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| Section | Weight | Objectives |
|---|---|---|
| Structural Design Fundamentals | 20% | - Design of structural elements
|
| Surveying | 20% | - Measurement and calculation techniques
|
| Municipal Engineering | 20% | - Water supply and distribution
|
| Materials Testing | 20% | - Soil mechanics and testing
|
| Transportation Engineering | 20% | - Highway and road design
|
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NEW QUESTION # 80
Which of the following statements best describes thefor piling loads in the diagram below?
Answer: C
Explanation:
For an axially loaded pile in compression, the resisting capacity comes from two primary components:end bearing at the tipandskin friction along the shaft. These components act together, and total pile resistance is typically expressed as thesumof tip resistance and shaft resistance. In standard geotechnical capacity formulation, the ultimate pile capacity is written as, whereis the shaft (friction) capacity andis the point (tip) capacity. Lindeburg's deep foundation section similarly explains that point-bearing and skin-friction capacities are simultaneously present to some degree in piles, and total support is based on their combined contribution. In the diagram,represents the tip component (unit tip resistance times tip area) andrepresents shaft resistance. Thereforecannot exceed the combined available resistance and is properly described asless than or equal to.
NEW QUESTION # 81
Which joints in concrete slab construction determine the location of cracks?
Answer: D
Explanation:
Concrete slabs shrink as they cure and experience temperature/moisture changes. Because the slab is restrained by subbase friction and adjacent elements, tensile stresses develop and cracking is likely unless the slab is intentionally "weakened" at planned locations.Control joints(also called contraction joints) are formed or saw-cut to create a deliberate plane of weakness so that shrinkage cracking occurswhere intended, producing straighter, serviceable cracks that are easier to seal and maintain. Technical references describe contraction/control joints as placed at regular intervals specifically tocontrol random crackingby encouraging the crack to form along the joint line, relieving tensile stresses in the slab. Expansion joints address thermal expansion, isolation joints separate the slab from fixed elements, and construction joints occur where placements stop and start; none of those are primarily intended tocontrol crack locationthe way control joints are. Therefore, the joint type that determines where cracks occur is thecontrol joint.
NEW QUESTION # 82
What test should be used to determine the compressive strength of concrete?
Answer: B
Explanation:
Concrete compressive strength is determined by loading astandard molded specimento failure in a compression testing machine and calculating strength from the peak load divided by the specimen's cross- sectional area. The common acceptance specimen for cast-in-place concrete is acylinder, produced and cured using standardized procedures to ensure that test results reliably represent the delivered concrete. Civil engineering materials references describe compressive strength testing as the principal measure used to verify compliance with specified strength (f'c), and that cylinder specimens are tested in compression to determine the maximum stress sustained.
A slump test measures workability/consistency, an air test measures entrained air content, and sieve testing measures aggregate gradation-none of these directly measure compressive strength. Therefore, the required test for compressive strength is thecylinder test (Option B).
NEW QUESTION # 83
The k-value in a vertical curve design defines the horizontal distance required to make a 1% change in the gradient. Provided that the stopping sight distance is the same, the uphill grade is 1%, the downhill grade is #0.
5%, and the design speed is 90 km/h, what is the length of the vertical curve?
Answer: C
Explanation:
For vertical curves, AASHTO uses theK valuedefined as, whereis curve length (m) andis the algebraic difference in grades (percent). Here,and, so. Withstopping sight distance controlled by the same criterion(i.
e., the applicable K value for the given design speed remains the same), length is found from. For 90 km/h, the SSD-based K for the controlling curve type yieldsthat corresponds to60 mforper the provided choices.
This reflects standard vertical-curve practice: once K is set by SSD for the design speed, length scales linearly with the grade difference.
NEW QUESTION # 84
For granular material, what is the typical optimum moisture content for dry densities ranging from 2100 kg/m³ to 2200 kg/m³?
Answer: A
Explanation:
Theoptimum moisture content (OMC)is the moisture content at which a soil achievesmaximum dry density for a given compactive effort on the Proctor curve. Granular materials (sands/gravels with low plastic fines) typically requirerelatively low moistureto reach peak density because their structure densifies primarily by particle rearrangement; only a small amount of water is needed to lubricate contacts and aid compaction.
Training/compaction manuals define OMC as the peak of the moisture-density relationship and highlight that coarse-grained materials generally peak at lower moisture than fine-grained soils. A maximum dry density range of about2100-2200 kg/m³(#2.10-2.20 Mg/m³) is consistent with well-compacted granular base
/subbase, which commonly has an OMC in thesingle-digit percentrange. Therefore, the typical OMC range that best matches granular materials at these densities is4-7%.
NEW QUESTION # 85
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