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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: SwiftUI Basics | 25% | - Layout and navigation
|
| Topic 2: Data Handling and Logic | 15% | - Error handling
|
| Topic 3: Development Environment | 15% | - Xcode interface and tools
|
| Topic 4: Swift Programming Fundamentals | 30% | - Structures and classes
|
| Topic 5: App Design and Best Practices | 15% | - Code organization
|
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NEW QUESTION # 13
Refer to this image to complete the code.
Note: You will receive partial credit for each correct answer
Answer:
Explanation:
Explanation:
This question belongs to View Building with SwiftUI , especially the objectives for using List views to iterate through collections and structuring views with standard SwiftUI containers. The screenshot shows two grouped sets of rows: one headed MY FRIENDS and one headed MY PETS . In SwiftUI, the correct container for a scrollable table-style presentation of rows is List, and the correct way to divide that list into labeled groups is Section. Apple documents List as a container that presents data in a single-column row- based layout, and Section as a way to organize list content into grouped areas with headers and optional footers. That is exactly the structure shown in the image. ( developer.apple.com , developer.apple.com ) The ForEach(names, id: \.self) and ForEach(pets, id: \.self) lines are already iterating through the arrays, so each ForEach should be wrapped inside a Section. The section labels such as " My Friends " and " My Pets
" are provided with the header: label. So the intended code structure is:
List {
Section {
ForEach(names, id: \.self) { name in Text(name) }
} header: {
Text( " My Friends " )
}
Section {
ForEach(pets, id: \.self) { pet in Text(pet) }
} header: {
Text( " My Pets " )
}
}
This matches the UI shown in the image and aligns directly with SwiftUI list and section composition patterns in App Development with Swift.
NEW QUESTION # 14
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
Answer: A,D
Explanation:
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
NEW QUESTION # 15
Select the location to set this app to run on an iPhone 14 in the simulator.
Answer:
Explanation:
Explanation:
This question belongs to Xcode Developer Tools , specifically the domain for building and running an app on the iOS simulator . In Xcode, the place where you choose whether the app runs on a simulator or a connected device is the run destination / scheme destination selector in the toolbar. This control appears near the top center of the Xcode window and displays the current destination, such as a simulator model or device target. To run the app on iPhone 14 , you click that selector and choose iPhone 14 from the available simulator list. Apple's Xcode documentation describes choosing a run destination before building and running the app in Simulator or on a device.
So, for the hotspot, the correct place is the device/simulator dropdown in the top toolbar , not the preview canvas controls, not the project navigator, and not the code editor. That selector determines where the app launches when you press Run.
NEW QUESTION # 16
Review the code.
Note: You might need to scroll to see the entire block of code.
A breakpoint is set on line 3. When the application is run. it will stop at line 3. You need to debug the code.
Drag each debugging control from the left to the correct instruction on the right. You will receive partial credit for each correct answer
Answer:
Explanation:
Explanation:
This question belongs to Xcode Developer Tools , especially the objective on using debugging techniques including breakpoints and stepping controls .
When execution stops at a breakpoint on line 3, Step Over runs that line without entering into another function call, so it is the correct action for moving past line 3 while staying in the current function. Step Into is used when execution reaches line 4 and you want to enter the display(numbers) function, which takes you into the function body starting at line 8. Once inside that function, Step Out continues execution until the current function returns, which is exactly what "step out from line 8" means.
Deactivate breakpoints turns breakpoint handling off so the debugger no longer stops on active breakpoints.
Continue program execution resumes the app until the next breakpoint or until the program finishes.
So the correct control order is:
1 = Continue
2 = Deactivate breakpoints
3 = Step Over
4 = Step Into
5 = Step Out
NEW QUESTION # 17
Review the code snippet.
What value does the code output?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int =
20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple's Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.
The conditional logic is then evaluated in order:
* if age > 64 # false, because 20 is not greater than 64
* else if age > 19 # true, because 20 is greater than 19
* so the function returns 2
Because Swift's if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.
Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .
NEW QUESTION # 18
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