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>> Latest JS-Dev-101 Test Objectives <<
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NEW QUESTION # 63
Refer to the code below (assuming Promise.race is intended):
let cat3 = new Promise(resolve =>
setTimeout(resolve, 3000, "Cat 3 completes")
);
Promise.race([cat1, cat2, cat3])
.then(value => {
let result = `${value} the race.`;
})
.catch(err => {
console.log("Race is cancelled:", err);
});
(Assuming cat1 and cat2 are similar to earlier examples: cat2 resolves fastest.) What is the value of result when Promise.race executes?
Answer: B
Explanation:
From earlier pattern (cars/cats race):
One promise resolves the fastest with "Car 2 completed" (or analogous "Cat 2 completes").
Promise.race resolves with the first settled promise's value.
In .then, value is "Car 2 completed" and:
let result = `${value} the race.`;
// "Car 2 completed the race."
Thus result is "Car 2 completed the race." → option A.
NEW QUESTION # 64
Given the following code:
01 counter = 0;
02 const logCounter = () => {
03 console.log(counter);
04 };
05 logCounter();
06 setTimeout(logCounter, 2100);
07 setInterval(() => {
08 counter++;
09 logCounter();
10 }, 1000);
What will be the first four numbers logged?
Answer: D
Explanation:
We need to track the value of counter and the timing of each call to logCounter.
Initial state:
Line 01: counter = 0;
Line 02-04: logCounter logs the current value of counter.
Execution order and timing:
Line 05: logCounter();
Called immediately at time t = 0 ms.
counter is 0.
First log: 0.
Line 06: setTimeout(logCounter, 2100);
Schedules logCounter to run once after 2100 ms.
No log yet at this line.
Line 07-10: setInterval(() => { counter++; logCounter(); }, 1000);
Schedules a repeating callback every 1000 ms (1 second).
First interval callback runs at t ≈ 1000 ms.
Now follow the timeline:
t = 0 ms:
logCounter(); from line 05
Logs: 0
t = 1000 ms (first interval execution):
counter++; → counter goes from 0 to 1.
logCounter(); logs 1.
t = 2000 ms (second interval execution):
counter++; → counter goes from 1 to 2.
logCounter(); logs 2.
t = 2100 ms (timeout from line 06):
logCounter(); runs again.
counter is still 2 (next setInterval will be at t = 3000 ms).
Logs 2.
So the first four logs are:
0
1
2
2
Concatenated as in the options: 0122.
Therefore, the correct choice is:
Answe r: A
Study Guide / Concept Reference (no links):
setTimeout and setInterval timing behavior
Order of execution in the event loop
Closures capturing variables (here, logCounter using counter)
Understanding asynchronous scheduling in JavaScript
NEW QUESTION # 65
Refer to the code below:
01 <html lang="en">
02 <table onclick="console.log('Table log');">
03 <tr id="row1">
04 <td>Click me!</td>
05 </tr>
06 </table>
07 <script>
08 function printMessage(event) {
09 console.log('Row log');
10 event.stopPropagation();
11 }
12
13 let elem = document.getElementById('row1');
14 elem.addEventListener('click', printMessage, false);
15 </script>
16 </html>
Which code change should be done for the console to log the following when "Click me!" is clicked?
Row log
Table log
Answer: D
Explanation:
Current behavior:
Clicking <td> triggers the click event on row1, then bubbles up to <table>.
printMessage runs, logs "Row log", then event.stopPropagation() stops the event from bubbling to the table.
So "Table log" never appears.
To allow the table's inline onclick to run after the row handler:
Remove the propagation stop:
function printMessage(event) {
console.log('Row log');
// event.stopPropagation(); // remove this
}
Now the event bubbles:
printMessage logs "Row log".
The table's onclick runs, logging "Table log".
Option A only changes capture/bubble phase but still stops propagation. C does nothing meaningful (stopPropagation takes no arguments). B removes the row handler entirely.
NEW QUESTION # 66
Refer to the code below:
01 let timedFunction = () => {
02 console.log('Timer called.');
03 };
04
05 let timerId = setInterval(timedFunction, 1000);
Which statement allows a developer to cancel the scheduled timed function?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From JavaScript Knowledge:
The code:
let timerId = setInterval(timedFunction, 1000);
setInterval schedules timedFunction to run every 1000 ms.
It returns an interval ID (here stored in timerId), which is used to cancel the interval later.
To cancel:
Use clearInterval(timerId);
This is the standard browser (and Node.js) API:
let id = setInterval(fn, delay);
clearInterval(id); stops future executions of that interval.
Check other options:
B . removeInterval(timerId);
There is no removeInterval function in the standard JavaScript timer API.
C . removeInterval(timedFunction);
Again, no such function; and timers are cancelled by ID, not by the callback function reference.
D . clearInterval(timedFunction);
clearInterval expects the ID returned by setInterval, not the callback function.
Passing the function does not cancel the timer.
Therefore, the correct statement is:
Answe r: A
Study Guide / Concept Reference (no links):
Timer APIs: setInterval and clearInterval
Relationship between timer ID and cancellation
Difference between interval ID and callback function
Basic async timing patterns in JavaScript
NEW QUESTION # 67
A developer has a fizzbuzz function that, when passed in a number, returns the following:
'fizz' if the number is divisible by 3.
'buzz' if the number is divisible by 5.
'fizzbuzz' if the number is divisible by both 3 and 5.
Empty string '' if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?
Answer: A,D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
First, recall the fizzbuzz rules:
If n divisible by 3 and not by 5 → return 'fizz'.
If n divisible by 5 and not by 3 → return 'buzz'.
If n divisible by both 3 and 5 → return 'fizzbuzz'.
Otherwise → return '' (empty string).
Evaluate each test:
Option A:
let res = fizzbuzz(true);
console.assert(res === '');
In JavaScript, when using arithmetic operations with true, it is coerced to the number 1. A typical implementation of fizzbuzz would treat the argument as a number and compute:
true % 3 → 1 % 3 → 1
true % 5 → 1 % 5 → 1
So true is effectively treated as 1, which is divisible by neither 3 nor 5. The function should return ''. The assertion res === '' will pass.
This test covers the scenario "neither divisible by 3 nor 5".
Option B:
let res = fizzbuzz(3);
console.assert(res === '');
3 is divisible by 3 but not by 5.
According to fizzbuzz rules, fizzbuzz(3) should return 'fizz'.
This test expects '', so it is incorrect; the assertion would fail in a correct implementation.
Option C:
let res = fizzbuzz(5);
console.assert(res === 'fizz');
5 is divisible by 5 but not by 3.
According to fizzbuzz rules, fizzbuzz(5) should return 'buzz'.
This test expects 'fizz', so it is incorrect.
Option D:
let res = fizzbuzz(15);
console.assert(res === 'fizzbuzz');
15 is divisible by both 3 and 5.
According to fizzbuzz rules, fizzbuzz(15) should return 'fizzbuzz'.
This assertion correctly matches the expected result, so it is a proper test case.
Thus, the two test cases that correctly test valid fizzbuzz behavior are:
Study Guide / Concept Reference (no links):
Modulo operator (%) for divisibility checks
Truthy/number coercion of boolean true in arithmetic (Number(true) === 1) Designing unit tests with console.assert Typical fizzbuzz logic structure and expected outputs
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NEW QUESTION # 68
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