Salesforce JS-Dev-101ブロンズ教材 & JS-Dev-101日本語試験対策

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Salesforce JS-Dev-101 認定試験の出題範囲：

トピック	出題範囲
トピック 1	Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
トピック 2	Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
トピック 3	Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
トピック 4	Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
トピック 5	Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
トピック 6	Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.

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Salesforce Certified JavaScript Developer - Multiple Choice 認定 JS-Dev-101 試験問題 (Q112-Q117):

質問 # 112
Refer to the code snippet:
01 let array = [1, 2, 3, 4, 4, 5, 4, 4];
02 for (let i = 0; i < array.length; i++) {
03 if (array[i] === 4) {
04 array.splice(i, 1);
05 i--;
06 }
07 }
What is the value of array after the code executes?

A. [1, 2, 3, 5]
B. [1, 2, 3, 4, 4, 5, 4]
C. [1, 2, 3, 4, 5, 4]
D. [1, 2, 3, 4, 5, 4, 4]

正解：A

解説：
Comprehensive and Detailed
The loop removes every 4:
Start: [1, 2, 3, 4, 4, 5, 4, 4]
i=0 → 1 (no change)
i=1 → 2 (no change)
i=2 → 3 (no change)
i=3 → 4 → splice removes index 3 → [1,2,3,4,5,4,4], then i-- → 2
Next loop, i=3 → 4 again → splice → [1,2,3,5,4,4], i-- → 2
i=3 → 5 (no change)
i=4 → 4 → splice → [1,2,3,5,4], i-- → 3
i=4 → 4 → splice → [1,2,3,5], i-- → 3
Next i=4, array.length is 4 → loop ends.
All 4s removed, final array: [1, 2, 3, 5].
________________________________________

質問 # 113
GIven a value, which three options can a developer use to detect if thevalue is NaN?
Choose 3 answers !

A. value == NaN
B. value === Number.NaN
C. Object.is(value, NaN)
D. value ! == value
E. Number.isNaN(value)

正解：A、E

質問 # 114
01 let a = "*";
02 let b = "**";
/ 7 x = 3;
04 console.log(a);
What is displayed when the code executes?

A. undefined
B. ReferenceError: a is not defined
C. null
D. a

正解：A

質問 # 115
Refer to the following code:
01 class Ship {
02 constructor(size) {
03 this.size = size;
04 }
05 }
06
07 class FishingBoat extends Ship {
08 constructor(size, capacity){
09 //Missing code
10 this.capacity = capacity;
11 }
12 displayCapacity() {
13 console.log('The boat has a capacity of ${this.capacity} people.');
14 }
15 }
16
17 let myBoat = new FishingBoat('medium', 10);
18 myBoat.displayCapacity();
Which statement should be added to line 09 for the code to display
The boat has a capacity of 10 people?

A. super.size = size;
B. ship.size = size;
C. this.size = size;
D. super(size);

正解：D

解説：
FishingBoat extends Ship, so it is a subclass. In ES6 classes:
When you define a constructor in a subclass, you must call super(...) before accessing this.
super(size) calls the parent class (Ship) constructor, which sets this.size = size.
So the correct constructor is:
class FishingBoat extends Ship {
constructor(size, capacity) {
super(size); // line 09
this.capacity = capacity;
}
displayCapacity() {
console.log(`The boat has a capacity of ${this.capacity} people.`);
}
}
Why others are incorrect:
B . ship.size = size;
ship is not defined; this would cause a ReferenceError.
C . super.size = size;
super is not an instance; you must call super(...) as a function to invoke the parent constructor.
D . this.size = size;
In a subclass constructor, you must call super() before using this, otherwise you get a ReferenceError. Also this bypasses the parent constructor logic.
Relevant concepts: ES6 class inheritance, extends, super() in subclass constructors, this initialization rules.

質問 # 116
Code:
01 let array = [1, 2, 3, 4, 4, 5, 4, 4];
02 for (let i = 0; i < array.length; i++) {
03 if (array[i] === 4) {
04 array.splice(i, 1);
05 i--;
06 }
07 }
What is the value of array after execution?

A. [1,2,3,4,5,4]
B. [1,2,3,5]
C. [1,2,3,4,5,4,4]
D. [1,2,3,4,4,5,4]

正解：B

解説：
Initial array:
[1, 2, 3, 4, 4, 5, 4, 4]
The loop removes every value equal to 4:
array.splice(i, 1) removes the element at index i and shifts all later elements left.
i-- ensures the next index is checked correctly after the shift, preventing skipping elements.
Step-by-step removal:
Remove the first 4 → array becomes [1,2,3,4,5,4,4]
Remove next 4 → [1,2,3,5,4,4]
Remove next 4 → [1,2,3,5,4]
Remove last 4 → [1,2,3,5]
Final result:
[1,2,3,5]
Option B is correct.
JavaScript Knowledge Reference (text-only)
splice(index, deleteCount) removes elements and shifts remaining items.
Adjusting the loop index when deleting prevents skipping items.
Arrays update length dynamically after splice().

質問 # 117
......

JS-Dev-101試験ガイドは、ビジネスマンであろうと学生であろうと、すべての人に適しています。試験に参加するには、20〜30時間で練習できます。あなたが素晴らしい成績をとれることは間違いありません。私たちの学習ペースに従えば、予想外の驚きがあります。当社のJS-Dev-101ガイドトレントを選択した場合にのみ、この重要な試験に合格し、JS-Dev-101試験の準備に関するまったく新しい経験を得ることが容易になります。

JS-Dev-101日本語試験対策: https://www.goshiken.com/Salesforce/JS-Dev-101-mondaishu.html

さらに、GoShiken JS-Dev-101ダンプの一部が現在無料で提供されています：https://drive.google.com/open?id=1I3qJQrLfDPugrkDWP_4kE1d4T7YH7o_5