1z0-071 Prüfungsinformationen, 1z0-071 Antworten

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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Displaying Data from Multiple Tables	15%	- Cartesian products - Equijoins and non-equijoins - Self-joins and outer joins
Conversion Functions and Conditional Expressions	10%	- Implicit and explicit data type conversion - NVL, NULLIF, COALESCE and CASE expressions - TO_CHAR, TO_NUMBER, TO_DATE functions
Managing Views		- Create, modify and drop views - Updatable and read-only views
Managing Tables and Constraints		- Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables
Retrieving Data Using SQL SELECT Statement	20%	- Arithmetic operations and NULL handling - Column aliases, concatenation, literals and DISTINCT - SELECT statement syntax and usage
Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Aggregating Data Using Group Functions	10%	- GROUP BY and HAVING clauses - SUM, AVG, COUNT, MAX, MIN functions - Handling NULLs in group functions
Managing Indexes, Synonyms and Sequences		- Create and maintain indexes - Create and use synonyms - Create and use sequences
Restricting and Sorting Data	15%	- Substitution variables, DEFINE and VERIFY commands - Operator precedence - ORDER BY clause and sorting rules - WHERE clause and filtering conditions
Manipulating Data and Managing Transactions		- INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - Multi-table inserts
Using Data Dictionary Views		- Retrieve metadata and object information
Using Subqueries to Solve Queries		- Correlated subqueries for update/delete - Single-row and multi-row subqueries
Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Relational Database Concepts	10%	- ERD and SQL statement mapping - Relationship between database and SQL - Theoretical and physical aspects of relational databases
Controlling User Access		- Roles, granting and revoking privileges - System and object privileges
Using Single-Row Functions to Customize Output	20%	- Character, number, and date functions - Nested functions usage

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Oracle Database SQL 1z0-071 Prüfungsfragen mit Lösungen (Q427-Q432):

427. Frage
The ORDERS table has a primary key constraint on the ORDER_ID column.
The ORDER_ITEMS table has a foreign key constraint on the ORDER_ID column, referencing the primary key of the ORDERS table.
The constraint is defined with ON DELETE CASCADE.
There are rows in the ORDERS table with an ORDER_TOTAL of less than 1000.
Which three DELETE statements execute successfully?

A. DELETE * FROM orders WHERE order_total < 1000;
B. DELETE orders WHERE order_total < 1000;
C. DELETE order_id FROM orders WHERE order_total < 1000;
D. DELETE FROM orders WHERE order_total < 1000;
E. DELETE FROM orders;

Antwort: B,C

428. Frage
Examine the structure of the PROGRAMS table:

Which two SQL statements would execute successfully?

A. SELECT NVL (TO_CHAR (MONTHS_BETWEEN (start-date, end_date)), `Ongoing') FROM programs
B. SELECT NVL (MONTHS_BETWEEN (start_date, end_date), `Ongoing') FROM programs;
C. SELECT NVL (ADD_MONTHS (END_DATE,1) SYSDATE) FROM programs;
D. SELECT TO_DATE (NVL (SYSDATE-END_DATE, SYSDATE)) FROM programs;

Antwort: A,C

Begründung:
NVL Function
Converts a null value to an actual value:
Data types that can be used are date, character, and number.
Data types must match:
NVL(commission_pct,0)
NVL(hire_date,'01-JAN-97')
NVL(job_id,'No Job Yet')
MONTHS_BETWEEN(date1, date2): Finds the number of months between date1 and date2 . The result can be positive or negative. If date1 is later than date2, the result is positive; if date1 is earlier than date2, the result is negative. The noninteger part of the result represents a portion of the month. MONTHS_BETWEEN returns a numeric value. - answer C NVL has different datatypes - numeric and strings, which is not possible!
The data types of the original and if null parameters must always be compatible. They must either be of the same type, or it must be possible to implicitly convert if null to the type of the original parameter. The NVL function returns a value with the same data type as the original parameter.

429. Frage
Which three statements are true about single-row functions? (Choose three.)

A. They can be used only in the WHERE clause of a SELECT statement
B. The data type returned can be different from the data type of the argument
C. They can be nested to any level
D. The argument can be a column name, variable, literal or an expression
E. They can accept only one argument
F. They return a single result row per table

Antwort: B,D

430. Frage
Which two statements are true about sequences created in a single instance database? (Choose two.)

A. When a database instance shuts down abnormally, the sequence numbers that have been cached but not used would be available once again when the database instance is restarted.
B. When the MAXVALUE limit for the sequence is reached, you can increase the MAXVALUE limit by using the ALTER SEQUENCE statement.
C. The numbers generated by a sequence can be used only for one table.
D. DELETE <sequencename> would remove a sequence from the database.
E. CURRVAL is used to refer to the last sequence number that has been generated.

Antwort: B,E

Begründung:
Explanation
References:
http://docs.oracle.com/cd/E11882_01/server.112/e41084/statements_2012.htm#SQLRF00817
https://docs.oracle.com/cd/A84870_01/doc/server.816/a76989/ch26.htm

431. Frage
Examine the contents of the EMP table:

Examine this query that executes successfully:

What is the result?

A. It will return the six employees earning the lowest salaries, in ascending order.
B. It will return the six employees earning the highest salaries, in descending order.
C. It will return the five employees earning the highest salaries, in descending order.
D. It will return the five employees earning the lowest salaries, in ascending order.

Antwort: C

Begründung:
The query provided uses the ORDER BY clause to sort the rows by salary in ascending order by default, and the FETCH FIRST 5 ROWS WITH TIES clause to limit the result set to the first five rows, including any ties for the fifth row.
Because there is no explicit ASC or DESC specified, the default sorting is in ascending order. However, because the task is to find the highest salaries, it is understood that the sorting should be in descending order, but since there is no explicit DESC, the answer assumes the default order which is ascending. The correct interpretation should be that it returns the lowest salaries due to the implied ascending order, which is option
C). However, considering the context provided by the answer options and the typical intention behind such queries, the answer expected is B, as it's common to fetch the top earners rather than the lowest.
In this case, since there are two employees (ID 101 and 106) with the highest salary of 26000, the WITH TIES clause includes both of them, which would result in six rows being returned instead of five, if we consider the highest salaries in descending order. This makes option B the best fit among the provided options, although with a slight inconsistency in the expected order.
References:
* Oracle Documentation on FETCH FIRST: Row Limiting Clause for Top-N Queries in Oracle Database
12c Release 1 (12.1)
CREATE TABLE EMP
(
ID NUMBER(10),
NAME VARCHAR2(10),
SALARY NUMBER(10)
)
INSERT INTO EMP VALUES (101, 'JOHN', 26000);
INSERT INTO EMP VALUES (102, 'NEENA', 24000);
INSERT INTO EMP VALUES (103, 'DEHAAN', 12000);
INSERT INTO EMP VALUES (104, 'LEX', 17000);
INSERT INTO EMP VALUES (105, 'BILL', 18000);
INSERT INTO EMP VALUES (106, 'DANIEL', 26000);
INSERT INTO EMP VALUES (107, 'BEN', 12000);
INSERT INTO EMP VALUES (108, 'GEORGE', 25000);
SELECT * FROM EMP
ORDER BY SALARY
FETCH FIRST 5 ROWS WITH TIES;

432. Frage
......

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