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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Exam Format: | Multiple Choice Questions, Multiple Select Questions |
| Passing Score: | 65% |
| Related Certifications: | Salesforce Platform Developer I Salesforce Platform Developer II |
| Available Languages: | English |
| Real Exam Qty: | 60 (multiple choice) |
| Exam Price: | $200 USD |
| Exam Duration: | 105 minutes |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Recommended Training: | MDN Web Docs - JavaScript Guide Salesforce Trailhead - JavaScript Developer I |
| Exam Registration: | Salesforce Certification Registration Kryterion Webassessor (Exam Delivery) |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
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NEW QUESTION # 56
Given the code below:
01 const delay = async delay => {
02 return new Promise((resolve, reject) => {
03 console.log(1);
04 setTimeout(resolve, delay);
05 });
06 };
07
08 const callDelay = async () => {
09 console.log(2);
10 const yup = await delay(1000);
11 console.log(3);
12 };
13
14 console.log(4);
15 callDelay();
16 console.log(5);
What is logged to the console?
Answer: A
Explanation:
Execution order:
Top-level code runs synchronously:
Line 14: console.log(4); → logs 4.
Line 15: callDelay(); is called.
Inside callDelay:
Line 9: console.log(2); → logs 2.
Line 10: await delay(1000);:
Calls delay(1000).
Inside delay(1000):
Line 3: console.log(1); → logs 1.
Line 4: setTimeout(resolve, delay); schedules resolve in 1000 ms.
delay returns a pending Promise. await pauses callDelay here and returns control to the event loop.
Back to top-level:
Line 16: console.log(5); → logs 5.
So synchronous log sequence is: 4, 2, 1, 5.
After ~1000 ms:
The setTimeout in delay resolves the Promise.
The await in callDelay resumes.
Line 11: console.log(3); → logs 3.
Final log order: 4 2 1 5 3.
Both A and B show the same sequence; one must be chosen, so A is correct.
Concepts: async/await flow, Promise resolution timing, event loop, and ordering of synchronous vs timer callbacks.
NEW QUESTION # 57
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?
Answer: B,C
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
________________________________________
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.
NEW QUESTION # 58
A developer has two ways to write a function:
Option A:
function Monster(){
this.growl = ()=>{
console.log('Grr!');
}
}
Option B:
function Monster(){};
Monster.prototype.growl = ()=>{
console.log('Grr!');
}
After deciding on an option, the developercreates 1000 monster objects.
How many growl methods are created with Option A and Option B?
Answer: B
NEW QUESTION # 59
Refer to the code below:
01 funetion Person() (
02 thie. fixsttane = "Zoha'y
os}
05 Perscn.prototype = [
06 jek: x => 'Developer'
onde
09 const myFather = new Peracn():
10 const result = myFather.firstiame + ' * + myFather.jeb()
What is the value of result after line 10 executes?
Answer: B
NEW QUESTION # 60
Which statement allows a developer to update the browser navigation history without a page refresh?
Answer: B
NEW QUESTION # 61
......
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