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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 2
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 3
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q135-Q140):

NEW QUESTION # 135
A developer needs to debug a Node.js web server because a runtime error keeps occurring at one of the endpoints.
The developer wants to test the endpoint on a local machine and make the request against a local server to look at the behavior. In the source code, the server.js file will start the server. The developer wants to debug the Node.js server only using the terminal.
Which command can the developer use to open the CLI debugger in their current terminal window?
(With corrected typing errors: node_inspect → node inspect, node_start_inspect → node start inspect.)

Answer: D

Explanation:
Node.js includes a built-in command-line (CLI) debugger. To use it directly in the terminal, the standard command is:
node inspect server.js
This:
Starts server.js under the Node.js inspector.
Opens the CLI debugger right in the terminal window where you ran the command.
Lets you interactively:
Step through code
Set breakpoints
Inspect variables
Continue execution, etc.
Why B is correct:
Option B (corrected to node inspect server.js) is exactly the standard Node.js command to run a script under the CLI debugger in the current terminal.
It does not rely on any external GUI tools.
You stay entirely in the terminal to debug.
Why the other options are incorrect:
A . node start inspect server.js
There is no start subcommand like this in standard Node.js CLI.
This is not a valid Node.js debugging command.
C . node server.js --inspect
This starts Node.js with the Inspector protocol enabled and is typically used to connect external tools like Chrome DevTools or VS Code.
It does not open the CLI debugger in the current terminal. Instead, it opens a debugging port that other tools attach to.
The question specifically says "only using the terminal" and "open the CLI debugger in their current terminal window", which points to node inspect, not --inspect.
D . node -i server.js
-i starts Node in interactive REPL mode, optionally after running a script.
This is for an interactive shell, not the Node debugger.
It does not provide breakpoint/step/next/continue debugging features like the CLI debugger.
Therefore, the only option that opens the Node.js CLI debugger in the current terminal is:
Answe r: B
JavaScript / Node.js knowledge / Study Guide references (concept names only, no links):
Node.js CLI debugger: node inspect <script>
Node.js inspector protocol: node --inspect
Difference between CLI debugger and DevTools-based debugging
Node.js command-line options and subcommands


NEW QUESTION # 136
Refer to the code snippet:
01 let array = [1, 2, 3, 4, 4, 5, 4, 4];
02 for (let i = 0; i < array.length; i++) {
03 if (array[i] === 4) {
04 array.splice(i, 1);
05 i--;
06 }
07 }
What is the value of array after the code executes?

Answer: D

Explanation:
Comprehensive and Detailed
The loop removes every 4:
Start: [1, 2, 3, 4, 4, 5, 4, 4]
i=0 → 1 (no change)
i=1 → 2 (no change)
i=2 → 3 (no change)
i=3 → 4 → splice removes index 3 → [1,2,3,4,5,4,4], then i-- → 2
Next loop, i=3 → 4 again → splice → [1,2,3,5,4,4], i-- → 2
i=3 → 5 (no change)
i=4 → 4 → splice → [1,2,3,5,4], i-- → 3
i=4 → 4 → splice → [1,2,3,5], i-- → 3
Next i=4, array.length is 4 → loop ends.
All 4s removed, final array: [1, 2, 3, 5].
________________________________________


NEW QUESTION # 137
A developer writes the code below to return a message to a user attempting to register a new username. If the username is available, a variable named msg is declared and assigned a value on line 03.
```javascript
function getAvailabilityMessage(item) {
if (getAvailability(item)) {
var msg = "Username available";
return msg;
}
}

Answer: D


NEW QUESTION # 138
A developer wants to use a module called DatePrettyPrint.
This module exports one default function called printDate().
How can the developer import and use printDate()?

Answer: D

Explanation:
ES Modules follow these rules:
Default exports are imported using:
import anyName from 'module'
The name chosen in the import does NOT need to match the exported name.
If a module exports:
export default function printDate() {}
then consuming code should import the function directly:
import printDate from '/path/DatePrettyPrint.js';
To execute it:
printDate();
Option analysis:
A incorrect:
import DatePrettyPrint() is invalid syntax.
Also calling printDate() without importing it is incorrect.
B incorrect:
A default export imported as DatePrettyPrint gives the function itself, not an object containing methods.
You cannot call DatePrettyPrint.printDate().
C incorrect:
Imports printDate but then calls DatePrettyPrint.printDate(), which does not exist.
D correct:
Correct import of a default-exported function.
Correct direct invocation.
JavaScript Knowledge Reference (text-only)
Default export → imported without braces.
Importing default functions gives a callable function, not an object.
Correct syntax: import identifier from "module".


NEW QUESTION # 139
A developer is asked to fix some bugs reported by users. To do that, the developer adds a breakpoint for debugging.
01 function Car(maxSpeed, color) {
02 this.maxSpeed = maxSpeed;
03 this.color = color;
04 }
05 let carSpeed = document.getElementById('carSpeed');
06 debugger;
07 let fourWheels = new Car(carSpeed.value, 'red');
When the code execution stops at the breakpoint on line 06, which two types of information are available in the browser console?

Answer: B,D

Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
When execution hits the debugger; statement on line 06, JavaScript execution pauses at that point. Most modern browsers (for example, using DevTools) allow you to inspect the current scope, DOM, and various browser APIs in the console.
Let's look at what is available precisely at line 06.
Current code state at the breakpoint:
Lines 01-04 define the Car constructor function.
Line 05 executes:
let carSpeed = document.getElementById('carSpeed');
So at line 06:
carSpeed is a variable containing a reference to a DOM element (the element with id "carSpeed").
Line 07 has not executed yet:
let fourWheels = new Car(carSpeed.value, 'red');
So fourWheels has not been created and is not accessible yet (it is in the temporal dead zone for the let declaration).
Now check each option:
Option A:
"A variable displaying the number of instances created for the Car object" This code does not implement any mechanism to count instances of Car.
There is no static property, global counter, or similar variable tracking the number of Car instances.
At line 06, no instance of Car has even been created yet (new Car(...) is on line 07, which has not run).
Therefore, there is no such variable by default in JavaScript or DevTools.
This option is not available.
Option B:
"The information stored in the window.localStorage property"
At a breakpoint, the console is fully usable to inspect global objects.
window.localStorage is always accessible from the console (assuming standard browser context).
You can type:
window.localStorage
and inspect key/value pairs stored there.
This is independent of the current function or breakpoint line; localStorage is part of the Web Storage API on the window object.
So this information is indeed available in the console at line 06.
Option C:
"The values of the carSpeed and fourWheels variables"
At line 06:
carSpeed has been declared and assigned (line 05), so it is available, and its value (a DOM element) can be inspected.
fourWheels is declared on line 07 with let and has not yet been executed.
Variables declared with let and const are in a temporal dead zone before their declaration line completes.
At line 06, fourWheels is not yet initialized, and attempting to access it would result in a ReferenceError.
Thus, you can inspect carSpeed but not fourWheels. The option explicitly says "the values of the carSpeed and fourWheels variables", which is not correct at this breakpoint, because fourWheels is not available yet.
Option D:
"The style, event listeners and other attributes applied to the carSpeed DOM element" carSpeed holds a reference to a DOM element (document.getElementById('carSpeed')).
In DevTools, you can inspect this element in several ways:
Typing carSpeed in the console.
Inspecting it in the Elements panel.
From the console or Elements panel, you can view:
Its style (inline styles and computed styles).
Event listeners attached to it (using event listener viewer in DevTools).
Other attributes (id, class, etc.).
All of this is accessible at the point where execution is paused.
Therefore, this information is available at the breakpoint.
Conclusion:
B is available (global window.localStorage).
D is available (full inspection of the carSpeed DOM element).
A is not present in this code or environment.
C is partially wrong (only carSpeed exists; fourWheels does not yet).
So the two correct answers are:
Reference of JavaScript knowledge documents or Study Guide (concept names only):
debugger statement and pausing execution
JavaScript execution context and scope at a breakpoint
let declarations and temporal dead zone
Browser DevTools console and inspection of variables
DOM access via document.getElementById and inspection of elements
Web Storage API: window.localStorage


NEW QUESTION # 140
......

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