit.
The output of the get router info bgp summary command is shown.
Which statement regarding adjacencies between the local router and its neighbors is correct?
Answer: D
Explanation:
The correct answer is B .
In the exhibit:
* Neighbor 100.64.1.254 shows State/PfxRcd = 1 , which means the session is established and the local FortiGate has received 1 prefix
* Neighbor 100.64.2.254 shows State/PfxRcd = Active
The study guide explains the BGP states exactly:
* Connect : Waiting for a successful three-way TCP connection
* Active : Unable to establish the TCP session
* OpenSent : Waiting for an OPEN message from the peer
* OpenConfirm : Waiting for the keepalive message from the peer
* Established : Peers have successfully exchanged OPEN and keepalive messages It also explains how to read the State/PfxRcd column:
"If the state is not established, this column displays the BGP state. If the state is established, this column displays the number of prefixes that the local FortiGate received from that neighbor." Therefore, because neighbor 100.64.2.254 is in Active state, the correct conclusion is that the BGP adjacency cannot form because the TCP session could not be established .
Why the other options are wrong:
* A is wrong because BGP can establish adjacencies with multiple neighbors independently; one established neighbor does not block another
* C is wrong because BGP adjacency is not established based on neighbor "priority"; the output shows adjacency is established because the session completed and prefixes were exchanged
* D is wrong because having two neighbors in the same remote AS is valid in BGP and does not prevent adjacency formation So the verified answer is: B .
NEW QUESTION # 150
Refer to the exhibit, which shows the modified output of the routing kernel.
Which statement is true?
Answer: D
NEW QUESTION # 151
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