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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Using Set Operators	5%	- Use a set operator to combine multiple queries into a single query - Describe set operators - Describe the order of precedence when the set operators are used
Working with Oracle Database SQL	8%	- Create a container database - Start up and shut down a database - Describe the Oracle Database architecture - Explain the installation of Oracle Database software
Creating Other Schema Objects	10%	- Create and maintain indexes - Create, modify, and retrieve data from a view - Create, maintain, and use sequences - Create synonyms for database objects
Controlling User Access	5%	- Grant privileges on tables and on a view - Differentiate system privileges from object privileges - Distinguish between granting privileges and roles
Restricting and Sorting Data	6%	- Use DEFINE and UNDEFINE commands - Use ampersand substitution to restrict and sort output at runtime - Sort the rows that are retrieved by a query - Limit the rows that are retrieved by a query
Using Conversion Functions and Conditional Expressions	10%	- Describe implicit and explicit data type conversion - Apply the NVL, NULLIF, and COALESCE functions to data - Use conditional IF THEN ELSE logic in a SELECT statement - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions
Retrieving Data Using the SQL SELECT Statement	5%	- Execute a basic SELECT statement - List the capabilities of SQL SELECT statements - Differentiate between SQL statements and SQL*Plus commands
Reporting Aggregated Data Using Group Functions	15%	- Identify the available group functions - Include or exclude grouped rows by using the HAVING clause - Describe the use of group functions - Group data by using the GROUP BY clause
Using DDL Statements to Create and Manage Tables	14%	- Categorize the main database objects - Alter table definitions - Describe the data types that are available for columns - Review the table structure - Create a simple table - Drop, rename, and truncate tables
Manipulating Data	14%	- Delete rows from a table - Insert rows into a table - Describe each data manipulation language (DML) statement - Control transactions - Update rows in a table
Using Subqueries to Solve Queries	15%	- List the types of subqueries - Define subqueries - Write single-row and multi-row subqueries - Describe the types of problems that subqueries can solve
Using Single-Row Functions to Customize Output	10%	- Manipulate numbers with the ROUND, TRUNC, and MOD functions - Describe the differences between single-row and multiple-row functions - Manipulate strings with character function in the SELECT and WHERE clauses - Perform arithmetic with date data - Manipulate dates with the date functions
Displaying Data from Multiple Tables Using Joins	15%	- Join a table to itself by using a self-join - View data that does not meet a join condition by using outer joins - Cross join tables - Write SELECT statements to access data from more than one table using equijoins and non-equijoins

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Oracle Database SQL Sample Questions (Q134-Q139):

NEW QUESTION # 134
View the exhibit and examine the structure of the EMPLOYEES table.

You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?

A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id and AND e.manager_id = 100
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id = 100;
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id = 100;
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id = 100;

Answer: B

NEW QUESTION # 135
Which two statements are true regarding the UNION ALL operators?

A. The names of columns selected in each SELECT statement must be identical.
B. Duplicates are eliminated automatically by the UNION ALL operator
C. The number of columns selected in each SELECT statement must be identical
D. The output is sorted by the UNION ALL operator.
E. NULLS are not ignored during duplicate checking.

Answer: C,E

NEW QUESTION # 136
Examine the description of the CUSTOMERStable:

Which two SELECTstatements will return these results (Choose two.):

A. SELECT customer_name FROM customers WHERE customer_name = `*Ma*';
B. SELECT customer_name FROM customers WHERE customer_name LIKE `Ma%';
C. SELECT customer_name FROM customers WHERE customer_name LIKE `Ma*';
D. SELECT customer_name FROM customers WHERE customer_name LIKE `%a%';
E. SELECT customer_name FROM customers WHERE UPPER (customer_name) LIKE `MA%';
F. SELECT customer_name FROM customers WHERE UPPER (customer_name) LIKE `MA*';
G. SELECT customer_name FROM customers WHERE customer_name LIKE `*Ma*';

Answer: E,F

Explanation:
You can use the UPPER function to perform a case-insensitive match, as in this condition:
UPPER(last_name) LIKE 'SM%'
https://docs.oracle.com/cd/B12037_01/server.101/b10759/conditions016.htm

NEW QUESTION # 137
You execute this query:
SELECT TO CHAR (NEXT_DAY(LAST_DAY(SYSDATE),'MON' ),' dd"Monday for" fmMonth rrr') FROM DUAL; What is the result?

A. It returns the date for the first Monday of the next month.
B. It executes successfully but does not return any result.
C. It generates an error.
D. It returns the date for the last Monday of the current month.

Answer: A

NEW QUESTION # 138
Examine the structure of the MEMBERS table:

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC;
What would be the result execution? (Choose the best answer.)

A. It displays all cities in descending order, within which the last names are further sorted in descending order.
B. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
C. It fails because a column alias cannot be used in the ORDER BY clause.
D. It displays all cities in ascending order, within which the last names are further sorted in descending order.

Answer: D

NEW QUESTION # 139
......

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