NSE7_FSN_AR-7.6資料勉強、NSE7_FSN_AR-7.6資格勉強

NSE7_FSN_AR-7.6の実際の試験をFortinet購入し、スコアを提供したお客様から得られたデータは、NSE7_FSN_AR-7.6試験問題の高い合格率が98%〜100%であることを示しています。 これは、市場で見つけて比較するのが難しいです。 そして、JPTestKing優秀なクライアントからの数多くの熱烈なフィードバックは、NSE7_FSN_AR-7.6の勉強の急流だけでなく、オンラインの誠実で役立つ24時間のカスタマーサービスにも高い評価を与えています。 これらはすべて、私たちがこのキャリアで最高のベンダーであり、NSE7_FSN_AR-7.6試験の最初の試行で成功を収める権限があることをFortinet NSE 7 - Secure Networking 7.6 Architect証明しています。

Fortinet NSE7_FSN_AR-7.6 Exam Syllabus Topics:

SectionObjectives
Enterprise Firewall- Troubleshooting
- High availability
- Centralized management and analytics
- VPN technologies
- Authentication and identity
- Advanced firewall deployment
- Routing and advanced networking
- Security Fabric integration
SD-WAN- SD-WAN architecture
- SD-WAN routing
- Application steering
- Overlay VPN
- Deployment and troubleshooting
- Performance SLA

>> NSE7_FSN_AR-7.6資料勉強 <<

Fortinet NSE7_FSN_AR-7.6資格勉強 & NSE7_FSN_AR-7.6試験過去問

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Fortinet NSE 7 - Secure Networking 7.6 Architect 認定 NSE7_FSN_AR-7.6 試験問題 (Q164-Q169):

質問 # 164
What is the correct order of the IKEv2 request-and-response protocol?

正解:C

解説:
The Internet Key Exchange version 2 (IKEv2) protocol simplifies the negotiation process compared to IKEv1.
It is defined by a specific sequence of message exchanges to establish a secure IPsec tunnel.
The correct chronological order of the IKEv2 exchanges is:
IKE_SA_INIT (Initial Exchange):
This is the first exchange. It negotiates the security parameters for the IKE Security Association (IKE SA), sends nonces, and performs the Diffie-Hellman key exchange. At the end of this exchange, the communication is encrypted, but the peers are not yet authenticated.
IKE_AUTH (Authentication Exchange):
This is the second exchange. It authenticates the previous messages, exchanges identities and certificates (if used), and establishes the first Child SA (the actual IPsec Security Association used for data traffic).
CREATE_CHILD_SA (Subsequent Exchanges):
This exchange occurs after the IKE SA and the initial Child SA are established. It is used to create additional Child SAs (for different traffic selectors) or to perform re-keying for the IKE SA or existing Child SAs.
Why other options are incorrect:
A & B: Incorrect because CREATE_CHILD_SA cannot happen before the SA is initialized (IKE_SA_INIT) and authenticated (IKE_AUTH).
D: Incorrect because IKE_AUTH cannot occur before IKE_SA_INIT.
Therefore, the protocol flow is IKE_SA_INIT $\rightarrow$ IKE_AUTH $\rightarrow$ CREATE_CHILD_SA.


質問 # 165
Refer to the exhibit, which shows the output of diagnose sys session stat.

Which statement about the output shown in the exhibit is correct?

正解:C

解説:
The correct answer is D.
The exhibit shows:
session_count=591
clash=162
memory_tension_drop=0
TCP sessions:
166 in NONE state
1 in ESTABLISHED state
3 in SYN_SENT state
2 in TIME_WAIT state
The study guide explains the TCP protocol states and states explicitly:
"When a session is closed by both the sender and receiver, FortiGate keeps that session in the session table for a few seconds, to allow for any out-of-order packets that might arrive after the FIN/ACK packet. This is the state value 5." In diagnose sys session stat, the exhibit shows 2 in TIME_WAIT state. Since TIME_WAIT = state value 5, those are the sessions being kept briefly for possible out-of-order packets. That makes D correct.
Why the other options are wrong:
A is wrong because session_count=591 is the total number of sessions, while the TCP sessions shown add up to only 172 (166 + 1 + 3 + 2). So not all sessions in the table are TCP sessions.
B is wrong because the study guide says the number of sessions deleted because of low free memory is shown by memory_tension_drop, and in the exhibit it is 0, not 162.
C is wrong because the study guide defines ephemeral/open TCP sessions as those not fully established, but the exhibit does not say all 166 in NONE state are specifically "waiting to complete the three-way handshake." The clearest directly supported statement from the displayed states is the 2 TIME_WAIT sessions retained for out-of-order packets.
So the verified answer is: D.


質問 # 166
Refer to the exhibit.

If the default settings are m place, what can you conclude about the conserve mode shown in the exhibit?

正解:A

解説:
The exhibit shows:
* memory conserve mode: on
* memory used: 2706 MB 89% of total RAM
* memory used threshold red: 2675 MB 88% of total RAM
* memory used + freeable threshold extreme: 2887 MB 95% of total RAM
The study guide states that the default thresholds are:
* Extreme = 95%
* Red = 88%
* Green = 82%
So this FortiGate is in conserve mode because memory usage is 89% , which is above the red threshold (88%) , but it has not yet reached the extreme threshold (95%) .
The study guide then explains exactly what happens during conserve mode:
"For traffic that requires proxy-based inspection (and if memory usage has not exceeded the extreme threshold):
config system global
set av-failopen [off | pass | one-shot]
pass (default): All new sessions pass without inspection"
It also says:
"The av-failopen setting also applies to flow-based antivirus inspection." And the same page adds:
"If memory usage exceeds the extreme threshold, all new sessions that require inspection (flow-based or proxy-based) are blocked." Therefore, with default settings and with memory usage below the extreme threshold , FortiGate is allowing new sessions that require inspection, but bypassing inspection . That matches C .
Why the other options are wrong:
* A is wrong because the default behavior is not to block proxy-based inspected sessions; the default is pass , meaning they pass without inspection
* B is wrong because if memory rises another 6% , it reaches 95% , which is the extreme threshold . At that point, the study guide says all new sessions that require inspection are blocked
* D is wrong because FortiGate blocks all new inspected sessions only when memory usage exceeds the extreme threshold , and the exhibit shows it is currently at 89% , not 95%


質問 # 167
Refer to the exhibits,

which show the configuration on FortiGate and partial session information for internet traffic from a user on the internal network. If the priority on route ID 2 were changed from 10 to 0, what would happen to traffic matching that user session? (Choose one answer)

正解:C

解説:
The correct answer is A . This behavior is dictated by the configuration command set snat-route-change enable shown in Exhibit 1 under config system global.
* Routing Change: By changing the priority of route ID 2 from 10 to 0, it becomes lower than route ID 1 (priority 5). In FortiOS, a lower priority value indicates a more preferred route. Consequently, the active route for the destination changes from port1 to port2 .
* SNAT Implication: The existing session (shown in Exhibit 2) is using Source NAT (SNAT) with the IP address associated with port1 (10.200.1.1). If the traffic were simply switched to port2 , the source IP would be incorrect for that interface and the return traffic would likely fail or be dropped.
* snat-route-change enable: This specific setting instructs the FortiGate on how to handle established SNAT sessions when a routing change occurs that alters the preferred outgoing interface. When enabled, if a route change forces an SNAT session to a new interface, FortiGate flushes (deletes) the session from the session table. This is necessary because a live TCP session cannot survive a change in its source IP address. The client must initiate a new session, which will then be created using the new correct route (port2) and the corresponding new SNAT IP.
If this setting were disabled, the session would likely remain " sticky " to the original interface (port1) until it closed, provided the route still existed. However, the explicit configuration forces the deletion.


質問 # 168
Refer to the exhibit, which shows a partial output of the real-time LDAP debug.

What two actions can the administrator take to resolve this issue? (Choose two.)

正解:B、D


質問 # 169
......

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