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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Server Side JavaScript | 8% | - Package management and CLI tools - Node.js fundamentals and core modules |
| Topic 2: Debugging and Error Handling | 7% | - Console usage, breakpoints and debugging techniques - Error types and handling strategies |
| Topic 3: Variables, Types, and Collections | 23% | - Variable declaration and scope - Strings, numbers, dates, arrays and methods - JSON parsing and manipulation - Data types, type coercion, truthy/falsy values |
| Topic 4: Browser and Events | 17% | - Browser APIs and developer tools - DOM selection and manipulation - Event handling, propagation, listeners |
| Topic 5: Testing | 7% | - Unit test structure and effectiveness - Test coverage and improvement |
| Topic 6: Asynchronous Programming | 13% | - Callbacks, promises, async/await - Event loop and execution flow |
| Topic 7: Objects, Functions, and Classes | 25% | - ES6 classes, inheritance, modules, decorators - Function types, scope, closures, arrow functions - Object creation, properties, prototypes |
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NEW QUESTION # 54
Refer to the code below:
01 const addBy = ?
02 const addByEight = addBy(8);
03 const sum = addByEight(50);
Which two functions can replace line 01 and return 58 to sum?
Answer: A,B
Explanation:
}
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
We want:
const addByEight = addBy(8);
const sum = addByEight(50);
And we need sum to be 58.
That means:
addBy(8) must return a function.
That returned function, when called with 50, must compute 8 + 50.
So addBy must be a higher-order function that returns another function capturing num1 and later using it with num2 (a closure).
Option A
const addBy = function(num1) {
return function(num2) {
return num1 + num2;
}
}
Step-by-step:
Call addBy(8):
num1 is 8.
The function returns an inner function: function(num2) { return num1 + num2; }.
So addByEight becomes this inner function, with num1 closed over as 8.
Then call addByEight(50):
num2 is 50.
The body computes num1 + num2, i.e., 8 + 50 = 58.
Therefore, with Option A in place:
const addByEight = addBy(8); // returns inner function
const sum = addByEight(50); // 58
So sum is 58. Option A is correct.
Option D (corrected)
const addBy = (num1) => {
return function(num2) {
return num1 + num2;
}
}
This is essentially the same logic expressed with an arrow function for the outer function:
Call addBy(8):
num1 is 8.
Returns the inner function function(num2) { return num1 + num2; }.
Call addByEight(50):
num2 is 50.
Computes num1 + num2 → 8 + 50 = 58.
So again:
const addByEight = addBy(8); // inner function with num1 = 8
const sum = addByEight(50); // 58
Option D is also correct.
Thus, A and D are the two functions that satisfy the requirement.
Why B and C are incorrect
Option B:
const addBy = function(num1) {
return num1 * num2;
}
This does not return a function; it returns a value.
addBy(8) returns 8 * num2, but num2 is not defined in this scope, which would cause a ReferenceError.
Also, addByEight would be a number (if num2 existed), not a function, so addByEight(50) would fail.
Option C:
const addBy = (num1) => num1 + num2;
Again, addBy returns a value, not a function.
addBy(8) returns 8 + num2, but num2 is not defined, so this is also invalid due to ReferenceError.
addByEight would be a number (or error), not a function.
Neither B nor C creates the required closure nor returns a function to be called later.
Reference / Study Guide concepts (no links):
Higher-order functions in JavaScript
Closures: inner functions capturing outer variables (num1)
Arrow functions vs function expressions
Returning functions from functions (function factories / currying)
Scope and ReferenceError when a variable is not defined
________________________________________
NEW QUESTION # 55
Given the code below:
let numValue = 1982;
Which three code segments result in a correct conversion from number to string?
Answer: B,D,E
Explanation:
Comprehensive and Detailed Explanation From JavaScript Knowledge:
We want to convert the number 1982 to a string.
Check each option:
A . numValue.toText()
There is no standard toText() method on numbers.
This will result in TypeError: numValue.toText is not a function.
B . String(numValue);
String() as a function converts its argument to a string.
String(1982) returns "1982".
This is correct.
C . '' + numValue;
'' is a string; + with a string operand performs string concatenation.
'' + 1982 → "1982".
This is a common shorthand for number-to-string conversion.
D . numValue.toString();
Number.prototype.toString() converts the number to its string representation.
1982..toString() or (1982).toString() returns "1982".
For the variable, numValue.toString() is valid: "1982".
E . (String)numValue;
This is not valid JavaScript casting syntax; it is more like a C/Java-style cast.
In JavaScript, that is parsed as a grouping expression (String) and then numValue; it does not convert numValue to a string.
Thus the correct answers are:
B . String(numValue);
C . '' + numValue;
D . numValue.toString();
Relevant concepts: primitive type conversion, String() casting, .toString(), coercion via + with strings.
________________________________________
NEW QUESTION # 56
Refer to the code below:
01 let sayHello = () => {
02 console.log('Hello, World!');
03 };
Which code executes sayHello once, two minutes from now?
Answer: A
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge To schedule a function for later execution in JavaScript, the standard built-in method is:
setTimeout(functionReference, delayInMilliseconds)
Characteristics of setTimeout():
Executes only once.
Delay is specified in milliseconds.
Requires passing the function reference, not calling the function.
Two minutes is:
2 minutes = 120 seconds = 120,000 milliseconds
Now evaluate each option:
________________________________________
Option A: delay(sayHello, 120000);
Incorrect.
There is no built-in delay() function in JavaScript.
________________________________________
Option B: setTimeout(sayHello, 120000);
Correct.
sayHello is passed as a function reference, so it will execute once after 120,000 ms.
________________________________________
Option C: setTimeout(sayHello(), 120000);
Incorrect.
sayHello() calls the function immediately, and the return value (undefined) is passed to setTimeout.
This executes the function right away instead of after two minutes.
________________________________________
Option D: setInterval(sayHello, 120000);
Incorrect.
setInterval() repeats execution every 120,000 ms.
The question requires executing the function once, so this cannot be correct.
________________________________________
JavaScript Knowledge Reference (text-only)
setTimeout() schedules a function to run once after a specified delay.
Passing functionName gives a reference; passing functionName() invokes it immediately.
setInterval() repeats indefinitely, unlike setTimeout().
NEW QUESTION # 57
Given the following code:
What will be the first four numbers logged?
Answer: A
NEW QUESTION # 58
A developer has an ErrorHandler module that contains multiple functions.
What kind of export be leverages so that multiple functions can beused?
Answer: A
NEW QUESTION # 59
......
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