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NEW QUESTION # 113
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString && searchString.toLowerCase();
03 document.querySelectorAll('.account').forEach(account => {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */;
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?
Answer: D
Explanation:
We have a ternary:
account.style.display = accountName.includes(parsedSearchString)
? /* if true */
: /* if false */;
Requirement:
If the account matches the search string → show it.
If it does not match → hide it.
For display:
Show: 'block' (or similar visible value).
Hide: 'none'.
So we want:
account.style.display = accountName.includes(parsedSearchString)
? 'block'
: 'none';
That corresponds to option A.
Why others are wrong:
B, C use values suitable for visibility, not display.
D ('none' : 'block') inverts the logic, hiding matches and showing non-matches.
________________________________________
NEW QUESTION # 114
Corrected code:
let a = "*";
let b = "**";
// x = 3;
console.log(a);
What is displayed when the code executes?
Answer: D
Explanation:
The correct answer is B because variable a is declared and initialized before it is printed.
let a = "*";
This creates a block-scoped variable named a and assigns it the string value:
"*"
The line:
// x = 3;
is a comment. JavaScript ignores comments during execution, so this line has no effect.
Then this line runs:
console.log(a);
Since a already exists and contains "*", the console displays:
* Option A is incorrect because a is defined.
Option C is incorrect because a has an assigned value, so it is not undefined.
Option D is incorrect because a was never assigned null.
Therefore, the verified answer is B.
NEW QUESTION # 115
A developer creates a simple webpage with an input field. When a user enters text in the input field and clicks the button, the actual value of the field must be displayedin the console.
Here is the HTML file content:
<input type =" text" value="Hello" name ="input">
<button type ="button" >Display </button> The developer wrote the javascript code below:
Const button = document.querySelector('button');
button.addEvenListener('click', () => (
Const input = document.querySelector('input');
console.log(input.getAttribute('value'));
When the user clicks the button, the output is always "Hello".
What needs to be done to make this code work as expected?
Answer: A
NEW QUESTION # 116
01 function Animal(size, type) {
02 this.type = type || 'Animal';
03 this.canTalk = false;
04 }
05
06 Animal.prototype.speak = function() {
07 if (this.canTalk) {
08 console.log("It spoke!");
09 }
10 };
11
12 let Pet = function(size, type, name, owner) {
13 Animal.call(this, size, type);
14 this.size = size;
15 this.name = name;
16 this.owner = owner;
17 }
18
19 Pet.prototype = Object.create(Animal.prototype);
20 let pet1 = new Pet();
Given the code above, which three properties are set for pet1?
Answer: A,B,D
Explanation:
When pet1 = new Pet(); is created:
Inside Pet constructor:
Animal.call(this, size, type);
this.size = size;
this.name = name;
this.owner = owner;
Animal.call(this, size, type):
Sets this.type = type || 'Animal' → 'Animal' (because type is undefined).
Sets this.canTalk = false.
Then this.size, this.name, this.owner are set (to undefined since no args passed), but they do exist as properties.
So as own properties, pet1 has: type, canTalk, size, name, owner.
speak is defined on Animal.prototype, so pet1.speak exists by inheritance, but is not an own data property created in the constructor.
From the listed options, three important properties directly set by constructor logic and clearly used in behavior are:
canTalk
name
type
Thus, C, D, E.
________________________________________
NEW QUESTION # 117
Refer to the following code:
01 let obj = {
02 foo: 1,
03 bar: 2
04 }
05 let output = []
06
07 for (let something of obj) {
08 output.push(something);
09 }
10
11 console.log(output);
What is the value of output on line 11?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
The key line is:
for (let something of obj) {
In JavaScript:
for...of is used to iterate over iterable objects, such as:
Arrays
Strings
Maps
Sets
Other objects that implement a [Symbol.iterator] method.
Plain JavaScript objects created with object literal {} are not iterable by default. They do not have [Symbol.iterator], so using for...of directly on them causes a runtime error.
Specifically:
for (let something of obj) { ... }
will throw a TypeError similar to:
obj is not iterable
Therefore, the loop body never executes, and console.log(output); is never reached without an error.
Why other options are incorrect:
B . [1, 2]
To get [1, 2], you could use Object.values(obj) and iterate that array.
But here, for...of obj never yields values because it throws an error.
C . ["foo", "bar"]
To get property names, you could use Object.keys(obj) with for...of.
Again, the code does not do that; it incorrectly tries to iterate the object directly.
D . ["foo:1", "bar:2"]
You would need both keys and values, combining them manually.
The given code does not implement such logic and fails before pushing anything into output.
Hence, the correct answer is:
Answe r: A
Study Guide / Concept Reference (no links):
Difference between for...of and for...in
Iterables in JavaScript and [Symbol.iterator]
Plain objects {} are not iterable by default
Correct patterns to iterate object keys/values (Object.keys, Object.values, Object.entries)
________________________________________
NEW QUESTION # 118
......
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