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>> Authorized JS-Dev-101 Exam Dumps <<
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NEW QUESTION # 70
A developer needs to test this function:
01const sum3 = (arr) => (
02if (!arr.length) return 0,
03if (arr.length === 1) return arr[0],
04if (arr.length === 2) return arr[0]+ arr[1],
05 return arr[0] + arr[1] + arr[2],
06 );
Which two assert statements are valid tests for the function?
Choose 2 answers
Answer: B,D
NEW QUESTION # 71
A developer has an ErrorHandler module that contains multiple functions.
What kind of export be leverages so that multiple functions can beused?
Answer: B
NEW QUESTION # 72
bar, awesome is a popular JavaScript module. the versions publish to npm are:
Teams at Universal Containers use this module in a number of projects. A particular project has thepackage, json definition below.
A developer runs this command: npm install. Which version of bar .awesome is installed?
Answer: D
NEW QUESTION # 73
Refer to the code below:
let strNumber = '12345';
Which code snippet shows a correct way to convert this string to an integer?
Answer: A
Explanation:
The correct answer is C.
The original option contains a typing error. It should use the existing variable name:
let numberValue = Number(strNumber);
The value of strNumber is a string:
'12345'
Using Number() converts the numeric string into a JavaScript number:
12345
So after execution:
typeof numberValue;
returns:
"number"
Professional review of each option:
Option
Result
Explanation:
A
Incorrect
JavaScript does not have a standard global Integer() conversion function.
B
Incorrect
Strings do not have a standard .toInteger() method.
C
Correct
Number(strNumber) correctly converts '12345' into 12345.
D
Incorrect
This is not valid JavaScript casting syntax.
A commonly used alternative would also be:
let numberValue = parseInt(strNumber, 10);
But from the provided answer choices, the verified answer is C.
NEW QUESTION # 74
Given the following code:
01 counter = 0;
02 const logCounter = () => {
03 console.log(counter);
04 };
05 logCounter();
06 setTimeout(logCounter, 2100);
07 setInterval(() => {
08 counter++;
09 logCounter();
10 }, 1000);
What will be the first four numbers logged?
Answer: C
Explanation:
We need to track the value of counter and the timing of each call to logCounter.
Initial state:
Line 01: counter = 0;
Line 02-04: logCounter logs the current value of counter.
Execution order and timing:
Line 05: logCounter();
Called immediately at time t = 0 ms.
counter is 0.
First log: 0.
Line 06: setTimeout(logCounter, 2100);
Schedules logCounter to run once after 2100 ms.
No log yet at this line.
Line 07-10: setInterval(() => { counter++; logCounter(); }, 1000);
Schedules a repeating callback every 1000 ms (1 second).
First interval callback runs at t ≈ 1000 ms.
Now follow the timeline:
t = 0 ms:
logCounter(); from line 05
Logs: 0
t = 1000 ms (first interval execution):
counter++; → counter goes from 0 to 1.
logCounter(); logs 1.
t = 2000 ms (second interval execution):
counter++; → counter goes from 1 to 2.
logCounter(); logs 2.
t = 2100 ms (timeout from line 06):
logCounter(); runs again.
counter is still 2 (next setInterval will be at t = 3000 ms).
Logs 2.
So the first four logs are:
0
1
2
2
Concatenated as in the options: 0122.
Therefore, the correct choice is:
Answe r: A
Study Guide / Concept Reference (no links):
setTimeout and setInterval timing behavior
Order of execution in the event loop
Closures capturing variables (here, logCounter using counter)
Understanding asynchronous scheduling in JavaScript
NEW QUESTION # 75
......
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