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| Section | Objectives |
|---|---|
| Topic 1: User Interface Development | - Building iOS interfaces
|
| Topic 2: App Logic and Data Handling | - Data management in apps
|
| Topic 3: App Lifecycle and Deployment Concepts | - Understanding app structure
|
| Topic 4: Introduction to App Development with Swift | - Swift programming fundamentals
|
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質問 # 39
Review the code snippet.
The " faces " dictionary contains emojis and their descriptions.
Which code will create an array named " emo)is " that will copy all the emojis from the " faces " dictionary?
正解：A
解説：
This question belongs to Swift Programming Language , specifically the objective on managing data using collection types , including dictionaries and arrays . In the dictionary shown, the emojis are the keys and the text descriptions are the values . Swift provides a keys property on dictionaries that returns a collection containing all dictionary keys. To convert that keys collection into an array, you use the Array(...) initializer.
Therefore, the correct code is let emojis = Array(faces.keys). Apple documents both the Dictionary.keys property and the Array type used to store a sequence of values of the same type.
Option B is incorrect because faces.values would return the descriptions like " grinning " , " thinking " , and " happy " , not the emoji keys. Options A and C are incorrect because List is a SwiftUI view type, not the correct collection type for creating an array from dictionary contents. Also, the dictionary interface uses properties like .keys and .values, not method calls like .keys() or .values(). Apple's dictionary documentation makes clear that keys is a property returning a collection of the dictionary's keys.
質問 # 40
You have a set of Views within a ZStack that produce the screen below:
Arrange the lines of code that will make up the ZSlack so that the View appears as shown.
正解：
解説：
Explanation:
This question belongs to View Building with SwiftUI , specifically stacking views and applying modifiers. A ZStack layers views from back to front, so the first item becomes the background and later items appear on top. To match the screenshot, the black background must be the back layer, so Color.black goes first. The large white circle sits above that, so Circle() followed by .foregroundStyle(.white) comes next. Finally, the red heart image sits on top of the circle, so Image(systemName: " heart " ).resizable() followed by .
foregroundStyle(.red).frame(width: 200, height: 200) must be last. SwiftUI's Image.resizable() allows the symbol image to scale to the frame you apply, and foregroundStyle sets the visible color styling for the shape and symbol.
So the intended structure is:
ZStack {
Color.black
Circle()
.foregroundStyle(.white)
Image(systemName: " heart " ).resizable()
.foregroundStyle(.red)
.frame(width: 200, height: 200)
}
This produces a black background, a white circular shape, and a centered red heart on top, exactly as shown.
質問 # 41
Review the code snippet.
Which statement completes the code snippet so that:
* The lastReleaseDate remains the same when nextApplePhone.releaseDate is nil.
* The lastReleaseDate updates to the nextApplePhone.releaseDate when nextApplePhone.releaseDate is NOT nil.
正解：B
解説：
This question is from Swift Programming Language , especially the domains for Optional types , safe and unsafe unwrapping , and control flow . The code uses the ternary conditional operator :
nextApplePhone.releaseDate != nil ? _____
In Swift, the ternary operator follows this structure:
condition ? valueIfTrue : valueIfFalse
So if nextApplePhone.releaseDate != nil is true, the expression must return the new release date. If it is false, it must keep lastReleaseDate unchanged. That means the missing part must be:
nextApplePhone.releaseDate! : lastReleaseDate
which is option D .
This works because nextApplePhone.releaseDate is declared as String?, so it is an optional. Once the condition confirms it is not nil, the code force-unwraps it with ! to access the underlying String value. If the optional is nil, the expression returns lastReleaseDate instead. Apple's Swift documentation describes the ternary conditional operator as a shortcut for choosing one of two expressions based on a condition, and it explains that force unwrapping with ! accesses an optional's wrapped value when you know it is not nil.
The other options are incorrect because they reverse the true/false logic, omit the needed unwrap, or contain invalid identifiers. Therefore, the correct completion is D .
質問 # 42
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
正解：B、C
解説：
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
質問 # 43
Which code correctly creates a size 300 rectangular Image View with rounded corners that displays the entire image, regardless of size?
正解：C
解説：
This question belongs to View Building with SwiftUI , specifically the objective on positioning and laying out a single SwiftUI view with standard views and modifiers.
The correct answer is D because it uses the right combination of SwiftUI image modifiers for all three requirements:
* the image is made resizable with .resizable()
* it is given rounded corners with .clipShape(RoundedRectangle(cornerRadius: 50))
* it displays the entire image with .aspectRatio(contentMode: .fit)
* it is sized with .frame(width: 300)
The key part is .aspectRatio(contentMode: .fit) . In SwiftUI, .fit scales the image so the whole image remains visible inside the available frame. That matches the requirement "displays the entire image, regardless of size." By contrast, .fill may crop part of the image, so options using .fill do not satisfy the requirement.
Why the others are wrong:
* Option A uses .fill, so the full image may not remain visible.
* Option B uses invalid modifiers such as .sizablc() and .size(width: 300), and also uses Rectangle (cornerRadius: 50), which is not the correct rounded-rectangle shape syntax.
* Option C also uses invalid syntax and .fill, which can crop the image.
* Option D uses valid SwiftUI syntax and the correct content mode.
So the correct choice is D , because it is the only option that correctly creates a 300-width image with rounded corners while ensuring the entire image is shown.
質問 # 44
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