Oracle Database SQL Valid Exam Guide & 1z0-071 Free Pdf Vce & Oracle Database SQL Latest Practice Questions

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Oracle 1z0-071 Exam Overview:

Certification Vendor:	Oracle
Exam Name:	Oracle Database SQL
Exam Number:	1Z0-071
Exam Format:	Proctored exam, Computer-based exam, Multiple Response, Multiple Choice
Exam Duration:	120 minutes
Exam Price:	USD 245 (varies by country/region)
Related Certifications:	Oracle Database Administrator Certified Associate Oracle Database Development certifications
Certificate Validity Period:	Non-expiring (Oracle certification policy subject to change)
Available Languages:	Portuguese, Spanish, Japanese, Chinese (Simplified), English
Recommended Training:	Oracle Database SQL Training
Exam Registration:	Oracle Certification Registration
Sample Questions:	Oracle 1z0-071 Sample Questions
Exam Way:	Online proctored or test center delivery depending on region
Pre Condition:	No formal prerequisites required; basic knowledge of relational databases and SQL recommended.
Official Syllabus URL:	https://education.oracle.com/oracle-database-sql/pexam_1Z0-071

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Oracle Database SQL Sample Questions (Q165-Q170):

NEW QUESTION # 165
See the Exhibit and Examine the structure of the CUSTOMERS table:

Using the CUSTOMERS table, you need to generate a report that shows an increase in the credit limit by 15% for all customers. Customers whose credit limit has not been entered should have the message "Not Available" displayed.
Which SQL statement would produce the required result?

A. SELECT NVL(cust_credit_limit*.15,'Not Available') "NEW CREDIT" FROM customers;
B. SELECT TO_CHAR(NVL(cust_credit_limit*.15,'Not Available')) "NEW CREDIT" FROM customers;
C. SELECT NVL(cust_credit_limit,'Not Available')*.15 "NEW CREDIT" FROM customers;
D. SELECT NVL(TO_CHAR(cust_credit_limit*.15),'Not Available') "NEW CREDIT" FROM customers;

Answer: D

Explanation:
NVL Function
Converts a null value to an actual value:
Data types that can be used are date, character, and number.
Data types must match:
NVL(commission_pct,0)
NVL(hire_date,'01-JAN-97')
NVL(job_id,'No Job Yet')

NEW QUESTION # 166
Examine the data in the CUST_NAMEcolumn of the CUSTOMERStable.

You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:

Which two queries give the required output? (Choose two.)

A. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR (cust_name, ' '), '*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',1,-2)<>0;
B. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR (cust_name, ' '), '*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',1,2)<>0;
C. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',-1,2)<>0;
D. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME" FROM customers WHERE INSTR(cust_name, ' ',1,2)<>0;

Answer: C,D

NEW QUESTION # 167
You issued this command:

Which three statements are true?

A. Views referencing HR.EMPLOYEES are dropped.
B. The HR.EMPLOYEES table may be moved to the recycle bin.
C. Sequences used to populate columns in the HR.EMPLOYEES table are dropped.
D. All indexes defined on HR.EMPLOYEES are dropped.
E. Synonyms for HR.EMPLOYEES are dropped.
F. All constraints defined on HR.EMPLOYEES are dropped.

Answer: A,D,F

NEW QUESTION # 168
View the exhibit and examine the descriptions of the DEPTand LOCATIONStables.

You want to update the CITYcolumn of the DEPTtable for all the rows with the corresponding value in the CITYcolumn of the LOCATIONStable for each department.
Which SQL statement would you execute to accomplish the task?

A. UPDATE dept d
SET city = (SELECT city
FROM locations l)
WHERE d.location_id = l.location_id;
B. UPDATE dept d
SET city = ANY (SELECT city
FROM locations l)
C. UPDATE dept d
SET city = (SELECT city
FROM locations l
WHERE d.location_id = l.location_id);
D. UPDATE dept d
SET city = ALL (SELECT city
FROM locations l
WHERE d.location_id = l.location_id);

Answer: C

NEW QUESTION # 169
View the Exhibit and examine the description of the EMPLOYEES table.

Evaluate the following SQL statement:
SELECT first_name, employee_id, NEXT_DAY(ADD_MONTHS(hire_date, 6), 1) "Review" FROM employees; The query was written to retrieve the FIRST_NAME, EMPLOYEE_ID, and review date for employees. The review date is the firsts Monday after the completion of six months of the hiring. The NLS_TERRITORY parameter is set to AMERICA in the session.
Which statement is true regarding this query?

A. The query would not execute because the NEXT_DAY function accepts a string as argument.
B. The query would execute but the output would give review dates that are Sundays.
C. The query would not execute because date functions cannot be nested.
D. The query would execute to give the desired output.

Answer: B

NEW QUESTION # 170
......

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