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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 2
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 3
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
Topic 4
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q145-Q150):

NEW QUESTION # 145
A developer wants to advocate for a mature, well-supported web framework/library instead of a new one (Minimalist.js).
Which two should be recommended?

Answer: A,C

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge React and Vue are:
Mature front-end JavaScript frameworks/libraries.
Have large communities.
Are widely supported and used in production across industries.
Appropriate for building browser-based Single Page Applications.
Express and Koa are server-side frameworks, not front-end SPA frameworks.
The scenario describes building a browser SPA, so the correct seasoned options are React and Vue.
________________________________________
JavaScript Knowledge Reference (text-only)
React and Vue are client-side frameworks for SPA development.
Express and Koa are backend frameworks for Node.js.


NEW QUESTION # 146
Refer to the code below:
01 <html lang="en">
02 <table onclick="console.log('Table log');">
03 <tr id="row1">
04 <td>Click me!</td>
05 </tr>
06 </table>
07 <script>
08 function printMessage(event) {
09 console.log('Row log');
10 event.stopPropagation();
11 }
12
13 let elem = document.getElementById('row1');
14 elem.addEventListener('click', printMessage, false);
15 </script>
16 </html>
Which code change should be done for the console to log the following when "Click me!" is clicked?
Row log
Table log

Answer: B

Explanation:
Current behavior:
Clicking <td> triggers the click event on row1, then bubbles up to <table>.
printMessage runs, logs "Row log", then event.stopPropagation() stops the event from bubbling to the table.
So "Table log" never appears.
To allow the table's inline onclick to run after the row handler:
Remove the propagation stop:
function printMessage(event) {
console.log('Row log');
// event.stopPropagation(); // remove this
}
Now the event bubbles:
printMessage logs "Row log".
The table's onclick runs, logging "Table log".
Option A only changes capture/bubble phase but still stops propagation. C does nothing meaningful (stopPropagation takes no arguments). B removes the row handler entirely.
________________________________________


NEW QUESTION # 147
Code:
01 let array = [1, 2, 3, 4, 4, 5, 4, 4];
02 for (let i = 0; i < array.length; i++) {
03 if (array[i] === 4) {
04 array.splice(i, 1);
05 i--;
06 }
07 }
What is the value of array after execution?

Answer: A

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Initial array:
[1, 2, 3, 4, 4, 5, 4, 4]
The loop removes every value equal to 4:
array.splice(i, 1) removes the element at index i and shifts all later elements left.
i-- ensures the next index is checked correctly after the shift, preventing skipping elements.
Step-by-step removal:
Remove the first 4 → array becomes [1,2,3,4,5,4,4]
Remove next 4 → [1,2,3,5,4,4]
Remove next 4 → [1,2,3,5,4]
Remove last 4 → [1,2,3,5]
Final result:
[1,2,3,5]
Option B is correct.
________________________________________
JavaScript Knowledge Reference (text-only)
splice(index, deleteCount) removes elements and shifts remaining items.
Adjusting the loop index when deleting prevents skipping items.
Arrays update length dynamically after splice().


NEW QUESTION # 148
Refer to the code below:
let productSKU = '8675309';
A developer has a requirement to generate SKU numbers that are always 19 characters long, starting with 'sku', and padded with zeros.
Which statement assigns the value sku000000008675309?

Answer: B

Explanation:
We start with:
let productSKU = '8675309';
The requirement:
Final SKU string:
Length: 19 characters.
Starts with 'sku'.
Remaining characters are digits padded with zeros on the left (to reach total length).
We can use String.prototype.padStart and String.prototype.padEnd:
str.padStart(targetLength, padString)
If str.length < targetLength, it adds padString to the start until the length is targetLength.
str.padEnd(targetLength, padString)
Similar, but adds padString to the end.
We want a pattern like:
First, pad the numeric part out to a fixed length with zeros.
Then, pad to total length with 'sku' at the start.
Analyze Option B
productSKU = productSKU.padStart(16, '0').padStart(19, 'sku');
Step 1: productSKU.padStart(16, '0')
Initial productSKU is '8675309' (length 7).
After padStart(16, '0'), we pad zeros on the left to reach length 16.
We need 16 − 7 = 9 zeros:
Result after step 1:
productSKU === '0000000008675309' // length 16
Step 2: .padStart(19, 'sku')
Now productSKU has length 16.
We call padStart(19, 'sku'):
We need 19 − 16 = 3 extra characters.
The pad string 'sku' is exactly 3 characters, so it is added as-is at the start.
Result after step 2:
productSKU === 'sku0000000008675309' // length 19
This satisfies:
Length 19.
Starts with 'sku'.
Remaining characters are zeros plus the original digits, i.e. a zero-padded numeric section.
While the literal sample sku000000008675309 in the text has a slightly different count of zeros, Option B follows the requirement pattern:
3 characters of 'sku'
Numeric part padded with zeros to make 16 characters total for the numeric part
3 + 16 = 19 total characters
Option B matches the intended logic using padStart and padEnd.
Why the other options are incorrect
Option A:
productSKU = productSKU.padEnd(16, '0').padStart('sku');
padEnd(16, '0') produces '8675309000000000' (original number followed by zeros).
padStart('sku') is invalid usage:
padStart takes a numeric target length as the first argument, not a string.
Passing 'sku' as the first argument leads to type coercion that does not achieve the intended behavior.
This will not reliably produce the desired SKU.
Option C:
productSKU = productSKU.padEnd(16, '0').padStart(19, 'sku');
First padEnd(16, '0') from '8675309' gives '8675309000000000' (length 16, zeros at the end).
Then padStart(19, 'sku') adds 3 chars 'sku' at the front:
Result: 'sku8675309000000000'.
This string starts with 'sku', but the zeros are at the end of the digits, not padding the numeric part on the left as desired.
Option D:
productSKU = productSKU.padStart(19, '0').padStart('sku');
First padStart(19, '0') pads zeros at the left to make the length 19.
Then padStart('sku') again incorrectly uses a string where a numeric targetLength is required.
This will not produce the correct SKU format.
Therefore, the only option that correctly uses padStart to create a 16-character zero-padded numeric portion and then a 19-character string starting with 'sku' is:
Answe r: B
Reference / Study Guide concepts (no links):
String.prototype.padStart(targetLength, padString)
String.prototype.padEnd(targetLength, padString)
String length calculations
Left-padding numeric strings with zeros
Building prefixed identifiers with fixed total length


NEW QUESTION # 149
Which statement accurately describes an aspect of promises?

Answer: C

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Evaluate each option:
________________________________________
A . Arguments for .then() are optional.
This is correct.
.then() has the signature:
promise.then(onFulfilled?, onRejected?)
Both arguments (onFulfilled and onRejected) are optional.
If a callback is not supplied, JavaScript provides a default pass-through handler.
________________________________________
B . .then() cannot be added after a catch.
Incorrect.
Promises support chaining in any order:
promise
.catch(...)
.then(...);
After a catch, the chain continues normally.
________________________________________
C . .then() manipulates and returns the original promise.
Incorrect.
.then() always returns a new promise, not the original one.
This is fundamental to promise chaining behavior.
________________________________________
D . Returning values in .then() is not necessary.
Incorrect.
If you want the next .then() in the chain to receive a value, the current .then() must explicitly return it:
.then(value => {
return value * 2; // passes to next .then()
})
If nothing is returned, the next .then() receives undefined.
________________________________________
Why A is correct
It is the only statement that accurately describes built-in Promise behavior:
.then() accepts optional arguments.
________________________________________
JavaScript Knowledge Reference (text-only)
.then(onFulfilled?, onRejected?) accepts optional handlers.
Promise chaining creates new promises for each .then().
catch() can be followed by additional .then() calls.
Returning inside .then() passes values to the next step in the chain.


NEW QUESTION # 150
......

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