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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Using Subqueries to Solve Queries | - Single-row and multi-row subqueries - Correlated subqueries for update/delete | |
| Topic 2: Controlling User Access | - Roles, granting and revoking privileges - System and object privileges | |
| Topic 3: Working with Time Zones and Date/Time Data | - TIMESTAMP, INTERVAL data types - Time zone conversion functions | |
| Topic 4: Managing Tables and Constraints | - Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables | |
| Topic 5: Conversion Functions and Conditional Expressions | 10% | - Implicit and explicit data type conversion - NVL, NULLIF, COALESCE and CASE expressions - TO_CHAR, TO_NUMBER, TO_DATE functions |
| Topic 6: Manipulating Data and Managing Transactions | - INSERT, UPDATE, DELETE, MERGE statements - Multi-table inserts - Transaction control: COMMIT, ROLLBACK, SAVEPOINT | |
| Topic 7: Aggregating Data Using Group Functions | 10% | - GROUP BY and HAVING clauses - SUM, AVG, COUNT, MAX, MIN functions - Handling NULLs in group functions |
| Topic 8: Restricting and Sorting Data | 15% | - ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands - Operator precedence - WHERE clause and filtering conditions |
| Topic 9: Using SET Operators | - UNION, UNION ALL, INTERSECT, MINUS operators - Ordering results with set operations | |
| Topic 10: Relational Database Concepts | 10% | - Theoretical and physical aspects of relational databases - Relationship between database and SQL - ERD and SQL statement mapping |
| Topic 11: Retrieving Data Using SQL SELECT Statement | 20% | - Column aliases, concatenation, literals and DISTINCT - Arithmetic operations and NULL handling - SELECT statement syntax and usage |
| Topic 12: Using Single-Row Functions to Customize Output | 20% | - Character, number, and date functions - Nested functions usage |
| Topic 13: Displaying Data from Multiple Tables | 15% | - Equijoins and non-equijoins - Cartesian products - Self-joins and outer joins |
| Topic 14: Managing Views | - Create, modify and drop views - Updatable and read-only views | |
| Topic 15: Using Data Dictionary Views | - Retrieve metadata and object information | |
| Topic 16: Managing Indexes, Synonyms and Sequences | - Create and maintain indexes - Create and use synonyms - Create and use sequences |
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NEW QUESTION # 414
Which three are true about multitable INSERT statements?
Answer: A,B,C
NEW QUESTION # 415
Examine the structure of the MARKStable:
Which two statements would execute successfully? (Choose two.)
SELECT SUM(DISTINCT NVL(subject1,0)), MAX(subject1)
Answer: B,D
NEW QUESTION # 416
Examine the structure of the EMPLOYEES table.
You must display the maximum and minimum salaries of employees hired 1 year ago.
Which two statements would provide the correct output? (Choose two.)
Answer: A,C
NEW QUESTION # 417
Examine this SQL statement:
SELECT cust_id, cus_last_name "Last Name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses, any one of which can complete the query successfully.
Answer: C,E
Explanation:
In SQL, the ORDER BY clause can refer to columns by their alias defined in the SELECT clause or by their positional number in the SELECT list. It's important to understand that after a UNION, the column names in the ORDER BY clause refer to the first SELECT statement's column names and aliases:
* Option A: ORDER BY 2, 1This is correct because it refers to the second and first columns in the first SELECT clause, which correspond to the aliases "Last Name" and cust_id, respectively.
* Option E: ORDER BY "Last Name"This is correct because "Last Name" is a valid alias defined in the first SELECT clause.
The other options fail for the following reasons:
* Option B: "CUST_NO" is not recognized in the ORDER BY clause because it's not an alias used in the first SELECT statement.
* Option C: Incorrect because 2, cust_id mixes positional reference with a column name that doesn't apply to both SELECT statements consistently.
* Option D: ORDER BY CUST_NO fails because CUST_NO is not an alias in the first SELECT clause.
NEW QUESTION # 418
Which three statements are true regarding single-row functions? (Choose three.)
Answer: B,C,D
NEW QUESTION # 419
......
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