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Oracle 1z1-071 Exam Syllabus Topics:

Section	Weight	Objectives
Using Set Operators	5%	- Describe the order of precedence when the set operators are used - Describe set operators - Use a set operator to combine multiple queries into a single query
Creating Other Schema Objects	10%	- Create, maintain, and use sequences - Create synonyms for database objects - Create and maintain indexes - Create, modify, and retrieve data from a view
Displaying Data from Multiple Tables Using Joins	15%	- View data that does not meet a join condition by using outer joins - Write SELECT statements to access data from more than one table using equijoins and non-equijoins - Join a table to itself by using a self-join - Cross join tables
Restricting and Sorting Data	6%	- Use ampersand substitution to restrict and sort output at runtime - Limit the rows that are retrieved by a query - Use DEFINE and UNDEFINE commands - Sort the rows that are retrieved by a query
Using Conversion Functions and Conditional Expressions	10%	- Apply the NVL, NULLIF, and COALESCE functions to data - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions - Describe implicit and explicit data type conversion - Use conditional IF THEN ELSE logic in a SELECT statement
Retrieving Data Using the SQL SELECT Statement	5%	- List the capabilities of SQL SELECT statements - Execute a basic SELECT statement - Differentiate between SQL statements and SQL*Plus commands
Using DDL Statements to Create and Manage Tables	14%	- Describe the data types that are available for columns - Drop, rename, and truncate tables - Alter table definitions - Review the table structure - Create a simple table - Categorize the main database objects
Using Subqueries to Solve Queries	15%	- Define subqueries - Write single-row and multi-row subqueries - List the types of subqueries - Describe the types of problems that subqueries can solve
Working with Oracle Database SQL	8%	- Explain the installation of Oracle Database software - Start up and shut down a database - Describe the Oracle Database architecture - Create a container database
Manipulating Data	14%	- Control transactions - Insert rows into a table - Delete rows from a table - Describe each data manipulation language (DML) statement - Update rows in a table
Reporting Aggregated Data Using Group Functions	15%	- Describe the use of group functions - Identify the available group functions - Include or exclude grouped rows by using the HAVING clause - Group data by using the GROUP BY clause
Using Single-Row Functions to Customize Output	10%	- Describe the differences between single-row and multiple-row functions - Perform arithmetic with date data - Manipulate numbers with the ROUND, TRUNC, and MOD functions - Manipulate dates with the date functions - Manipulate strings with character function in the SELECT and WHERE clauses
Controlling User Access	5%	- Distinguish between granting privileges and roles - Differentiate system privileges from object privileges - Grant privileges on tables and on a view

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Oracle Database SQL Sample Questions (Q109-Q114):

NEW QUESTION # 109
The first DROP operation is performed on PRODUCTS table using this command:
DROP TABLE products PURGE;
Then a FLASHBACK operation is performed using this command:
FLASHBACK TABLE products TO BEFORE DROP;
Which is true about the result of the FLASHBACK command?

A. It recovers the table structure, data, and the indexes.
B. It is not possible to recover the table structure, data, or the related indexes.
C. It recovers the table structure and data but not the related indexes.
D. It recovers only the table structure.

Answer: B

Explanation:
Explanation
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_9003.htm

NEW QUESTION # 110
SCOTTis a user in the database.
Evaluate the commands issued by the DBA:

Which statement is true regarding the execution of the above commands?

A. Statement 1 would not execute because the IDENTIFIED BY <password>clause is missing.
B. Statement 1 would not execute because the WITH GRANToption is missing.
C. Statement 2 would not execute because system privileges and object privileges cannot be granted together in a single GRANTcommand.
D. Statement 3 would not execute because role and system privileges cannot be granted together in a single GRANTstatement.

Answer: C

Explanation:
Explanation/Reference:

NEW QUESTION # 111
Which two statements are true regarding a SAVEPOINT? (Choose two.)

A. Rolling back to a SAVEPOINT can undo a DELETE statement
B. Only one SAVEPOINT may be issued in a transaction
C. Rolling back to a SAVEPOINT can undo a CREATE INDEX statement
D. A SAVEPOINT does not issue a COMMIT
E. Rolling back to a SAVEPOINT can undo a TRUNCATE statement

Answer: A,D

Explanation:
Explanation/Reference:

NEW QUESTION # 112
Examine the description of the ORDERS table:

Which three statements execute successfully?

A. SELECT * FROM orders ORDER BY order_ id
INTERSEOT
SELECT * FROM invoices ORDER BY invoice_ id;
B. SELECT order_ id, invoice_ data order_ date FROM orders
MINUS
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY invoice_ id;
C. SELECE order _id, order _ date FRON orders
LNTERSECT
SELECT invoice_ id, invoice_ id, order_ date FROM orders
D. SELECT order_ id, order_ data FROM orders
UNION ALL
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY order_ id;
E. (SELECT * FROM orders
UNION ALL
SELECT* FROM invoices) ORDER BY order _id;
F. SELECT * FROM orders
MINUS
SELECT * FROM INVOICES ORDER BY 1
G. SELECT * FROM orders ORDER BY order_ id
UNION
SELECT * FROM invoices;

Answer: D,E,G

Explanation:
In Oracle SQL, set operations like UNION, UNION ALL, INTERSECT, and MINUS can be used to combine results from different queries:
Option A:
Combining results using UNION ALL followed by ORDER BY will execute successfully because UNION ALL allows duplicate rows and ORDER BY can be used to sort the combined result set.
Option E:
Similar to option A, UNION ALL combines all rows from the two selects and allows ordering of the results.
Option G:
UNION combines the results from two queries and removes duplicates, and ORDER BY can be used to sort the final result set.
Options B, C, D, and F are incorrect because:
Option B: You cannot intersect different columns (ORDER_ID with INVOICE_ID).
Option C: Incorrect column names and syntax with ORDER BY.
Option D: ORDER BY cannot be used before a set operator like INTERSECT.
Option F: ORDER BY cannot be used directly after a MINUS operator without wrapping the MINUS operation in a subquery.

NEW QUESTION # 113
Examine the structure of the employees table:

There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the name, joining date, and manager for all the employees. Newly hired employees are yet to be assigned a department or a manager. For them, 'No Manager1 should be displayed in the manager column.
Which SQL query gets the required output?

A. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e JOIN employees m ON (e.manager_id = m.employee_id);
B. SELECT e.last_name/ e.hire_date/ NVL(m.last_______ name/ 'No Manager') Manager FROM employees e NATURAL JOIN employees m ON (e.manager_id = m.employee_id);
C. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e LEFT OUTER JOIN employees m ON (e.manager_id = m.employee_id);
D. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') Manager FROM employees e RIGHT OUTER JOIN employees m ON (e.manager_id = m.employee_id);

Answer: C

Explanation:
We should use LEFT OUTER JOIN as we want to display employees which have no (have NULL values for) managers.

NEW QUESTION # 114
......

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