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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and use sequences - Create and maintain indexes
Relational Database Concepts	10%	- ERD and SQL statement mapping - Theoretical and physical aspects of relational databases - Relationship between database and SQL
Using Single-Row Functions to Customize Output	20%	- Character, number, and date functions - Nested functions usage
Working with Time Zones and Date/Time Data		- TIMESTAMP, INTERVAL data types - Time zone conversion functions
Restricting and Sorting Data	15%	- Substitution variables, DEFINE and VERIFY commands - ORDER BY clause and sorting rules - WHERE clause and filtering conditions - Operator precedence
Manipulating Data and Managing Transactions		- Multi-table inserts - INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT
Using Subqueries to Solve Queries		- Single-row and multi-row subqueries - Correlated subqueries for update/delete
Managing Views		- Create, modify and drop views - Updatable and read-only views
Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Using Data Dictionary Views		- Retrieve metadata and object information
Retrieving Data Using SQL SELECT Statement	20%	- Arithmetic operations and NULL handling - SELECT statement syntax and usage - Column aliases, concatenation, literals and DISTINCT
Aggregating Data Using Group Functions	10%	- GROUP BY and HAVING clauses - Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions
Controlling User Access		- System and object privileges - Roles, granting and revoking privileges
Managing Tables and Constraints		- Data types, creating/altering/dropping tables - Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null
Conversion Functions and Conditional Expressions	10%	- NVL, NULLIF, COALESCE and CASE expressions - TO_CHAR, TO_NUMBER, TO_DATE functions - Implicit and explicit data type conversion
Displaying Data from Multiple Tables	15%	- Self-joins and outer joins - Cartesian products - Equijoins and non-equijoins

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Oracle Database SQL Sample Questions (Q412-Q417):

NEW QUESTION # 412
Which two join conditions in a from clause are non-equijoins?

A. table1 join table2 using (column1, column2)
B. table1 join table2 on (table1.column between table2.column] and table2.column2)
C. table1 join table2 ON (table1.column >= table2.column)
D. table1 natural JOIN table2
E. tablet join table2 ON (table1.column = table2.column) where table2.column LIKE 'A'

Answer: B,C

Explanation:
Equijoins are joins that use the equality operator (=) to match rows. Non-equijoins are joins that use operators other than the equality operator.
A). False. This condition is an equijoin as it uses the equality operator (=).
B). True. This join condition uses the BETWEEN operator, which is not based on equality.
C). False. A natural join is a type of equijoin where the join is made on all columns with the same names in both tables.
D). False. USING clause is used to specify an equijoin on one or more columns.
E). True. This join condition uses the greater than or equal to (>=) operator, making it a non-equijoin.

NEW QUESTION # 413
The BOOKS_TRANSACTIONStable exists in your database.
SQL>SELECT * FROM books_transactions ORDER BY 3;
What is the outcome on execution?

A. Rows are displayed sorted in ascending order of the values in the third column in the table.
B. Rows are displayed in the order that they are stored in the table only for the first three rows.
C. Rows are displayed in the order that they are stored in the table only for the three rows with the lowest values in the key column.
D. The execution fails unless the numeral 3 in the ORDER BYclause is replaced by a column name.

Answer: A

NEW QUESTION # 414
See the Exhibit and examine the structure of the PROMOTIONS table:

Using the PROMOTIONS table,
you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:

What would be the outcome?

A. It generates an error because CASE cannot be used with group functions.
B. It generates an error because multiple conditions cannot be specified for the WHEN clause.
C. It executes successfully and gives the required result.
D. It generates an error because NULL cannot be specified as a return value.

Answer: C

Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END

NEW QUESTION # 415
Which three statements are true regarding subqueries? (Choose three.)

A. Logical operators, such as AND, OR and NOT, cannot be used in the WHERE clause of a subquery.
B. A subquery can be placed in a WHERE clause, a GROUP BY clause, or a HAVING clause.
C. A subquery can be used in the FROM clause of a SELECT statement.
D. The ORDER BY Clause can be used in a subquery.
E. If a subquery returns NULL, the main query may still return rows.

Answer: B,C,D

NEW QUESTION # 416
Which two statements are true about the DUAL table?

A. It can be used to display only constants or pseudo columns.
B. It can be accessed only by the SYS user.
C. It consists of a single row and single column of VARCHAR2 data type.
D. It can display multiple rows and columns.
E. It can be accessed by any user who has the SELECT privilege in any schema
F. It can display multiple rows but only a single column.

Answer: D,E

NEW QUESTION # 417
......

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