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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Asynchronous Programming | 13% | - Callbacks, promises, async/await - Event loop and execution flow |
| Topic 2: Debugging and Error Handling | 7% | - Error types and handling strategies - Console usage, breakpoints and debugging techniques |
| Topic 3: Server Side JavaScript | 8% | - Node.js fundamentals and core modules - Package management and CLI tools |
| Topic 4: Browser and Events | 17% | - Event handling, propagation, listeners - Browser APIs and developer tools - DOM selection and manipulation |
| Topic 5: Variables, Types, and Collections | 23% | - Data types, type coercion, truthy/falsy values - Strings, numbers, dates, arrays and methods - Variable declaration and scope - JSON parsing and manipulation |
| Topic 6: Objects, Functions, and Classes | 25% | - Object creation, properties, prototypes - ES6 classes, inheritance, modules, decorators - Function types, scope, closures, arrow functions |
| Topic 7: Testing | 7% | - Test coverage and improvement - Unit test structure and effectiveness |
>> Exam Salesforce JS-Dev-101 Topic <<
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NEW QUESTION # 88
A developer has a fizzbuzz function that, when passed in a number, returns the following:
'fizz' if the number is divisible by 3.
'buzz' if the number is divisible by 5.
'fizzbuzz' if the number is divisible by both 3 and 5.
Empty string if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?
Answer: A,D
Explanation:
The correct answers are B and D.
A strong test case checks whether the actual output matches the expected behavior of the function.
For Option B:
let res = fizzbuzz(15);
console.assert(res === 'fizzbuzz');
The number 15 is divisible by both 3 and 5:
15 % 3 === 0
15 % 5 === 0
So the correct return value is:
'fizzbuzz'
That makes option B a valid test.
For Option D:
let res = fizzbuzz(Infinity);
console.assert(res === '');
Infinity is not a normal finite divisible number. In JavaScript:
Infinity % 3
Infinity % 5
produce NaN, and comparisons such as:
Infinity % 3 === 0
are false.
So a typical fizzbuzz implementation would not treat Infinity as divisible by 3 or 5, meaning it should return:
''
That makes option D a valid test for the "neither divisible by 3 nor 5" path.
Now compare the incorrect options:
Option A is wrong because:
fizzbuzz(3)
should return:
'fizz'
not:
'buzz'
Option C is wrong because the function specification says the function returns strings such as 'fizz', 'buzz', 'fizzbuzz', or ''. It does not say the function returns numeric NaN.
So this assertion is not appropriate:
console.assert(isNaN(res));
Therefore, the verified answers are B and D.
NEW QUESTION # 89
A developer is working on an ecommerce website where the delivery date is dynamically calculated based on the current day. The code line below is responsible for this calculation.
Const deliveryDate = new Date ();
Due to changes in the business requirements, the delivery date must now be today's date + 9 days.
Which code meets thisnew requirement?
Answer: A
NEW QUESTION # 90
Given two expressions var1 and var2. What are two valid ways to return the logical AND of the two expressions and ensure it is data type Boolean ?
Choose 2 answers:
Answer: C,D
NEW QUESTION # 91
Refer to the code below:
What is the value of result when the code executes?
Answer: A
NEW QUESTION # 92
Given the code:
01 function GameConsole(name) {
02 this.name = name;
03 }
04
05 GameConsole.prototype.load = function(gamename) {
06 console.log('${this.name} is loading a game: ${gamename}....');
07 }
08
09 function Console16bit(name) {
10 GameConsole.call(this, name);
11 }
12
13 Console16bit.prototype = Object.create(GameConsole.prototype);
14
15 // insert code here
16 console.log('${this.name} is loading a cartridge game: ${gamename}....');
17 }
18
19 const console16bit = new Console16bit('SNEGeneziz');
20 console16bit.load('Super Monic 3x Force');
What should a developer insert at line 15?
Answer: A
Explanation:
A subclass created by:
Console16bit.prototype = Object.create(GameConsole.prototype);
inherits all prototype methods from GameConsole, including load.
To override the inherited method, the correct syntax is to assign a new function to the method name on the prototype:
Console16bit.prototype.load = function(gamename) {
console.log(`${this.name} is loading a cartridge game: ${gamename}....`);
};
Why the other options are wrong:
A assigns something to the constructor function itself, not to the prototype method. Invalid.
B attempts to call a function in the left-hand side of an assignment; invalid syntax.
C also uses invalid syntax-prototype methods cannot be defined this way.
D is the correct definition of a prototype method override.
JavaScript Knowledge Reference (text-only)
Methods are overridden by assigning functions to Subclass.prototype.methodName.
Object.create() establishes prototype inheritance.
Constructor functions require prototype method attachment using assignment syntax.
NEW QUESTION # 93
......
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