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| Section | Weight | Objectives |
|---|---|---|
| SwiftUI Basics | 25% | - Views and controls
|
| Swift Programming Fundamentals | 30% | - Control flow
|
| App Design and Best Practices | 15% | - Code organization
|
| Development Environment | 15% | - Xcode interface and tools
|
| Data Handling and Logic | 15% | - Error handling
|
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NEW QUESTION # 21
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
Answer: B,E
Explanation:
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
NEW QUESTION # 22
Which code correctly creates a size 300 rectangular Image View with rounded corners that displays the entire image, regardless of size?




Answer: D
Explanation:
This question belongs to View Building with SwiftUI , specifically the objective on positioning and laying out a single SwiftUI view with standard views and modifiers.
The correct answer is D because it uses the right combination of SwiftUI image modifiers for all three requirements:
* the image is made resizable with .resizable()
* it is given rounded corners with .clipShape(RoundedRectangle(cornerRadius: 50))
* it displays the entire image with .aspectRatio(contentMode: .fit)
* it is sized with .frame(width: 300)
The key part is .aspectRatio(contentMode: .fit) . In SwiftUI, .fit scales the image so the whole image remains visible inside the available frame. That matches the requirement "displays the entire image, regardless of size." By contrast, .fill may crop part of the image, so options using .fill do not satisfy the requirement.
Why the others are wrong:
* Option A uses .fill, so the full image may not remain visible.
* Option B uses invalid modifiers such as .sizablc() and .size(width: 300), and also uses Rectangle (cornerRadius: 50), which is not the correct rounded-rectangle shape syntax.
* Option C also uses invalid syntax and .fill, which can crop the image.
* Option D uses valid SwiftUI syntax and the correct content mode.
So the correct choice is D , because it is the only option that correctly creates a 300-width image with rounded corners while ensuring the entire image is shown.
NEW QUESTION # 23
Review the code snippet.
What is the output from each print statement?
Answer:
Explanation:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
NEW QUESTION # 24
Which property wrapper allows you to read data from the system or device settings?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , specifically the objective about using property wrappers such as @State, @Binding, and @Environment to manage and share data between views.
The correct answer is @Environment because it is used to read values provided by the system or the surrounding view environment. These values can include device-related or system-provided information such as size classes, color scheme, locale, and dismiss actions. In SwiftUI, @Environment gives a view access to contextual information that it does not own directly, but which is supplied by the framework or ancestor views.
The other options are not correct for this purpose:
* @State is used for local mutable state owned by the current view.
* @Binding is used to create a two-way connection to state owned elsewhere, usually in a parent view.
* @StateObject is used to create and own an observable reference-type object for the lifetime of the view.
So if you want a SwiftUI view to read data coming from system or device settings, the correct property wrapper is @Environment .
NEW QUESTION # 25
Review the code snippet.
What value does the code output?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int =
20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple's Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.
The conditional logic is then evaluated in order:
* if age > 64 # false, because 20 is not greater than 64
* else if age > 19 # true, because 20 is greater than 19
* so the function returns 2
Because Swift's if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.
Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .
NEW QUESTION # 26
......
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