1z0-071問題サンプル、1z0-071合格率

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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
Topic 1: SQL Retrieval	- Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS - SELECT statements and filtering data 1. ORDER BY and row limiting 2. WHERE clause and conditions
Topic 2: Relational Database Concepts	- Data types and database objects overview - Tables, rows, columns, and relational model basics
Topic 3: Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints
Topic 4: Subqueries and Advanced SQL	- Correlated subqueries and nested queries - Single-row and multi-row subqueries
Topic 5: SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions

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1z0-071合格率、1z0-071問題と解答

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Oracle Database SQL 認定 1z0-071 試験問題 (Q190-Q195):

質問 # 190
You need to list the employees in DEPARTMENT_ID 20 days in a single row, ordered by HIRE_DATE.
Examine the sample output:

Which query will provide the required output?

A. SELECT LISTAGG(last_name, '; ')
WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30;
B. SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30; ORDER BY (hire_date);
C. SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30; WITHIN GROUP ORDER BY (hire_date);
D. SELECT LISTAGG(last_name)
WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30;

正解：A

質問 # 191
View the Exhibit and examine the data in EMP and DEPT tables.

In the DEPT table, DEPTNO is the PRIMARY KEY.
In the EMP table, EMPNO is the PRIMARY KEY and DEPTNO is the FOREIGN KEY referencing the DEPTNO column in the DEPT table.
What would be the outcome of the following statements executed in the given sequence?
DROP TABLE emp;
FLASHBACK TABLE emp TO BEFORE DROP;
INSERT INTO emp VALUES (2, 'SCOTT', 10);
INSERT INTO emp VALUES (3, 'KING', 55);

A. Only the SECOND INSERT statement would succeed because all the constraints except referential integrity constraints that reference other tables are retrieved automatically after the table is flashed back.
B. Only the first INSERT statement would succeed because all constraints except the primary key constraint are automatically retrieved after a table is flashed back.
C. Both the INSERT statements would fail because the constraints are automatically retrieved when the table is flashed back.
D. Both the INSERT statements would succeed because none of the constraints on the table are automatically retrieved when the table is flashed back.

正解：A

質問 # 192
Which three statements are true about multiple-row subqueries?

A. They can contain group functions and the GROUP BYclause, but not the HAVINGclause.
B. They cannot contain a subquery within a subquery.
C. They can contain group functions and GROUP BYand HAVINGclauses.
D. They can return only one column but multiple rows.
E. They can return multiple columns as well as rows.
F. They can contain a subquery within a subquery.

正解：C、E、F

質問 # 193
You must create a table EMPLOYEES in which the values in the columns EMPLOYEES_ID and LOGIN_ID must be unique and not null. (Choose two.) Which two SQL statements would create the required table?

A. CREATE TABLE employees
(employee_id NUMBER,
login_id NUMBER,
employee_name VARCHAR2(25),
hire_date DATE,
CONSTRAINT emp_id_pk PRIMARY KEY (employee_id, login_id));
B. CREATE TABLE employees
(employee_id NUMBER,
Login_id NUMBER,
Employee_name VARCHAR2(100),
Hire_date DATE,
CONSTRAINT emp_id_uk UNIQUE (employee_id, login_id);
CONSTRAINT emp_id_nn NOT NULL (employee_id, login_id));
C. CREATE TABLE employees
(employee_id NUMBER CONSTRAINT emp_id_nn NOT NULL,
Login_id NUMBER CONSTRAINT login_id_nn NOT NULL,
Employee_name VARCHAR2(100),
Hire_date DATE,
CONSTRAINT emp_id_ukUNIQUE (employee_id, login_id));
D. CREATE TABLE employees
(employee_id NUMBER CONSTRAINT emp_id_pk PRIMARY KEY,
Login_id NUMBER UNIQUE,
Employee_name VARCHAR2(25),
Hire_date DATE);
E. CREATE TABLE employees
(employee_id NUMBER,
Login_id NUMBER,
Employee_name VARCHAR2(100),
Hire_date DATE,
CONSTRAINT emp_id_ukUNIQUE (employee_id, login_id));

正解：A、C

質問 # 194
Evaluate the following query

What is the correct output of the above query?

A. +00-300, +00-650, +00 11:12:10.123457
B. +25-00, +54-02, +00 11:12:10.123457
C. +25-00, +00-650, +00 11:12:10.123457
D. +00-300, +54-02, +00 11:12:10.123457

正解：B

質問 # 195
......

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