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Oracle 1z1-071 Exam Syllabus Topics:

SectionWeightObjectives
Controlling User Access5%- Distinguish between granting privileges and roles
- Grant privileges on tables and on a view
- Differentiate system privileges from object privileges
Working with Oracle Database SQL8%- Explain the installation of Oracle Database software
- Start up and shut down a database
- Create a container database
- Describe the Oracle Database architecture
Reporting Aggregated Data Using Group Functions15%- Identify the available group functions
- Group data by using the GROUP BY clause
- Include or exclude grouped rows by using the HAVING clause
- Describe the use of group functions
Using Conversion Functions and Conditional Expressions10%- Apply the NVL, NULLIF, and COALESCE functions to data
- Use conditional IF THEN ELSE logic in a SELECT statement
- Describe implicit and explicit data type conversion
- Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions
Manipulating Data14%- Update rows in a table
- Delete rows from a table
- Control transactions
- Insert rows into a table
- Describe each data manipulation language (DML) statement
Displaying Data from Multiple Tables Using Joins15%- View data that does not meet a join condition by using outer joins
- Write SELECT statements to access data from more than one table using equijoins and non-equijoins
- Join a table to itself by using a self-join
- Cross join tables
Using Set Operators5%- Describe set operators
- Describe the order of precedence when the set operators are used
- Use a set operator to combine multiple queries into a single query
Retrieving Data Using the SQL SELECT Statement5%- Execute a basic SELECT statement
- Differentiate between SQL statements and SQL*Plus commands
- List the capabilities of SQL SELECT statements
Using Single-Row Functions to Customize Output10%- Manipulate numbers with the ROUND, TRUNC, and MOD functions
- Manipulate strings with character function in the SELECT and WHERE clauses
- Describe the differences between single-row and multiple-row functions
- Manipulate dates with the date functions
- Perform arithmetic with date data
Using DDL Statements to Create and Manage Tables14%- Review the table structure
- Drop, rename, and truncate tables
- Describe the data types that are available for columns
- Alter table definitions
- Create a simple table
- Categorize the main database objects
Using Subqueries to Solve Queries15%- Describe the types of problems that subqueries can solve
- List the types of subqueries
- Write single-row and multi-row subqueries
- Define subqueries
Restricting and Sorting Data6%- Use ampersand substitution to restrict and sort output at runtime
- Limit the rows that are retrieved by a query
- Sort the rows that are retrieved by a query
- Use DEFINE and UNDEFINE commands
Creating Other Schema Objects10%- Create and maintain indexes
- Create, maintain, and use sequences
- Create, modify, and retrieve data from a view
- Create synonyms for database objects

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Oracle Database SQL Sample Questions (Q33-Q38):

NEW QUESTION # 33
Evaluate the following query:

What would be the outcome of the above query?

Answer: C


NEW QUESTION # 34
You execute the SQL statement:
SQL> CREATE TABLE citizens
(citizen_id CHAR (10) PRIMARY KEY,
last_name VARCHAR2 (50) NOT NULL,
first_name VARCHAR2 (50),
address VARCHAR2 (100),
city VARCHAR2 (30) DEFAULT 'SEATTLE' NOT NULL,
CONSTRAINT cnames CHECK (first_name<>last_name) );
What is the outcome?

Answer: A


NEW QUESTION # 35
Examine the data in the CUST NAME column of the CUSTOMERS table:
CUST_NAME
------------------------------
Renske Ladwig
Jason Mallin
Samuel McCain
Allan MCEwen
Irene Mikkilineni
Julia Nayer
You want to display the CUST_NAME values where the last name starts with Mc or MC. Which two WHERE clauses give the required result?

Answer: A,E

Explanation:
To find customers whose last names start with "Mc" or "MC", we need to ensure our SQL query correctly identifies and compares these prefixes regardless of case variations. Let's analyze the given options:
Option B: WHERE UPPER(SUBSTR(cust_name, INSTR(cust_name, ' ') + 1)) LIKE UPPER('MC%') This clause uses UPPER to convert both the extracted substring (starting just after the first space, assuming it indicates the start of the last name) and the comparison string 'MC%' to uppercase. This ensures case-insensitive comparison. The LIKE operator is used to match any last names starting with "MC", which will correctly capture both "Mc" and "MC". This option is correct.
Option C: WHERE INITCAP(SUBSTR(cust_name, INSTR(cust_name, ' ') + 1)) LIKE 'Mc%' This clause applies INITCAP to the substring, which capitalizes the first letter of each word and makes other letters lowercase. The result is compared to 'Mc%', assuming only the last name follows the space. This approach will match last names starting with "Mc" (like "McEwen"), but not "MC". However, considering we're looking for "Mc" specifically, this clause works under the assumption that "Mc" is treated as proper capitalization for these last names. Thus, it can also be considered correct, albeit less inclusive than option B.
The other options either use incorrect syntax or apply case-sensitive matches without ensuring that both "Mc" and "MC" are captured:
Option A: Contains syntax errors (unmatched quotes and wrong use of IN).
Option D: Uses case-sensitive match without combining both "Mc" and "MC".
Option E: Only matches "Mc", which is too specific.


NEW QUESTION # 36
View the Exhibit and examine the description of the EMPLOYEEStable.

You want to calculate the total renumeration for each employee. Total renumeration is the sum of the annual salary and the percentage commission earned for a year. Only a few employees earn commission.
Which SQL statement would you execute to get the desired output?
SELECT first_name, salary, salary*12+(salary*NVL2 (commission_pct,

Answer: B


NEW QUESTION # 37
Examine the structure of the EMPLOYEES table. (Choose two.)

You must display the maximum and minimum salaries of employees hired 1 year ago.
Which two statements would provide the correct output?

Answer: B,C


NEW QUESTION # 38
......

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