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| Section | Objectives |
|---|---|
| Topic 1: App Lifecycle and Deployment Concepts | - Understanding app structure
|
| Topic 2: App Logic and Data Handling | - Data management in apps
|
| Topic 3: User Interface Development | - Building iOS interfaces
|
| Topic 4: Introduction to App Development with Swift | - Swift programming fundamentals
|
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NEW QUESTION # 24
Review the code snippet.
What will print after the final line of code is executed?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objective on variable scope and shadowing .
The code first declares:
let even = 2
This creates a constant named even in the outer scope with the value 2.
Inside the for loop, the code declares another constant with the same name:
let even = num * 2
This inner even exists only inside the loop body. It shadows the outer even, which means that within the loop, the name even refers to the loop's local constant, not the original one. However, that inner constant goes out of scope at the end of each loop iteration.
After the loop finishes, the inner even no longer exists. So when the final line runs:
print(even)
Swift uses the original outer constant, which is still 2.
So the output is:
2
This question tests two important Swift concepts:
* Scope : where a variable or constant can be accessed
* Shadowing : when a local declaration temporarily hides another declaration with the same name Therefore, the correct answer is 2 .
NEW QUESTION # 25
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
Answer: C,D
Explanation:
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
NEW QUESTION # 26
Review the code snippet.
What is the output from each print statement?
Answer:
Explanation:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
NEW QUESTION # 27
Review the code snippet and then predict the output.
Answer: D
Explanation:
This question belongs to Swift Programming Language , especially the domains covering control flow , loops , logical operators , and guard . The loop runs through 0.. < max, and since max = 101, the values of num are 0 through 100. Inside the loop, the guard statement keeps only values that satisfy both conditions:
* num % 5 == 0 # the number must be divisible by 5
* num % 2 != 0 # the number must be odd
So the code counts numbers from 0 to 100 that are odd multiples of 5 . Those values are:
5, 15, 25, 35, 45, 55, 65, 75, 85, 95
That gives a total of 10 numbers. Therefore count becomes 10, and the printed output is:
Total count: 10
The key Swift concept here is that guard ... else { continue } skips any loop iteration that does not meet the required condition. Only matching values reach count += 1. This is a standard use of guard for early exit and of the remainder operator % for divisibility checks. Therefore, the correct answer is B .
NEW QUESTION # 28
Complete the code by selecting the correct option from each drop-down list to create the following screen.
Note: You will receive partial credit for each correct answer.
Answer:
Explanation:
NEW QUESTION # 29
......
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