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| Section | Objectives |
|---|
| SQL Retrieval | - Joins and set operations
- 1. UNION, INTERSECT, MINUS
- 2. INNER, OUTER, CROSS joins
- SELECT statements and filtering data
- 1. ORDER BY and row limiting
- 2. WHERE clause and conditions
|
| Relational Database Concepts | - Data types and database objects overview - Tables, rows, columns, and relational model basics
|
| Data Manipulation and Schema Objects | - DDL operations
- 1. CREATE, ALTER, DROP tables and constraints
- DML operations
- 1. INSERT, UPDATE, DELETE, MERGE
|
| Subqueries and Advanced SQL | - Correlated subqueries and nested queries - Single-row and multi-row subqueries
|
| SQL Functions | - Conversion and conditional functions
- 1. TO_CHAR, TO_NUMBER, CASE expressions
- Single-row functions
- 1. Character, numeric, date functions
|
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Oracle Database SQL Sample Questions (Q417-Q422):
NEW QUESTION # 417
View the Exhibit and examine the structure of the EMPLOYEES and JOB_HISTORY tables. (Choose all that apply.)

Examine this query which must select the employee IDs of all the employees who have held the job SA_MAN at any time during their employment.
SELECT EMPLOYEE_ID
FROM EMPLOYEES
WHERE JOB_ID = 'SA_MAN'
-------------------------------------
SELECT EMPLOYEE_ID
FROM JOB_HISTORY
WHERE JOB_ID = 'SA_MAN';
Choose two correct SET operators which would cause the query to return the desired result.
- A. UNION
- B. UNION ALL
- C. MINUS
- D. INTERSECT
Answer: A,B
NEW QUESTION # 418
Examine the structure proposed for the TRANSACTIONS table:

Which two statements are true regarding the storage of data in the above table structure? (Choose two.)
- A. The CUST_STATUS column would allow storage of data up to the maximum VARCHAR2 size of
4,000 characters. - B. The CUST_CREDIT_VALUE column would allow storage of positive and negative integers.
- C. The TRANS_VALIDITY column would allow storage of a time interval in days, hours, minutes, and seconds.
- D. The TRANS_DATE column would allow storage of dates only in the dd-mon-yyyy format.
Answer: B,C
NEW QUESTION # 419
Examine the description of the EMPLOYEES table:

Which statement will fail?
- A. SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90 GROUP BY department_id
HAVING COUNT(*) >= 3; - B. SELECT department_id, COUNT (*)
FROM employees
WHERE department_ id <> 90 AND COUNT(*) >= 3
GROUP BY department_id; - C. SELECT department_id, COUNT(*)
FROM employees
WHERE department_id <> 90 HAVING COUNT(*) >= 3
GROUP BY department_id; - D. SELECT department_id, COUNT (*)
FROM employees
HAVING department_ id <> 90 AND COUNT(*) >= 3
GROUP BY department_id;
Answer: B
Explanation:
The statement that will fail is B. In Oracle SQL, the WHERE clause cannot contain aggregate functions directly. The HAVING clause is used instead to apply conditions that involve aggregates, but it is applied after the GROUP BY clause.
A . While the HAVING clause is used before the GROUP BY clause which is not standard SQL syntax, Oracle SQL may still execute it successfully due to its flexibility in syntax.
B . This statement will fail because it uses an aggregate function, COUNT(*), in the WHERE clause, which is not allowed. The correct approach is to use the HAVING clause to filter the results of aggregate functions after the GROUP BY clause.
C . This statement is correct; it places the HAVING clause after the GROUP BY clause, applying the filter on the aggregated count.
D . This is a correctly constructed statement with the WHERE clause filtering individual records before grouping, and the HAVING clause filtering groups based on the aggregate function.
Reference:
Oracle Database SQL Language Reference, 12c Release 1 (12.1): "WHERE Clause" Oracle Database SQL Language Reference, 12c Release 1 (12.1): "HAVING Clause"
NEW QUESTION # 420
View the exhibit and examine the structure of the STORES table.
STORES table
NameNull?Type
---------------------- -------------
STORE_IDNUMBER
NAMEVARCHAR2(100)
ADDRESSVARCHAR2(200)
CITYVARCHAR2(100)
COUNTRYVARCHAR2(100)
START_DATEDATE
END_DATEDATE
PROPERTY_PRICENUMBER
You want to display the NAME of the store along with the ADDRESS, START_DATE, PROPERTY_PRICE, and the projected property price, which is 115% of property price.
The stores displayed must have START_DATE in the range of 36 months starting from 01-Jan-2000 and above.
Which SQL statement would get the desired output?
- A. SELECT name, concat (address||','| |city| |', ', country) AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
- B. SELECT name, address||','||city||','||country AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
- C. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE MONTHS_BETWEEN (start_date, '01-JAN-2000')
<=36; - D. SELECT name, concat (address| | ','| |city| |', ', country) AS full_address,start_date,property_price, property_price*115/100FROM storesWHERE TO_NUMBER(start_date-TO_DATE('01-JAN-2000','DD-MON-RRRR')) <=36;
Answer: A
NEW QUESTION # 421
Examine the description products table:

Examine the description of the new_projects table;

Which two queries execute successfully?
Answer: D,E
NEW QUESTION # 422
......
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