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| Section | Objectives |
|---|
| Topic 1: Subqueries and Advanced SQL | - Single-row and multi-row subqueries - Correlated subqueries and nested queries
|
| Topic 2: SQL Retrieval | - SELECT statements and filtering data
- 1. ORDER BY and row limiting
- 2. WHERE clause and conditions
- Joins and set operations
- 1. INNER, OUTER, CROSS joins
- 2. UNION, INTERSECT, MINUS
|
| Topic 3: Relational Database Concepts | - Tables, rows, columns, and relational model basics - Data types and database objects overview
|
| Topic 4: SQL Functions | - Conversion and conditional functions
- 1. TO_CHAR, TO_NUMBER, CASE expressions
- Single-row functions
- 1. Character, numeric, date functions
|
| Topic 5: Data Manipulation and Schema Objects | - DML operations
- 1. INSERT, UPDATE, DELETE, MERGE
- DDL operations
- 1. CREATE, ALTER, DROP tables and constraints
|
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Oracle Database SQL Sample Questions (Q304-Q309):
NEW QUESTION # 304
Examine the data in the CUST_NAME column of the CUSTOMERS table.
CUST_NAME
-------------------
Renske Ladwig
Jason Mallin
Samuel McCain
Allan MCEwen
Irene Mikilineni
Julia Nayer
You need to display customers' second names where the second name starts with "Mc" or "MC".
Which query gives the required output?
- A. SELECT SUBSTR (cust_name, INSTR (cust_name, ' ')+1)FROM customersWHERE SUBSTR (cust_name, INSTR (cust_name, ' ')+1)LIKE INITCAP ('MC%');
- B. SELECT SUBSTR (cust_name, INSTR (cust_name, ' ')+1)FROM customersWHERE INITCAP (SUBSTR(cust_name, INSTR (cust_name, ' ')+1)) =INITCAP 'MC%';
- C. SELECT SUBSTR (cust_name, INSTR (cust_name, ' ')+1)FROM customersWHERE INITCAP (SUBSTR(cust_name, INSTR (cust_name, ' ')+1)) ='Mc';
- D. SELECT SUBSTR (cust_name, INSTR (cust_name, ' ')+1)FROM customersWHERE INITCAP (SUBSTR(cust_name, INSTR (cust_name, ' ')+1))LIKE 'Mc%';
Answer: D
NEW QUESTION # 305
Which three queries execute successfully?
- A. SELECT 1 / SYSDATE - DATE '2019-01-01' FROM DUAL;
- B. SELECT 1 - SYSDATE- DATE '2019-01-01' FROM DUAL;
- C. SELECT (SYSDATE-DATE '2019-01-01') / 1 FROM DUAL;
- D. SELECT SYSDATE - 1 - DATE'2019-01-01' EROM DUAL;
- E. SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL;
- F. SELECT SYSDATE / DATE '2019-01-01' - 1 FROM DUAL
Answer: C,D,E
Explanation:
In Oracle SQL, date arithmetic can be performed directly, subtracting one date from another to get the number of days between them:
* Option A:
* SELECT (SYSDATE - DATE '2019-01-01') / 1 FROM DUAL; This query successfully calculates the difference between the current date and a specific date.
* Option D:
* SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL; This query subtracts a specific date from the current date and then subtracts 1 more day, which will execute successfully.
* Option F:
* SELECT SYSDATE - 1 - DATE '2019-01-01' FROM DUAL; Similar to D, this will successfully compute the date difference minus one day.
Options B, C, and E are incorrect because:
* Option B and Option C: You cannot divide by a date or divide a date by a number.
* Option E: You cannot subtract a date from a number.
NEW QUESTION # 306
Examine this description of the PRODUCTS table:

Rows exist in this table with data in all the columns. You put the PRODUCTS table in read-only mode.
Which three commands execute successfully on PRODUCTS?
- A. DROP TABLE products;
- B. ALTER TABLE products SET UNUSED (expiry_date);
- C. TRUNCATE TABLE products;
- D. ALTER TABLE products DROP UNUSED COLUMNS;
- E. ALTER TABLE products DROP COLUMN expiry_date;
- F. CREATE INDEX price_idx ON products (price);
Answer: A,C,F
NEW QUESTION # 307
Examine the commands used to create the DEPARTMENT_DETAILS and the COURSE-DETAILS tables:
SQL> CREATE TABLE DEPARTMfiNT_DETAILS
DEPARTMENT_ID NUMBER PRIMARY KEY ,
DEPARTMEHT_NAME VARCHAR2(50) ,
HOD VARCHAP2(50));
SQL> CREATE TABLE COURSE-DETAILS
(COURSE ID NUMBER PRIMARY KEY ,
COURS_NAME VARCHAR2 (50) ,
DEPARTMEHT_ID NUMBER REFERENCES DEPARTMENT_DETAIL
You want to generate a list of all department IDs along with any course IDs that may have been assigned to them.
Which SQL statement must you use?
- A. SELECT d.departranc_id, c.cours<<_id FROM cource_deatils c LEFT OUTER JOIN departmnt_details d ON (c.dapartmsnt_id=d.departtnent_id);
- B. SELECT d.department id. ccours_id FROM department_details d RIGHT OUTER JOIN course_details c ON (d.department_id);
- C. SELECT d.department_id, c.course_id FROM department_details d LEFT OUTER JOIN course_details c ON (d.department___id).- (DEPARTMENT_ID) ;
- D. SELECT d.department_id, c. course_id FROM dapartment_details d RIGHT OUTER JOIN course_dotails c ON (c.depattnient_id=d.department_id) ;
Answer: C
NEW QUESTION # 308
Which three are true about the MERGE statement?
- A. It can update, insert, or delete rows conditionally in multiple tables.
- B. It can combine rows from multiple tables conditionally to insert into a single table.
- C. It can update the same row of the target table multiple times.
- D. It can merge rows only from tables.
- E. It can use views to produce source rows.
- F. It can use subqueries to produce source rows.
Answer: B,E,F
Explanation:
B: True. The Oracle Database MERGE statement can use a subquery that involves views to generate the source data for the merge operation. This allows for greater flexibility in specifying the data to be merged.
C: True. MERGE can conditionally combine rows from one or more source tables (or views, or the results of a subquery) to insert or update rows in a single target table based on whether or not a match exists.
D: True. MERGE can indeed use subqueries to produce source rows. The source data for a merge operation can be a table, view, or the result of a subquery.
The MERGE statement is a powerful SQL operation in Oracle that allows for conditional INSERT or UPDATE operations in one statement, often referred to as an "upsert" operation. It can handle complex scenarios where the decision to insert or update is based on whether the data matches between the target and source datasets.
Reference:
Oracle SQL documentation on the MERGE statement provides information on how it can use different data sources, including subqueries and views, and perform conditional operations on the target table.
NEW QUESTION # 309
......
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