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Oracle 1z0-071 Exam Overview:

Certification Vendor:	Oracle
Exam Name:	Oracle Database SQL
Exam Number:	1Z0-071
Exam Price:	US$245
Certificate Validity Period:	18 months
Real Exam Qty:	63 - 78
Available Languages:	Korean, Japanese, Traditional Chinese, Spanish, Simplified Chinese, English
Passing Score:	63%
Exam Duration:	120 minutes
Related Certifications:	Oracle Database Developer Certified Associate Oracle Database Administrator Certified Associate
Exam Format:	Multiple Choice, Multiple Select
Recommended Training:	Oracle Database SQL Fundamentals Oracle Database 19c: SQL Workshop
Exam Registration:	Oracle University Registration Pearson VUE Registration
Sample Questions:	Oracle 1z0-071 Sample Questions
Exam Way:	Online proctored or Onsite at Pearson VUE test centers
Pre Condition:	No mandatory prerequisites; basic knowledge of SQL and relational databases recommended
Official Syllabus URL:	https://education.oracle.com/pexam_1Z0-071

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Oracle 1z0-071 exam, also known as the Oracle Database SQL exam, is a certification exam offered by Oracle Corporation. It is designed to test the knowledge and skills of SQL developers, database administrators, and database analysts who work with Oracle databases. Passing 1z0-071 Exam is a requirement for earning the Oracle Database SQL Certified Associate certification.

Oracle Database SQL Sample Questions (Q398-Q403):

NEW QUESTION # 398
View the Exhibit and examine the description of the EMPLOYEES table.

Evaluate the following SQL statement:
SELECT first_name, employee_id, NEXT_DAY(ADD_MONTHS(hire_date, 6), 1) "Review" FROM employees;
The query was written to retrieve the FIRST_NAME, EMPLOYEE_ID, and review date for employees. The review date is the firsts Monday after the completion of six months of the hiring. The NLS_TERRITORY parameter is set to AMERICA in the session.
Which statement is true regarding this query?

A. The query would not execute because date functions cannot be nested.
B. The query would not execute because the NEXT_DAY function accepts a string as argument.
C. The query would execute but the output would give review dates that are Sundays.
D. The query would execute to give the desired output.

Answer: C

NEW QUESTION # 399
View the Exhibit and examine the structure of ORDERS and ORDER_ITEMS tables.
ORDER__ID is the primary key in the ORDERS table. It is also the foreign key in the
ORDER_ITEMS table wherein it is created with the ON DELETE CASCADE option.

Which DELETE statement would execute successfully?

A. DELETE order_id FROM orders WHERE order_total < 1000;
B. DELETE orders o, order_items i WHERE o.order id = i.order id;
C. DELETE FROM orders WHERE (SELECT order_id FROM order_items);
D. DELETE orders WHERE order_total < 1000;

Answer: D

NEW QUESTION # 400
Examine the data in the INVOICES table:

Examine the data in the CURRENCIES table:
CURRENCY_CODE
-------------
JPY
GPB
CAD
EUR
USD
Which query returns the currencies in CURRENCIES that are not present in INVOICES?

A. SELECT * FROM currencies
MINUS
SELECT * FROM invoices;
B. SELECT * FROM currencies
WHERE NOT EXISTS (
SELECT NULL FROM invoices WHERE currency_ code = currency_ code);
C. SELECT currency_ code FROM currencies
INTERSECT
SELECT currency_ code FROM invoices;
D. SELECT currency_ code FROM currencies
MINUS
SELECT currency_ code FROM invoices;

Answer: D

Explanation:
To calculate the length of employment, you would compare the current date to the HIRE_DATE and calculate the difference in years.
A . This is the correct answer. The expression calculates the number of days between the current date (SYSDATE) and the HIRE_DATE, then divides by 365 to convert it to years, and checks if it is greater than 5.
B . SYSTIMESTAMP includes a time component including fractional seconds and time zone information, making this comparison incorrect.
C . There are typos in this option (CUARENT_DATE should be CURRENT_DATE and hire_data should be hire_date). Even with the correct function and column names, CURRENT_DATE returns the current date in the session time zone, not in years.
D . There are typos in this option (SYSNAYW should be SYSDATE). Additionally, dividing by 12 incorrectly assumes that a month is equivalent to a year.
E . This is a repetition of option D with the same issues.
F . There are typos in this option (CUNACV_DATE should be CURRENT_DATE and hire_data should be hire_date). Additionally, dividing by 12 incorrectly assumes that a month is equivalent to a year.
Reference:
Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Date Functions"

NEW QUESTION # 401
View the Exhibit and examine the structure of the ORDER_ITEMS table.

Examine the following SQL statement:
SELECT order_id, product_id, unit_price
FROM order_items
WHERE unit_price =
(SELECT MAX(unit_price)
FROM order_items
GROUP BY order_id);
You want to display the PRODUCT_ID of the product that has the highest UNIT_PRICE per ORDER_ID.
What correction should be made in the above SQL statement to achieve this?

A. Replace = with the >ANY operator
B. Remove the GROUP BY clause from the subquery and place it in the main query
C. Replace = with the IN operator
D. Replace = with the >ALL operator

Answer: C

NEW QUESTION # 402
Examine this query which executes successfully;
Select job,deptno from emp
Union all
Select job,deptno from jobs_history;
What will be the result?

A. It will return rows that are not common to both select statements.
B. It will return rows from both select statements after eliminating duplicate rows.
C. It will return rows both select statements including duplicate rows.
D. It will return rows common to both select statements.

Answer: C

Explanation:
For the provided UNION ALL query:
* Option C: It will return rows from both SELECT statements including duplicate rows.
* UNION ALL is used to combine the results of two SELECT statements and does not eliminate duplicates.
Options A, B, and D are incorrect because:
* Option A: UNION ALL does not eliminate duplicate rows, unlike UNION.
* Option B: This would be true for INTERSECT, not UNION ALL.
* Option D: This would be true for EXCEPT or MINUS, not UNION ALL.

NEW QUESTION # 403
......

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