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Oracle 1z1-071 (Oracle Database SQL) certification exam is a professional certification exam that verifies an individual's knowledge and skills in SQL programming language and Oracle database management systems. Passing 1z0-071 exam can help individuals enhance their career opportunities and advance their knowledge and skills in database management and application development.
Oracle 1z1-071 (Oracle Database SQL) Certification Exam is a multiple-choice exam that consists of 73 questions. Candidates are given 100 minutes to complete the exam and must score at least 63% to pass. 1z0-071 Exam is available in English and Japanese and can be taken at authorized testing centers worldwide. 1z0-071 exam fee varies depending on the country and region.
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The Oracle 1z0-071 exam covers a range of topics, including SQL fundamentals, data retrieval using SELECT statements, data manipulation, and database objects. It also includes advanced SQL topics, such as subqueries, set operators, and data aggregation. 1z0-071 Exam is intended for professionals who have a good understanding of SQL and have experience working with databases.
Oracle Database SQL Sample Questions (Q23-Q28):
NEW QUESTION # 23
Examine the description of the PRODUCTStable:

Which three queries use valid expressions? (Choose three.)
- A. discount FROM products;
SELECT product_id, unit_price, 5 "Discount", unit_price + surcharge - discount - B. SELECT product_id, (unit_price * 0.15 / (4.75 + 552.25)) FROM products;
- C. SELECT product_id, (expiry_date - delivery_date) * 2 FROM products;
- D. SELECT product_id, expiry_date * 2 FROM products;
- E. FROM products;
SELECT product_id, unit_price, unit_price + surcharge FROM products; - F. SELECT product_id, unit_price | | 5 "Discount", unit_price + surcharge -
Answer: A,D,E
NEW QUESTION # 24
You want to display the date for the first Monday of the next month and issue the following command:
SQL>SELECT TO_CHAR(NEXT_DAY(LAST_DAY(SYSDATE), 'MON'),
'dd "is the first Monday for" fmmonth rrrr')
FROM DUAL;
What is the outcome?
- A. In generates an error because TO_CHARshould be replaced with TO_DATE.
- B. It executes successfully and returns the correct result.
- C. It executes successfully but does not return the correct result.
- D. In generates an error because rrrrshould be replaced by rrin the format string.
- E. In generates an error because fmand double quotation marks should not be used in the format string.
Answer: B
NEW QUESTION # 25
View the Exhibit and examine the structure of the PRODUCT_INFORMATION table.

You want to see the product names and the date of expiration of warranty for all the products, if the product is purchased today. The products that have no warranty should be displayed at the top and the products with maximum warranty period should be displayed at the bottom.
Which SQL statement would you execute to fulfill this requirement?
- A. SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date" FROM product_information ORDER BY SYSDATE+warranty_period
- B. SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date" FROM product_information ORDER BY SYSDATE-warranty_period
- C. SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date" FROM product_information WHERE warranty_period > SYSDATE
- D. SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date" FROM product_information ORDER BY SYSDATE
Answer: A
NEW QUESTION # 26
View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables.

You executed the following query to display PRODUCT_NAME and the number of times the product has been ordered:
SQL>SELECT p.product_name, i.item_cnt
FROM (SELECT product_id, COUNT (*) item_cnt
FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p
ON i.product_id = p.product_id;
What would happen when the above statement is executed?
- A. The statement would not execute because the GROUP BY clause cannot be used in the inline.
- B. The statement would not execute because inline views and outer joins cannot be used together.
- C. The statement would execute successfully to produce the required output.
- D. The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.
Answer: C
NEW QUESTION # 27
Examine the data in the CUST_NAMEcolumn of the CUSTOMERStable.

You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:

Which two queries give the required output? (Choose two.)
- A. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, '
'), '*') "CUST NAME"
FROM customers
WHERE INSTR(cust_name, ' ',1,-2)<>0; - B. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, '
'), '*') "CUST NAME"
FROM customers
WHERE INSTR(cust_name, ' ',1,2)<>0; - C. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',1,2)<>0;
- D. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',-1,2)<>0;
Answer: C,D
NEW QUESTION # 28
......
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