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| Section | Objectives |
|---|---|
| JavaScript Fundamentals | - Variables, Data Types, and Operators - Functions and Scope - Control Flow and Error Handling |
| Object-Oriented JavaScript | - Objects and Prototypes - Classes and Inheritance |
| Browser and DOM Interaction | - Events and Event Handling - DOM Manipulation |
| Asynchronous Programming | - API Calls and Data Fetching - Callbacks, Promises, and Async/Await |
| Salesforce Platform Integration | - Working with Salesforce Data Models - Lightning Web Components (LWC) Basics |
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NEW QUESTION # 136
Refer to thefollowing code that imports a module named utils:
import (foo, bar) from '/path/Utils.js';
foo() ;
bar() ;
Which two implementations of Utils.js export foo and bar such that the code above runs without error?
Choose 2 answers
Answer: A,D
NEW QUESTION # 137
Given a value, which two options can a developer use to detect if the value is NaN?
Answer: B,C
Explanation:
We already know NaN is special: it is not equal to itself.
Check each:
A . value === Number.NaN
Number.NaN is NaN.
NaN === NaN is always false.
This will never be true; cannot reliably detect NaN.
B . value == NaN
NaN == NaN is also always false.
Again, this never detects NaN.
C . isNaN(value)
Global isNaN converts its argument to a number and then checks if the result is NaN.
This can detect NaN, but it may also return true for non-number values that coerce to NaN, such as isNaN('foo').
Regardless, it is a standard way to detect if a value is "NaN-like" in JavaScript.
D . Object.is(value, NaN)
Object.is(NaN, NaN) returns true.
This is a strict way to detect a value that is exactly NaN (no coercion).
Therefore, among the given choices, the two viable ways to detect NaN are:
isNaN(value)
Object.is(value, NaN)
NEW QUESTION # 138
Refer to the code:
01 console.log('Start');
02 Promise.resolve('Success').then(function(value) {
03 console.log('Success');
04 });
05 console.log('End');
What is the output after the code executes successfully?
Answer: B
Explanation:
console.log('Start') runs immediately (synchronous).
Promise.resolve().then(...) places the callback in the microtask queue. The .then handler does not run immediately.
console.log('End') runs next (still synchronous).
After the synchronous script finishes, the microtask queue runs, logging "Success".
Execution order:
Start
End
Success
This matches option B.
JavaScript Knowledge Reference (text-only)
Promise .then() callbacks execute after the current call stack finishes (microtask queue).
Synchronous logs run immediately, before promise callbacks.
NEW QUESTION # 139
Given two expressions, exp1 and exp2, which two valid ways return the logical AND of the two expressions and ensure it is a Boolean?
Answer: C,D
Explanation:
The correct answers are A and B.
The original question contains a typing error where 66 should be corrected to the logical AND operator:
&&
A is correct because it first evaluates the logical AND expression and then converts the final result to a Boolean:
Boolean(exp1 && exp2)
The && operator returns the first falsy value or the last truthy value. Wrapping the result in Boolean() ensures the final result is strictly either:
true
or:
false
Example:
Boolean("hello" && 123);
This returns:
true
B is also correct because it converts both expressions to Boolean values first, then applies logical AND:
Boolean(exp1) && Boolean(exp2)
This guarantees that both sides of the && operation are Boolean values.
Example:
Boolean("hello") && Boolean(123);
This returns:
true
C is incorrect because it uses the bitwise AND operator:
&
This is not the same as logical AND:
&&
Bitwise AND converts values into numbers and compares their binary representation. It does not reliably return a Boolean logical result.
D is incorrect as written because the question gives the expressions as exp1 and exp2, but option D uses var1 and var2. After correction, it would be the same idea as option B.
Therefore, the verified answers are A and B.
NEW QUESTION # 140
Refer to the code below:
01 let o = {
02 get js() {
03 let city1 = String('St. Louis');
04 let city2 = String('New York');
05
06 return {
07 firstCity: city1.toLowerCase(),
08 secondCity: city2.toLowerCase(),
09 }
10 }
11 }
What value can a developer expect when referencing o.js.secondCity?
Answer: B
Explanation:
1. Getter Functions in JavaScript
In JavaScript, when an object uses the get keyword, it defines a getter method. Accessing a getter property executes the function and returns its value. Thus:
o.js
does not return the getter function; instead, it executes the function located at:
get js() { ... }
and returns the object inside the return block.
2. Behavior of String() and toLowerCase()
Inside the getter:
let city1 = String('St. Louis');
let city2 = String('New York');
String() creates a string value.
Then, the returned object is constructed as:
{
firstCity: city1.toLowerCase(),
secondCity: city2.toLowerCase(),
}
The method toLowerCase() is a standard JavaScript string method that returns a new string with all alphabetic characters converted to lowercase.
Therefore:
city2.toLowerCase()
returns:
'new york'
3. Referencing the Property
When the developer writes:
o.js.secondCity
the following happens:
The getter js runs and returns an object.
The returned object includes the property:
secondCity: 'new york'
Accessing .secondCity retrieves the lowercase string 'new york'.
Therefore, the correct value is 'new york'.
Why the Other Options Are Incorrect
A . undefined - incorrect because the property secondCity clearly exists in the returned object.
B . An error - incorrect because no invalid operations occur; all methods and properties are valid.
C . 'New York' - incorrect because toLowerCase() transforms the string to lowercase.
JavaScript Knowledge Reference (Text-Based)
Getter methods using the get keyword return computed values when accessed.
JavaScript String values support the toLowerCase() method, which returns a lowercase version of the original string.
Accessing nested properties like o.js.secondCity triggers the getter, returning the constructed object.
NEW QUESTION # 141
......
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