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Apple App-Development-with-Swift-Certified-User Exam Syllabus Topics:

SectionObjectives
Introduction to App Development with Swift- Swift programming fundamentals
  • 1. Operators and expressions
    • 2. Control flow (if, switch, loops)
      • 3. Variables, constants, and data types
        User Interface Development- Building iOS interfaces
        • 1. UIKit fundamentals
          • 2. Views and layout concepts
            • 3. Auto Layout basics
              App Lifecycle and Deployment Concepts- Understanding app structure
              • 1. App lifecycle events
                • 2. Debugging and testing basics
                  App Logic and Data Handling- Data management in apps
                  • 1. Model-view-controller (MVC) basics
                    • 2. Arrays and collections
                      • 3. Simple persistence concepts

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                        Apple App Development with Swift Certified User Exam Sample Questions (Q17-Q22):

                        NEW QUESTION # 17
                        Review the code snippet.

                        What value does the code output?

                        Answer:

                        Explanation:
                        Answer the question by typing in the box.
                        2
                        Explanation:
                        This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int =
                        20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple's Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.
                        The conditional logic is then evaluated in order:
                        * if age > 64 # false, because 20 is not greater than 64
                        * else if age > 19 # true, because 20 is greater than 19
                        * so the function returns 2
                        Because Swift's if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.
                        Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .


                        NEW QUESTION # 18
                        When you press ' Show Button ' on your app. a modal View appears.
                        Complete the code by selecting the correct option from each drop-down list.
                        Note: You will receive partial credit for each correct answer.

                        Answer:

                        Explanation:

                        Explanation:

                        This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .
                        To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:
                        sheet(isPresented: $showInfo) {
                        // modal content
                        }
                        So the first blank must be .sheet , and the second blank must be (isPresented: .
                        The logic works like this:
                        * @State stores the local Boolean that controls presentation.
                        * Pressing the button calls showInfo.toggle(), changing the value from false to true.
                        * When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.
                        * When the modal is dismissed, SwiftUI updates the Boolean back as needed.
                        There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:
                        @State var showInfo = false
                        Therefore, the correct dropdown selections are:
                        sheet
                        (isPresented:


                        NEW QUESTION # 19
                        Review the code snippet.

                        What is the output from each print statement?

                        Answer:

                        Explanation:
                        Answer the question by typing in the box.
                        10
                        Explanation:
                        This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
                        The key point is that Printer is declared as a class :
                        class Printer {
                        var copies: Int
                        init(copies: Int) {
                        self.copies = copies
                        }
                        }
                        In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
                        var printer1 = Printer(copies: 2)
                        var printer2 = printer1
                        both printer1 and printer2 point to the same Printer instance.
                        Next, this line changes the shared object:
                        printer2.copies = 10
                        Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
                        copies. Therefore, when the code executes:
                        print(printer1.copies)
                        the output is 10 .
                        This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.


                        NEW QUESTION # 20
                        Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.

                        |Complete the code by typing in the boxes.

                        Answer:

                        Explanation:
                        NavigationLink, .sheet
                        Explanation:
                        This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
                        The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
                        So the completed structure is effectively:
                        NavigationLink( " Show Blue View " ) {
                        BlueView()
                        }
                        sheet(isPresented: $showRedView) {
                        RedView()
                        }
                        This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.


                        NEW QUESTION # 21

                        Which two assignments of a value to direction are allowed? (Choose 2.)

                        Answer: A,D

                        Explanation:
                        This question belongs to Swift Programming Language , specifically the domain covering basic Swift types and how Swift handles enumerations . The code defines an enum named CompassPoint with the cases north, south, east, and west, and then declares direction as type CompassPoint. In Swift, an enum case can be assigned using the fully qualified form CompassPoint.north, so B is valid. Swift also allows the shorthand form .north when the compiler already knows the expected type is CompassPoint, so D is also valid. Apple's Swift language documentation explains that once a variable is known to be of a specific enumeration type, you can set its value using the shorter dot syntax.
                        The other options are not allowed. A is invalid because enum cases are not assigned using constructor-style syntax like CompassPoint(north). C is invalid because north by itself is not enough unless it is written with dot shorthand in a context with inferred enum type. E is invalid because north is a case of the enum type, not a member accessed from the variable instance as direction.north. Swift enum cases are referenced from the enum type or by shorthand dot syntax, not as instance properties.


                        NEW QUESTION # 22
                        ......

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